CN | Flow Control Methods | Introduction to Access control methods, TDM and Polling | RBR

[@priyanshushankhdhar3258]

sir plz start making videos on network security...... very important for many userssss

[@bukharifaraz]

If each station requires 2 kbps BW only, and total BW allowed is 2Mbps, then why only 1000 stations are allowed? I mean, each station is asking for the bandwidth alone (i.e. at a time only one station is utilising the link) in TDM, then why there is a limitation on the number of stations connected ?

[@akashsinha5611]

Because Time is divided among stations for using the line. If BW of line is 2Mbps, then that 2Mbps is used by a single station for only 1/Nth of a second. So the BW for that device will become (bits transmitted)/total time. Hence it is 1/Nth of the total bandwidth. Hope you understand.

[@nishitshah1653]

hi Akash, correct my solution If I am wrong? As mentioned by you BW for a device = (bits transmitted)/total time so, BW for a device = (x bits/1 secs) considering in 1 second, x bits are transmitted. 2 Kbps = x/1 Then BW given = (Total bits transmitted by all device/total time) = 2 Mbps BW = (sum of bits transmitted by all devices/total time) = ( x1 + x2 + .... + xn)/(1 secs) n * 2 Kbps = 2 Mbps Hence, n = 1000

[@mysmallcap]

Thanks a lot bhai

[@mysmallcap]

Yes Nishit Shah, your solution is correct.

[@satyamgupta1105]

@@akashsinha5611 But for 1/Nth of a second, total bits transmitted by the particular station is 1/N th of total bits transmitted per second by it.

[@ShivamVerma-mu6oy]

Why Tp is not part of useful time? As it is the time when the data packets are present in the link and is being transmitted to destination( worst possible case)?

[@vivekjain6854]

10:20 why N is not infinite? because only one station can use link.

[@debabratabhattacharjee1313]

That's what I was thinking 🤔

[@piyushmittal4780]

Why we are seeing effective bandwidth? In bandwidth allotted to a channel, it'll transmit the data which includes total time to transmit data i.e. both transmission time and propagation time and propagation time is time which is reducing effective bandwidth. So according to me it should be BW = 4mbps N x 2kbps = 4mbps N = 2000 So 2000 stations should be there. Because 2000 stations will transmit data at 2kbps then 4mbps BW is required out of which 50% is inefficient as 50% time is wasted in propagation. Correct me if I'm Wrong..

[@coderslife7561]

what is the correct ans

[@jerinpullan5123]

nice method of teaching..

[@nagarajmahajan2336]

thanks

[@sanketsh6748]

Sir, Which book did you say to refer at 2:49

[@Maydays960games]

Data Communications and Networking By Behrouz A.Forouzan

[@vinaypant5027]

at 10:12 sir how could be the value of n is 100 n*2 kbps=2mbps {1 mbps=2^10 kbps) so n=1024

[@anilbabu7239]

when it comes to counting 1kb=10^3 and 1mb=10^6 when it is data 1KB=2^10 and 1MB=2^20.

[@Neon_-xo4gn]

thanks sir ur video very helpfull

[@louerleseigneur4532]

Thanks sir Thanks god

[@sword013]

9:30 , If someone is watching this recently, please explain this.

[@BikashSingh-ze4ny]

if there are N users than bandwidth is divided in N equal-sized portions

[@sword013]

@@BikashSingh-ze4ny Whats the meaning of the formula ? Is what I'm asking. Why Effective bw ? At a point of time, only 1 station is going to utilise it, so it may just use the whole bw. Theres no clear explanation of this formula anywhere, although I know it holds cause sir just told it. But, the context and meaning is not clear. And everyone explaining this, it seems they're just talking about bw, but I'm concerned about the whole formula.

[@BikashSingh-ze4ny]

@@sword013 you are right, in Tdm the user gets full bandwidth of the channel in particular time slot. Bandwidth is divided in Fdm

[@sword013]

@@BikashSingh-ze4ny Yes thats why I still do not understand why effective was used. And why would one divide the bw if only one is going to use at a time ?

[@BikashSingh-ze4ny]

@@sword013 becaues bandwidth is theoretical measure of data transfer while throughput (effective bandwidth) is actual speed of data transfer

[@laxitrana2344]

Why tp is noT useful time ??

[@pranavsharma7479]

its time for the packet to come in the channel

[@AjeetKumar-he9lk]

@9:31 If all the stations are using the link individually, then won't they have access to whole 2Mbps at once ??? What am i missing here??

[@grajeshbharadwaj]

you are right. But I think because we are having 1000 stations and everyone is using 2mbps only for a fixed slot and remained ideal when other stations are in use, on average it goes back to 2mbps/1000 = 2kbps.

[@Modern-Mastani]

fantastic

[@mrsmurf911]

Hi aap kaise hoo

[@shradhaverma2272]

thank uuu sir your videos are very helpful

[@divyasree-br7il]

thanks annaya

[@tarangsharma123]

nice!

[@gurpalsingh5566]

DAR...

[@jsl_21]

i liked the previous lectures but this one is bad. Not taught very well.