you are a living legend and a real chad , CHAD!!! all love and support from an egyptian pharmacy student who finds this super helpful in understanding the O chem course .
@ChadsPrep4 ай бұрын
Thank you - glad the channel is helping you!
@MaxVangogh711 ай бұрын
The chart is super helpful, I wish my professor taught it like this. Thank you for always saving my grades!
@ChadsPrep11 ай бұрын
Glad the channel is helping you.
@hiranthini12 жыл бұрын
Excellent method of teaching, I really liked the way you show the different reactions.
@ChadsPrep2 жыл бұрын
Thank you!
@NoorNoor-pf5id Жыл бұрын
Passed orgo 1 last semester with B- and now taking orgo 2 and my first person to learn things from is you. Much love and respect to you
@ChadsPrep Жыл бұрын
Great to hear this! Keep up the good work and love and respect right back at you :)
@abigailbui57536 ай бұрын
100% my favorite video of yours. The diagram and delivery was genius. thanks again!
@ChadsPrep6 ай бұрын
Glad you liked it!
@strugglingcollegestudent Жыл бұрын
I love this chart because I know there's no way I could memorize all the reactions for ochem this makes the patterns very clear!
@ChadsPrep Жыл бұрын
Glad it helps - Happy Studying!
@gizachewmulualem Жыл бұрын
HI GUIES
@ChadsPrep Жыл бұрын
@@gizachewmulualem Welcome to the channel.
@heatherbland559710 ай бұрын
This is the best video of yours I’ve seen. Makes the pattern so clear!
@ChadsPrep10 ай бұрын
Glad you think so!
@jadeluu60612 ай бұрын
this is crazy wow, chart changed my life
@ChadsPrep2 ай бұрын
Great!
@jaydenallegakoen9974 Жыл бұрын
This is one of the best explanations ever bro. thanks so much!
@ChadsPrep Жыл бұрын
You're welcome and Thank You!
@BruceWayne-i2n9 ай бұрын
Just spent an hour and a half making anki cards on the chart 😆 appreciate the effort and succinctness of this video. just so well explained
@ChadsPrep9 ай бұрын
Glad it helped!
@laura5878 Жыл бұрын
I worship you.
@ChadsPrep Жыл бұрын
As long as the channel is helping you, I'm pleased - Happy Studying!
@nilsnickname445510 ай бұрын
I have got a question regarding to the last reaction in the video. Why not transforming the amide acid-catalyzed under heat and afterwards a direct acid-catalyzed reaction with the isopropanol? That would be one step less. Wouldn't it also work fine?
@mirjam936525 күн бұрын
I was thinking the same thing
@ImAzer2 жыл бұрын
Hey Chad, quick question, in the last example, couldn't we go directly from carboxylic acid to ester with R'OH/H+?
@ChadsPrep2 жыл бұрын
Hey Andreas! We totally could but since every step in the (Fisher Esterification) reaction is in equilibrium we would need to use an excess of the alcohol or carboxylic acid, or remove the water product in order to drive this to completion and obtain a good yield.
@belalsalama49953 жыл бұрын
for the last example, couldn't we go directly from carboxylic acid to ester with R'OH/H+
@equityeyewear19873 жыл бұрын
Yes, I had that question as well
@madisenw.40593 жыл бұрын
I also had that question when we walked through the last example. I would think so? It'd be one less step.
@mallorythompson33652 жыл бұрын
Maybe that would just give the corresponding ester rather than the specific product we need? I was wondering that as well.
@ChadsPrep2 жыл бұрын
Just replied to the same question above: We totally could go this way but since every step in the reaction is in equilibrium we would need to use an excess of the alcohol or carboxylic acid, or remove the water product in order to drive this to completion and obtain a good yield.
@abdoulazizdabo90646 ай бұрын
Thank you 🙏🏾
@ChadsPrep6 ай бұрын
You are so welcome
@dheranshahi4741 Жыл бұрын
Mans doing gods work
@ChadsPrep Жыл бұрын
Thanks!
@jpbolivar99952 жыл бұрын
Hello, Chad! You're a great teacher and I'm grateful that your videos really help me out here in my studies. I have a question tho'. Isn't it that aldehydes and ketones would react the least in this trend since the H and R groups connected to the carbonyl carbon are very weak bases? Thank you! :))
@ChadsPrep2 жыл бұрын
Hey JP! Thanks for your kind words :) Regarding your question - aldehydes and ketones don't react by this mechanism at all because they don't contain suitable leaving groups (weaker bases are better leaving groups as they are more stable on their own - so H- and R- are terrible leaving groups because they are strong bases), and instead they undergo nucleophillic addition reactions. Hope that clarifies!
@dwrans6147 Жыл бұрын
thank you so much!! Your videos are really helpful :))
@ChadsPrep Жыл бұрын
Glad you like them!
@forlornhauntedghost Жыл бұрын
You're amazing!
@ChadsPrep Жыл бұрын
Thank you
@bboir7 ай бұрын
I am not sure if you will see this message. In the last example why didnt you use excess H3O+ to go from carboxylic acid to ester?
@ChadsPrep7 ай бұрын
That's been asked a few times here - We totally could go this way but since every step in the reaction is in equilibrium we would need to use an excess of the alcohol or carboxylic acid, or remove the water product in order to drive this to completion and obtain a good yield :)
@BruceWayne-i2n9 ай бұрын
Quick question - does the acid catalysis help the electrophiles get better leaving groups (by protonating them) while the base catalysis makes the nucleophiles get stronger by making them negative (deprotonating them). Thanks
@ChadsPrep9 ай бұрын
Is this about a reaction in particular? Acid catalysis protonates the carbonyl oxygen (C=O) to form C=OH+ which makes the carbonyl carbon more electrophillic for attack by nucleophile. Basic catalysis does act on the nucleophile to make it stronger (more anionic), yes, as the reaction will not occur if the leaving group is a stronger base than the nucleophile.
@BruceWayne-i2n9 ай бұрын
Yea it was more for the carboxylic acid substitutions but also in general for any of these substitution reactions since they have a lot of the same common themes/patterns.But your response answered that so thanks, makes sense.
@ChadsPrep9 ай бұрын
Great to hear and you are welcome :)
@ItsMe-dj6pl Жыл бұрын
How could you explain all of this in that easily way in 30 minutes? My profisor takes 3 lectures every one for 3 hours and he didn't make me understand all of these
@ChadsPrep Жыл бұрын
Glad you found it so helpful :)
@SM-gc2tx8 ай бұрын
absolute chad
@ChadsPrep8 ай бұрын
Happy Studying!
@Yamikani-e5w11 ай бұрын
Thank you Bald guy😊
@ChadsPrep11 ай бұрын
You're welcome, Person of Unknown Follicle Quantity.
@BruteDuke2 жыл бұрын
Hey Chad, on your second example at the end of the video, is it possible to skip the acid halide step and go directly to the ester from the carboxylic acid? I understand why it had to be converted down carboxylic acid from the amine, but why did we have to go all the way back up to halide instead of directly converting to an ester. Thanks :)
@SM-gc2tx8 ай бұрын
I was wondering the same thing
@CCai-yr5gr2 жыл бұрын
But you just said caboxylic acid can turn into ester with acid catalyze, wht did you have to go back to acid halide???
@felixm25862 жыл бұрын
he replied in the comments above " every step in the (Fisher Esterification) reaction is in equilibrium we would need to use an excess of the alcohol or carboxylic acid, or remove the water product in order to drive this to completion and obtain a good yield"