Class 12 Physics | Electromagnetic Force | #18 Force on Random Shaped Current Carrying Wire

[@roneet9027]

thank you sir

[@frankenstein9123]

Such a flawless explanation!

[@alphaiitd1]

Beautiful

[@yuko5894]

ありがとうございました ！ Your videos are very helpful 😄

[@sherlockjunior8612]

If you're BTS holic, why have you used Japanese?

[@yuko5894]

@@sherlockjunior8612 Because my native language is japanese And being a BTS Army has nothing to do with the nationality or language of a person !

[@sherlockjunior8612]

@@yuko5894 Oh wait, you're actually Japanese! Sorry! Lol, There are many Indians who are crazy BTS fans, so I thought maybe you are one of them... And wondered why an Indian wrote Japanese if he was a K-POP fan lol... Gommenasai! I am learning Japanese myself :P

[@yuko5894]

@@sherlockjunior8612 Lol , so it was just a misunderstanding XD Daijoubu (•ᴗ•)

[@sherlockjunior8612]

@@Kirandevi3673 Imagine the opposite, if he didn't break the length into dx and dy... Imagine if we just write the resultant force on the original 'dl' length, according to Fleming's left hand rule... It will give the direction of force on the current carrying element Then if your break down that Force into x and y directions, won't you say that the vector sum of those x and y components is the net Force?

[@barkhagangwani4066]

awesome explanation sir i was solving iit jee previous year que and came across such a que i couldnt understand it first but now i got it thank you so mucu

[@DieAnotherDay6969]

What if we place another wire at origin ? Then ?

[@rajeevshrivastava9491]

....

[@Nimai_15]

sir can't we do this with any other metal in aqueous medium why only mercury

[@sd12217]

Sir can u plz make videos on error analysis ,v.c,screw gauge

[@physicsgalaxyworld]

Yes it will be done soon...

[@cosmolearner5562]

not uploaded yet also cyclotron is not explained

[@badhil4468]

@@cosmolearner5562 Are you preparing for 2021 let me know please I have some doubt to clarify?

[@cosmolearner5562]

@@badhil4468 No, I am NEET 2020 Aspirant!

[@badhil4468]

@@cosmolearner5562 Best of luck for neet stay safe😷😷

[@foodie5448]

Sir I have a doubt . While mentioning , direction of magnetic force - also we need mention signs +ve or -ve . ? And How can we define that the force is attractive or repulsive ? Please sir clarify my doubt. And you are fabulous physics expert .😊

[@madihasiddiqui4540]

the sign +ve or -ve will be placed according to the axis you take for eg if the force is along x axis its +ve if its opp to it its -ve sometimes we take other vectors as reference axes like if you take length as the reference vector then if b is along length its +ve.and attration or repulsion are defined with respect to an object like in case of two parallel wires the force on a wire with respect to the other could be attractive if its in the direction of the other wire,

[@adityarajiv6346]

sir what will be the magnetic induction at the center of infinte concentric circles?.......it iss given that the direction of current in every alternative circle in opposite to the pervious one...

[@physicsgalaxyworld]

You can write the expression in form of series and sum up... if radius is given then it can be summed up...

[@adityarajiv6346]

Physics Galaxy but sir it is extending to infinity..., won't it just be the same as that for one circular coil?

[@physicsgalaxyworld]

As there are infinite circles... you either need to sum up the series, as current is same and radius is growing, it will be a converging series... or if turns are close packed, we can use integration also by considering an element...

[@adityarajiv6346]

okay thank you sir

[@ruchisingh8796]

respecected sir will direction of force on random shape conductor is same as that on direct wire between the end points

[@ayushgupta4077]

yes...

[@StrikerBot]

for a circular loop, will it experience a force? ( length b/w two terminals is 0 i guess?)

[@adarshchaturvedi3498]

Sir how u have determined dirn of current in dx and dy?

[@physicsgalaxyworld]

Its the same direction as that of the element...

[@adarshchaturvedi3498]

why ? won"t we resolve current also.. i know result will be same , but can we generalize this thing , if one wire along y dirn carrying current, other in x dirn , can we equate this to resulting wire along 45degree with same current , will all parametres of elec. and magnetism will remain same ?

[@kandukuruchandbibi6299]

Sir how we can integrate sir we have to do vector addition na sir how you decided the direction of all the elements are same pls clear my doubt sir pls 🙏

[@madihasiddiqui4540]

its because he already resolved the length dl along x and y as dlx and dly and hence the force would be just perpendicular to the lengths for eg force for xaxis elements were along y axis

[@theexperiment9105]

Sir if we take a circular current carrying wire will it move in any direction or not,?

[@physicsgalaxyworld]

as explained it will experience the force like a straight wire of length equal to the line joining its end points...

[@theexperiment9105]

Physics Galaxy thanks sir I was bit confused about it

[@theexperiment9105]

Sir here is net torque is 0 on wire I want to ask that will it move along y-axis straight ward or rotating?

[@physicsgalaxyworld]

If you have watched the above video completely and carefully you can see that all the forces acting on the elements of the wire are in y direction so these will not produce any rotational effect on the wire... as it is acting along the whole length of wire...

[@theexperiment9105]

Physics Galaxy if we take a wire having non uniform cross section then also moving straight forward direction or not answer I want to ask you that is there any effect on non uniformity of mass in motion of wire

[@physicsgalaxyworld]

Yes in that case its center of mass will not be at geometric center so it will have some rotational effect as well...

[@theexperiment9105]

Physics Galaxy thankyou sir

[@jamunabaskar7537]

Here why right hand thumb rule is used , shouldn't it be left hand

[@sanketgharatkar5379]

Sir what if while integrating dfx limits will be from 0 to x

[@physicsgalaxyworld]

Then result will be non zero for force in x direction...

[@poojasuthar548]

Sir how can i watch your previous booster classes videos.

[@asishbauri7433]

Sir why u have taken the limits of integration of dFx from zero to zero

[@physicsgalaxyworld]

Because both the terminal points of wire are at y=0