Voltage Multiplier Circuit Using Diodes and Capacitors

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The Organic Chemistry Tutor

The Organic Chemistry Tutor

Күн бұрын

Пікірлер: 97
@TheOrganicChemistryTutor
@TheOrganicChemistryTutor 10 ай бұрын
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@valenmosquera9
@valenmosquera9 9 ай бұрын
You're literally the only person who didn't skip important steps. Thank you!
@tendaimoyo
@tendaimoyo 21 сағат бұрын
This is by far the best explanation ive seen so far. I've been struggling with this for two whole days. Most texts and videos skip all the nuances of current flow like you did and that makes all the difference. Your visuals and explainations are so easy to follow. Thank you!!
@mariolazzarini5806
@mariolazzarini5806 Жыл бұрын
By far the best explanation I´ve seen of this. Finally, someone explains in detail every cycle. Thank you so much!
@amitzerikunthe7635
@amitzerikunthe7635 Жыл бұрын
i can't express in words how u tought this concept....i saw nearly 10 videos but i did't ge understand from anywhere but u explained it in very easy way.....thank you so much sir
@stephendixon8575
@stephendixon8575 7 ай бұрын
Excellent effort to explain the complexities of this type of circuit. It’s helpful that you explained why the voltage drops across the diodes were left out the calculations for the sake of simplicity, but I think it is also worth explaining that 12V AC power source in this is also being simplified to mean 12V Peak AC, rather than the usual 12V AC being RMS (i.e. an ‘average’ of 12V) where the peak voltage would actually be higher (~16.9V before diode voltage drops). Appreciate you’re trying to simplify things, but its important people understand the actual voltages would be much higher (especially if anyone is thinking of playing with making a real circuit!). Great job 👍
@alexgee248
@alexgee248 2 жыл бұрын
This is the best explanation I've seen yet. For the first time I understand how this works.
@Marimuthu-hn7pr
@Marimuthu-hn7pr 4 жыл бұрын
Sir,I really many more & most thanks because that circuits work on my maintenance department //lot lot of thank you very much
@binbin6525
@binbin6525 4 жыл бұрын
I really appreciate your videos. Your videos are awesome and I can easily understand it. Thank you SO MUCH. You are a good speaker.
@thanksgiving156
@thanksgiving156 4 жыл бұрын
✊🏽✊🏽 keep on doing the electronic lessons✨💖💖💖. I really need them. I have downloaded more than 10 videos of Electronic lessos
@thehaseeb9136
@thehaseeb9136 2 жыл бұрын
Thank you sir, Only well explained video on YT.
@landonfrigault2183
@landonfrigault2183 Жыл бұрын
Oh man, the things I would do to this man, for all the help he's given me over my career, insane.
@inventorbrothers7053
@inventorbrothers7053 4 жыл бұрын
Awesome explanation! I now understand how this circuit works! Thanks!
@Amandeeprana437
@Amandeeprana437 2 жыл бұрын
Thank you so much, i understand easily from your video..
@akamiyire4147
@akamiyire4147 4 жыл бұрын
wow your voice is very clear in this video thanks man keep the good work God bless you million times a day.
@igorying8548
@igorying8548 Жыл бұрын
Very clear explanation, thanks!
@snoobeagle
@snoobeagle 4 жыл бұрын
Very good tutorial! Helped me a lot!
@dennisjohnson8753
@dennisjohnson8753 Ай бұрын
Very good video
@luizcvieira3124
@luizcvieira3124 2 жыл бұрын
So... if you manage to control the 12Vac from 0 to 12, you're going to have a 0 to 72Vcc controlled output, minus all diodes' voltage drops. Considering a possible high-voltage source to, say, capacitor revival, a sinusoidal generator (60Hz or some more suitable frequency) connected to the input of a "tunned" symmetrical power amplifier with some tens of output voltage and some hundreds of milliamps @ its output and driving a multiplier would then give us a DIY controlled high-voltage, low-current capacitor revival circuit. Also, each diode junction would provide some lower voltage output, that could be connected to a selection switch for max voltage output. Hummm... Sound "delicious"... Of course, capacitors' working voltage MUST be carefully set, or else... KABOOM!!!
