Clamper Circuits

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Күн бұрын

Пікірлер: 95

@TheOrganicChemistryTutor 8 ай бұрын

Final Exams and Video Playlists: www.video-tutor.net/ Full-Length Math & Science Videos: www.patreon.com/mathsciencetutor/collections

@rabinsivadev3999 3 жыл бұрын

Calls himself the organic chemistry tutor. Has posted more physics and math videos than chemistry videos. Has videos on all topics and domains of science. This guy sure is a legend !

@caiyunwurslin2468 4 жыл бұрын

I tried to figure this out by myself ALL day without any luck, my text book only gives very little information. And the circuit looks so simply only with few components, so in some point I thought that I am the stupidest person in the world and get frustrated. You save my LIFE. Thank you !!!!

@abrahamabbas3557 3 жыл бұрын

Same

@PunmasterSTP 3 жыл бұрын

Absolutely same.

@eric1989 12 күн бұрын

@@PunmasterSTP me too lol i think its because if even a single idea is missing then it gets harder to make sense

@Teyros 4 жыл бұрын

You seriously rock!!!!! Amazing tutorials. Whenever I see one of your tutorials I always get happy because I think to myself "I'll actually understand this now". Thank you so much.

@muhammadrafay7398 10 ай бұрын

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@timschavusky 4 жыл бұрын

wtf now you have this topic as well? you are a legend mate!

@Rabb865 2 жыл бұрын

You are a gift from God thank you so much for the work you do 🙂

@azoozksa-op8rn 2 жыл бұрын

Thank you for existing

@yohansyalelet6476 3 жыл бұрын

I love ur voice and ur description tnk u i learn a lot

@Ranbir.Bhardwaj Жыл бұрын

Bro, can't tell you how much I owe you after watching this video

@luciferani8279 5 ай бұрын

My teacher took 4 periods to teach this, but I didn't understand :((( Thank you so much

@88NA Жыл бұрын

you are the best tutor. thank you so much for what you are doing. God bless you.

@yahasalel-sheibany5403 20 күн бұрын

Better than my lect. All credits to u Sir

@eggxecution 7 ай бұрын

personal notes, I realized you can kvl capacitors because the supply voltage is AC, capacitor are opened during DC. Since it's AC you can get Vc and VL if it's an inductor. Also, the capacitor charges if current goes from + to -, and when doing kvl, initially, Vc = 0V for positive clamp, so doing kvl would equal load to supply.

@provtech 6 ай бұрын

You're a great tutor ... GOD bless you

@jeremymathew7072 4 жыл бұрын

Amazing tutorial, please keep doing these! I'm going go through all the other EE tutorials now, thanks!

@juansoto6088 4 жыл бұрын

Thank youuu. I dont get why the textbook does not go deeper into the time constant and explaining how it affects charging vs discharging (I didnt remember). The book just says the capacitor has a large constant. period. and doesnt give any details on how clamping behaves before steady state. Its so much complex to put everything together without a complete explanation like this.

@lemonuncle 3 жыл бұрын

You deserve so much more attention my dude. Thanks a bunch

@ghufranalmoamen9470 3 жыл бұрын

i trust u more than my aec tutor

@aravindhancs1813 3 жыл бұрын

Thalaiva vera level..

@successthruknowledge 5 ай бұрын

So many new concepts for me in this video! I learned a lot although I needed to review several times. He did clarify one point from the earlier video that troubled me - so the Rl resistor does assume the voltage of the diode then?

@josephdalal6698 4 жыл бұрын

Organic Chemistry please, please make a video on timing diagrams. The basic ones, ones with MUX's and LUTs! please I beg of you

@kevingunawan4869 4 жыл бұрын

Why he always better than my EE lecturer

@nikitaavontuur340 2 жыл бұрын

Great video Sir,I only had to double check whether the voltage fluctuates around the capacitors and max voltage of both the positive and negative clamper circuit...I still love your videos ,Sir .

@PunmasterSTP 3 жыл бұрын

Amazing information presented in a wonderful way. Thanks so much!

@ethanhu2831 Жыл бұрын

4:05 To clarify, the diode is in parallel with the branch that contains the input signal and the capacitor, and is also in parallel with the load resistor.

