SN1 Reaction Mechanism

[@TheOrganicChemistryTutor]

Organic Chemistry - Video Lessons: www.video-tutor.net/organic-chemistry.html Access The Full 1 Hour Video on Patreon: bit.ly/3kIbBmP SN1 SN2 E1 E2 - 4 Hour Test Review: bit.ly/3Bt4ghw

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Just had that moment where everything made sense. Thank you

[@priyansubramanian6465]

Hi, at 8:10. From step 2 to step 3, the Energy Profile Diagram has shown decrease (endothermic) but during the 3rd step, when OH2+ changes to OH, it becomes more stable and energy is released. So it must be exothermic and the graph must increase at the third transition state.

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[@nefariouswrld]

14:11 most reactive to sn1 23:05 best substrate for sn1 and sn2 24:40 aryl halides and benzyl halides do NOT work for sn1 25:11 to 26:01 iodide is a better leaving group than bromide as it can stabilize the -ve charge better. larger ions can stabilize a -ve charge better than smaller ions.

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[@plasmada263]

I think at 21:49 there's a mistake, because the ability of a compound to give SN1 reaction is measured by the stability of the carbocation that's going to be formed IMMEDIATELY after the removal of the old nucleophile as that is the rate determining step and the rearrangement shouldn't be considered in this case, hence the third compund will show most reactivity to SN1 as the carbocation that's going to be formed will have 5 alpha hydrogens for hyperconjugation stabilization

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24:21 They dont work so we are just supposed to remember this arbitrary rule? No explanation? WOW great lessons here! just remember this random rule !

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[@flaffy13091]

12:44 wouldn't the carbon on the bottom of the carbon marked red also be a stereocenter?

[@andrewjustin256]

6:56, if I would like to assign "Absolute Configuration" to these two Meso compounds, the how will I do so? There's no hydrogen atom. May I do like so by placing priority on the hydroxide ion, then this leads to R for the dashed bond and S for the wedge bond. Please someone rectify me if I made an erroe on calling them meso compounds and the sterochemistry. Thank you!

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[@shairahcortez]

9:10 why did it just grow a random leg and H ?????

[@nefariouswrld]

the h is always there and it is not a random leg, it represents the bond between c and h. the bonds between c and h are often not shown in a line diagram, only the heteroatoms (i.e, atoms other than c and h, like O, N, etc,) are shown differently and named.

[@sardaraghayev6189]

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[@harshbirbrar2830]

24:40 Could easier way to find the better leaving group be finding the more stable base/more acidic leaving group?

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[@mhq945]

at 4:05 wouldn't that carbon be a chiral center ?therefore producing a racemic mixture. anyone please chime in

[@Notsann_minecraft960]

No to be a chiral carbon It should be attached to four different groups

[@Notsann_minecraft960]

Ya but it can be racemic mixture because it is dissymmetric and has a mirror image also it has an enantiomer

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