@Lababthuh
@Lababthuh 3 жыл бұрын
Why does the current not flow to C2 in the 1st negative cycle?
@energyforever720
@energyforever720 2 жыл бұрын
does the voltage across the capacitors ever get higher than double the input voltage? like, if you had 100 stages, would the voltage measured across the capacitor in the 100th stage only be double the input voltage? im trying to understand what capacitors should be used in a circuit like this, that info was absent from the video for some reason. is there a rule of thumb for picking capacitors for votage multiplier circuits, like 4 times the input voltage no matter how many stages you make? also, is there a maximum amount of stages you can make?
@JeffreyJamon
@JeffreyJamon 3 ай бұрын
With each stage the voltage is multiplied higher so, the capacitor increases with each stage. Over this design's length the cost could be less with the first stages but the capacitors in added stages would be factored because circuit analysis that reveals more information would tell you these values. If starting with High Voltage ⚡ then, its special characteristics should be considered because it's prone to ark.
@Glockperfection666
@Glockperfection666 2 жыл бұрын
Best !!!
@nishitjoshi1600
@nishitjoshi1600 4 жыл бұрын
can you make a explanation video on voltage multiplier ckt working a dc source
@SidJain-h7b
@SidJain-h7b Жыл бұрын
Good explanation, thanks!! Is it possible to multiply voltage of small signals using this method?
@reginaldhorkyiiregorreggie1559
@reginaldhorkyiiregorreggie1559 Жыл бұрын
current doesn't flow thru a capacitor. if it did it would be called a short. I think what you mean is charge the capacitor. outside of that, thanks. lol. I made one when I was ten. now I know why it didn't work. I used dc. I wonder if that's the same principle behind a fly back circuit. I'm designing an ac inverter for fun and I'm dead set on using the irfp250's that I ordered at 120v. hum? I know lower voltage rectification. but I don't want to. I want to use the 250's at a higher efficiency.
@jaysmith3259
@jaysmith3259 Жыл бұрын
Current always flows during capacitor charging until finished with the voltage you're charging it with.
@JackieBrown3123
@JackieBrown3123 Жыл бұрын
Good explanation thank you. What type of diode and capacitor could we use? What is the maximum frequency used with this circuit?
@successthruknowledge
@successthruknowledge 7 ай бұрын
It was a good lecture though I guess that I'm hazy yet why the current only goes through the nearest diode back to the negative terminal of the AC source and not dividing itself between the diode and the next capacitor along the wire. If you follow my reasoning. For example after the current passes through D1 and charges C1 then why doesn't it charge also C3?
@karhukivi
@karhukivi 7 ай бұрын
Just a quick answer, because as it charges C1 the voltage is held constant and a silicon diode needs a forward voltage of about 0.7V before it conducts, so D2 isn't conducting. .
@successthruknowledge
@successthruknowledge 7 ай бұрын
@@karhukivi thanks!
@sravanth3008
@sravanth3008 4 жыл бұрын
yo whats that software you use man?
@kruimels
@kruimels 2 жыл бұрын
I live in the Netherlands, were we have 220 volt ac. What kind of capacitors and diodes I need?
@blissboy1642
@blissboy1642 2 жыл бұрын
Please I want to know if this strategy also work for Ac to AC voltage booster
@Renshen1957
@Renshen1957 10 ай бұрын
It would be easy to use two transformers: Input Primary to mains voltage T1-then connect the secondary winding of T1 to secondary winding of T2, and use the primary winding as the AC voltage booster. Transformer 1 120V secondary 12 v to 12 v secondary winding T2 and Primary 230 V to 230 volts AC Use different secondary windings on T2 for desired voltage boost, advantage isolation from mains, disadvantage weight and current limited to secondary T2 rating.
@ShilohSedlak
@ShilohSedlak 4 жыл бұрын
If every one of the capasitors are only rated at 12 volts will this system still work? Or do I need higher rated capasitors all the way down the line?
@inventorbrothers7053
@inventorbrothers7053 4 жыл бұрын
You would need an appropriately rated capacitor for the voltage potential it will be storing.