@safalgupta6927 7 ай бұрын

bestt one till now

@shreyassomashekar6264 4 жыл бұрын

Great video!!! Your videos are amazing!!!!

@babarazamsucks 4 жыл бұрын

Tech Sure Couldn’t agree more!!!!

@ahmed221 2 жыл бұрын

you are 100% the best

@yvesbouchard5197 3 жыл бұрын

Many thanks for the tutorial! Crystal clear, as usual. I guess you meant "will not discharge completely" @7:24.

@naderhazem9928 3 жыл бұрын

no he meant charge because the resistance will take all the voltage then the capacitor's voltage will be approxi. zero.

@PunmasterSTP 3 жыл бұрын

I think it can get a bit confusing, since discharging a capacitor with a given polarity would have the same direction of current as charging the capacitor with the *opposite* polarity. In either case, in the ideal positive clamper circuit, the capacitor shouldn't discharge appreciably during the positive half-cycle (or, on the very first positive half-cycle, charge the other way). Then during the negative half-cycle, the capacitor would (quickly) charge with the correct polarity.

@MohamedAhmed-nf8qh Жыл бұрын

he meant charge because resistance is low, if it was high it wouldn't discharge completely

@chanakadilshan9036 3 жыл бұрын

thank you

@simonhaesaert8175 9 ай бұрын

very great explanation video

@fortunetmupeta130 2 жыл бұрын

you are a guru sir

@parasite4076 3 жыл бұрын

So what you're saying is that the capacitor charges up in the negative cycle to offer a positive base around which the voltage fluctuates? Thanks for the explanation!

@parasite4076 3 жыл бұрын

I see now how that capacitor works, it basically is a line except when the voltage exceeds the positive clamp voltage of the diode in the correct direction. When the voltage is bigger then the stable voltage of the diode on the positive direction, all of the rest of that excess voltage gets dumped into the capacitor, causing it to charge up to the maximum voltage remaining. (i.e the input minus the diode stable voltage)Then when it does, it will remain the same voltage and stay the same(idk why tho). Then what happens is as if the load is connected in series with a DC source, the voltage is the capacitor's. The process starts at the exact moment the peak positive voltage is reached, when the capacitor finished charging. After that it acts like a DC source, and founds the base around which the ac voltage fluctuates.

@PunmasterSTP 3 жыл бұрын

I think that is a great way of putting it!

@Enigma758 3 жыл бұрын

It seems to me that this circuit would not work well when driving a low impedance stage (e.g. a speaker). I suppose you would have to add buffering if that were the case.

@emiliomota2459 4 жыл бұрын

You ser a genious man

@khanyisanibuthelezi676 4 жыл бұрын

sir can you please help us with the laplace transform videos problems and answers

@BlackZero1X 10 ай бұрын

You are just amazing!

@mr.helpful3844 3 жыл бұрын

thank you for the great videos

@km-sc4kz 4 жыл бұрын

great video :) I had a doubt: is the time period of the clamped signal the same as the original? Because just looking at the diagram, I'm not sure.

@syabongajele6431 3 жыл бұрын

i do see but the logics are blowing my mind why for the negative clamper you introduce the ground and the Vc becomes negative but in the positive clamper everything was on point mathematically and scientifically?

@thisz123 4 жыл бұрын

At the negative clamper, why put a connection to the earth? If earth is at 0 V potential, than you have a short circuit between power source and ground no (during first wave)?

@PunmasterSTP 3 жыл бұрын

That’s a good observation. I think that as long as only one side of the voltage source is at ground, then it isn’t a short circuit. If the more negative side is grounded, then the source would generate a relative positive voltage, and vice versa. From the diagram, the other side of the voltage source has to go through the capacitor and then either the diode or the load resistor to get to ground.

