I also have a video for the Chi Square Test of Independence (with a contingency table) kzbin.info/www/bejne/gYiUnYVpZr2jirM. Thanks for watching!!
@user-td5bz2tf5o3 ай бұрын
Thank you.
@AngieTeaches3 ай бұрын
You're welcome!
@duykhoi1402 Жыл бұрын
Thank you. very informative steps.
@AngieTeaches Жыл бұрын
You are so welcome!
@facundopucill79572 жыл бұрын
Thanks!
@AngieTeaches2 жыл бұрын
You are very welcome, Facundo!
@phantomlegend211Ай бұрын
Sorry for my lack of understanding but if I may ask, say I have multiple questions in the survey I'll have to conduct a Chi square on every single one of them?
@AngieTeachesАй бұрын
The Chi Square checks for a relationship between 2 variables. For example, Is “gender” related to “screen time”. Conduct a chi square test for each pair of variables you’re analyzing. Hope this helps!
@ranjeettate86763 ай бұрын
It is clear that the chi-square test for a 2D array of data does not assume a uniform distribution. Is the chi-square test (for a single variable) valid for a non-uniform expected distribution? E.g. for a cohort of members all of whom joined on a specific date, I have data for the number who dropped out each week over the subsequent weeks - to simplify things until there are no cohort members left. My hypothesis is that this exponential decay (I am looking for deviations form it - e.g. that the drop out rate peaks in the third week). I can do a regression to get the time constant, can I use this to build the "expected" data and chi-square test against it? And then, if the p-value if smaller than something, so I can reject the null hypothesis, look for elements of the chi-square array which are large?
@AngieTeaches3 ай бұрын
That's a great question. This video from Lis Wilson may help kzbin.info/www/bejne/jpqZiIiXer6dZrssi=nh83Y1zHaMb4pnvn