@alimuhammad.s3013
@alimuhammad.s3013 Жыл бұрын
Is this a practical ckt? Can we run loads on it like LCD?
@Cien_Swiatla
@Cien_Swiatla 3 жыл бұрын
Can you explain why D1 and D2 do not discharge the capacitor C2?
@PunmasterSTP
@PunmasterSTP 3 жыл бұрын
I think the reason would be because the terminal of C2 connected to the cathode of D2 is at a higher voltage than the terminal of C2 connected to the anode of D1. Therefore the diodes would prevent the discharging of C2, since they would be reverse-biased in that situation.
@jaysmith3259
@jaysmith3259 Жыл бұрын
Because the second half cycle coming off of source voltage plus charged C1 at 12 volts, makes it a 24volt charge to charge C2.
@Cien_Swiatla
@Cien_Swiatla Жыл бұрын
@@jaysmith3259 Thx
@ATLAStheprotogen1
@ATLAStheprotogen1 4 жыл бұрын
Hi I have a question well a few the first one is do I have to have a transformer on the input the second one is do you need different number diode‘s for each connection because I only have one kind third I’m using a set called snap circuits and the only other numbered diode‘s have lights on them which sucks up a lot of voltage please respond thank you
@descampk2346
@descampk2346 4 жыл бұрын
That parallel battery gon blow up
@ninjafishing7120
@ninjafishing7120 3 жыл бұрын
Can i series the capacitor without the diode ? Will it work ?
@Renshen1957
@Renshen1957 10 ай бұрын
What you illustrate in this video is known as a Cockcroft-Walton Multiplier...
@JeffreyJamon
@JeffreyJamon 3 ай бұрын
Thank you! This is what I was searching for in the comments!
@Renshen1957
@Renshen1957 3 ай бұрын
@@JeffreyJamon Hi, you’re welcome, glad to be of help. The voltage multiplies, but the current is halved. There are current doublers which require inductors…I have yet to use the current dabbler in series with a subsequent voltage doubler.
@juanmf
@juanmf Жыл бұрын
No increase in energy but no waste in skin effect of magnetic induction.
@usermlgbzzcnm
@usermlgbzzcnm Жыл бұрын
why in the first negative half cycle current isn't flowing through c2-d3-c3-c1 etc.
@jaysmith3259
@jaysmith3259 Жыл бұрын
Because current flows the path to Source with the least resistance with the voltage you're starting out with.
@doprisi
@doprisi 3 жыл бұрын
If you discharge the circuit, will only the last capacitator be discharged or all at once? I would bet only the last given how a capacitator works.
@Mark-k2z9p
@Mark-k2z9p 5 ай бұрын
Are AC capacitors needed? Or does it work with DC capacitors?
@JeffreyJamon
@JeffreyJamon 3 ай бұрын
Non polarized capacitors that can take AC are required.
@iwantsushant
@iwantsushant 4 жыл бұрын
But In the mosquito bat this formula used with different style???
@adhambarakat8688
@adhambarakat8688 3 жыл бұрын
Is he using conventional current flow?
@sakdavith6969
@sakdavith6969 4 жыл бұрын
Could u make an explanation vid on integrated circuit?
@ikekennedy9700
@ikekennedy9700 4 жыл бұрын
How would you hook up the input and output
@brandonsmith8680
@brandonsmith8680 3 жыл бұрын
Input could be a battery and output could be an arc
@juancarlosabad3298
@juancarlosabad3298 4 жыл бұрын
...any AC voltage source is specified as Volts - RMS = Vrms...so a 12Vrms voltage source will charge the first capacitor at 12V*sqrt(2) = 16.97V ~17V (- voltage drop on the diode ~0.7)....~16.3V ...and not to 12V as wrongly explained in the video...
@abhiramkj2910
@abhiramkj2910 4 жыл бұрын
Look into peak detectors
@jaysmith3259
@jaysmith3259 Жыл бұрын
He is explaining the first half cycle, not the second half cycle.
@aselim20.
@aselim20. 2 жыл бұрын
I watched it.
@newton4098
@newton4098 3 жыл бұрын
wait parallel batteries dont subtract thier voltages. You either add the volts, or add the Amps......