@suraomar3350 Жыл бұрын

Thank you so much

@simozy4475 Жыл бұрын

thanks a lot

@ahmedragab3679 3 жыл бұрын

جمدااااان ❤❤

@myjbrz 3 жыл бұрын

Hi! There is some points I didn’t understand : 1- at point c which is the debut of the negative cycle the diode is forward biased but it also needs 0.3 V to conduct. Correct me if I’m wrong but when the negative cycle comes the diode anode is at O V but I can’t figure out what’s the potential at the cathode. In other words I would like to know how the diode cathode potential varies during the half negative cycle. 2- since during the half negative cycle the capacitor becomes more and more charged until it reaches Vm how the diode could still conduct if the cathode which is connected to the positive side of capacitor is more positive than the anode knowing that the anode is at 0V ? 3- I always used to draw the potential arrow from the positive side of the component to its negative one. From D to E the diode doesn’t conduct anymore. Then the circuit is just Vin C1 and RL. So for me I would draw the potential arrow from right to left for C1, from top to bottom for RL and from bottom to top for Vin since we are still in the negative cycle which means the bottom is most positive than the top. According to Kirchhoff law I will sum the arrow in the same direction and substract the arrow in opposite direction : Vout + Vin = VC1. This is how I would do. In others words I don’t get how you could say that from D to E Vout is the sum of Vc1 and Vin. So these are the 3 points I didn’t really get from the video. Any help would be appreciated. Thank you !

@Teyros 4 жыл бұрын

How do we determine the polarity of the non-polarized capacitor? I'm not sure when to add the capacitor voltage or subract it from the input when trying to make my waveform?

@km-sc4kz 4 жыл бұрын

in the case when diode is forward biased, the capacitor is charged up (because it connects to the voltage source along a low resistance path), you can determine the polarity of the capacitor by looking at the polarity of V input. in the first problem, the diode is forward biased when the top terminal is -ve and bottom terminal is +ve. so the polarity of the capacitor would be -+ from left to right.

@themiyack6192 3 жыл бұрын

Awesome..!! :))

@studentapple7920 3 жыл бұрын

Anduna neh Themiya malli 🤣🤣🤣

@AhmedElsayed-ur1iy 2 жыл бұрын

Amazinnnnng dude I love it

@Harry001by7 9 ай бұрын

What happens if we introduce a series resistor in the input side and for time varying square wave input signal, how to calculate R and C (if the input signal frequency is around 1MHz how the circuit behaves and what type of diode we have to chose ?).

@kiran6042 3 жыл бұрын

Why don't they just use a biasing voltage,we will instantly get the clamping

@SorooshMhs 2 жыл бұрын

7:03 how does the + half cycle current flow through C1? Isn’t C1 supposed to accept current from right to left in this arrangement? I mean since it’s it’s an electrolytic capacitor i thought it could only be used in a DC circuit

@usdohs 5 ай бұрын

Does a clamping circuit change anything about the shape of the waveform?

@Thoalfeqargamer 4 жыл бұрын

i love you man😍

@kabandajamir9844 2 жыл бұрын

So nice

@Acesushii. Жыл бұрын

what to do when negative clamper has, freq, capacitor, battery and rl value?

@Tashrif-00 Жыл бұрын

at 14:14 , can you please explain why we need to use a polarized capacitor

@李全棣 2 жыл бұрын

why does the Vm (the voltage across the capacitor) not change in the right-hand side of the negative half circle at the first circle ? (still remains 9.7V)

@Yusufksdmr 4 ай бұрын

I want to ask a question What happens on the graph if I change the resistor value?

@husnainhyder6713 Жыл бұрын

can we use Laplace Transform to draw the waveform at output if all the values are given and the time period of input waveform. please explain.

@rupeshortega9680 3 жыл бұрын

Physics tells us that capacitor stores energy through electric field, but electrons cannot pass through dielectric between the plates, but the way he explained, electrons pass through the dielectric but block by the diode in reverse bias, is that so? I hope he would explains it further.

@ohmslaw6856 3 жыл бұрын

Current does flow through capacitor

@PunmasterSTP 3 жыл бұрын

I may be wrong but I think he was saying that if only a small current goes to the capacitor, then the plates will have very close to the same voltage.

@PunmasterSTP 3 жыл бұрын

@@ohmslaw6856 I think it depends how you think about it. Electrons will move onto one plate when other electrons move off of the other, so from the outside, it looks like current is moving “through” the capacitor. But in actuality, no electrons are crossing between the plates (at least unless the capacitor starts breaking down).