@Dinco422
@Dinco422 Жыл бұрын
Is not really 'as far as you want' because of the losses.
@Owliver0411
@Owliver0411 10 ай бұрын
Why do capacitors charge up one at a time ? Wouldn't they all charge at the same time ?
@JeffreyJamon
@JeffreyJamon 3 ай бұрын
Only possible if capacitors are already charged to the DC voltages already before the input voltage is applied.
@kristofersozo464
@kristofersozo464 4 жыл бұрын
Is there any simple formula for this circuit?
@kietluu4577
@kietluu4577 10 ай бұрын
Where are the positive and negative ends of the output voltage?
@JeffreyJamon
@JeffreyJamon 3 ай бұрын
Positive/point D and negative/point A.
@indibil
@indibil 4 жыл бұрын
¿And the ground is connected 1/2 wave to positive, and 1/2 wave to negative???? don't produce short circuit with the rest of circuit??
@wgcr7gaming406
@wgcr7gaming406 2 күн бұрын
why dont we take the positive half cycle first
@abdessalemakerma4636
@abdessalemakerma4636 4 жыл бұрын
the polarized capacitor cant run by Ac !!
@inventorbrothers7053
@inventorbrothers7053 4 жыл бұрын
ha good catch
@abdessalemakerma4636
@abdessalemakerma4636 4 жыл бұрын
@@inventorbrothers7053 what do u mean
@inventorbrothers7053
@inventorbrothers7053 4 жыл бұрын
@@abdessalemakerma4636 I meant that it was Good that you caught the mistake made in the video. That polarized capacitors can't take a reverse polarity voltage. That's all.
@abdessalemakerma4636
@abdessalemakerma4636 4 жыл бұрын
ah okey thanks
@S24W2
@S24W2 Жыл бұрын
Actually, the polarities on the capacitors are not changing
@mattstroker
@mattstroker 2 жыл бұрын
Why only ac? Why doesn't anyone talk about a DC version?
@WaffleRune
@WaffleRune 10 ай бұрын
It should be easier, and then you use a rectifier to turn it into AC with a total voltage smaller than the peak voltage, but still above like, half of it, specifically Vp/√2
@JeffreyJamon
@JeffreyJamon 3 ай бұрын
Joule thief uses batteries as a power source or DC input. A square wave would work for the OP. A square wave input is a DC input.
@paulosergioenergia1659
@paulosergioenergia1659 4 жыл бұрын
I wish know about frequence response of this kind of circuit, if someone did, plz awsner this coment.
@thecyborg6718
@thecyborg6718 3 жыл бұрын
Current it flows only from negative to positive dude...
@mint2607
@mint2607 3 жыл бұрын
It flows from positive to negative based on conventional flow. I think you're basing it on electron flow?
@niksa28
@niksa28 4 жыл бұрын
Charging of C3 is explained very badly, he should have simply said we got +36V and -12V charging it to 24V.
@Someone-de7wf
@Someone-de7wf 4 жыл бұрын
What grade is this?
@keepmehomeplease
@keepmehomeplease 4 жыл бұрын
Probably college electromagnetism or AP chem
@Someone-de7wf
@Someone-de7wf 4 жыл бұрын
Koop Bar Oh wow, thanks so much
@sakdavith6969
@sakdavith6969 4 жыл бұрын
@@keepmehomeplease probably more of electronic engineering.
@keepmehomeplease
@keepmehomeplease 4 жыл бұрын
@@Someone-de7wf can't tell if you were being sarcastic but what i meant in actual grades was probably around 11th grade or college introductory type class
@ExodusX1
@ExodusX1 4 жыл бұрын
@@keepmehomeplease oh, I'm in 8th grade lol. I enjoy learning about electricity and circuits.
@bullblood1641
@bullblood1641 9 ай бұрын
Thank you! I spent around 3 hours trying to understand this with different videos, but you helped me realize the key point in just 10 minutes. You're the best! 🎉🫶🏼
@blissboy1642
@blissboy1642 2 жыл бұрын
Please I want to know if this strategy also work for Ac to AC voltage booster
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