Comparison test for improper integrals example 2, calculus 2 tutorial

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blackpenredpen

blackpenredpen

Күн бұрын

Learn how to use the comparison test to determine if an improper integral converges or not.
We will do the integral of x^2/sqrt(x^5-1) from e to infinity. The 3 steps to use the comparison theorem for improper integral: what you know, do the check, and draw the conclusion!
Check out example 3: • Comparison test for im...
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Пікірлер: 31
@williampattison6628
@williampattison6628 6 жыл бұрын
I need more teachers like you. You explain things a lot better than a large majority of the teachers that I have had in the past
@jayyyalldayyy
@jayyyalldayyy 7 жыл бұрын
I've watched a few videos on the comparison test and yours are by far the most helpful ! thank you 😊
@mohammedaamir9582
@mohammedaamir9582 4 ай бұрын
Thanks, amazing teaching!
@andreamonteroso8586
@andreamonteroso8586 4 жыл бұрын
good thing blackpenredpen and youtube exist
@larissa8232
@larissa8232 4 жыл бұрын
Thank you thank you thank you omg thank you SO much
@juanjosemiguel6966
@juanjosemiguel6966 7 жыл бұрын
I tried to integrate that function, but i could not. I putted into Wolfram Mathematica and the result was longer than expected. Clearly this integral isn't very easy to resolve, true?
@rafiihsanalfathin9479
@rafiihsanalfathin9479 4 жыл бұрын
Juan José Miguel well thats called divergent :)
@ladyanne4294
@ladyanne4294 5 жыл бұрын
hey btw you have really helped me alot.thank u
@vivellywang4037
@vivellywang4037 7 жыл бұрын
ok,take your time Thanks. Take care
@princessmalobola8378
@princessmalobola8378 4 жыл бұрын
And he's sooo funnny :-)))))!!!
@luyandamolala1108
@luyandamolala1108 Жыл бұрын
Wola mzukulu ka Chan
@vivellywang4037
@vivellywang4037 7 жыл бұрын
How do they get linearly independent on (-Infiniti, Infiniti) ? Please upload some videos if you can. If you can't, it's ok. I did research on KZbin, I couldn't find one good video. Thank you so much tho. Take care. I've been watching your videos since spring 2016. You are the best.
@ncedonqeto9107
@ncedonqeto9107 Жыл бұрын
What happens when the inequality is false , say the the integral you start with ( the know) is covergent and you work that until you see that the inequality does not hold true , would that mean the improper integral is divergent ?
@blackpenredpen
@blackpenredpen 11 ай бұрын
check out example 3 kzbin.info/www/bejne/a3izamlpoLWmhqc
@DestinyQx
@DestinyQx 7 жыл бұрын
i love your videos! (side note: slight error at 6:10 ? shouldn't it be x^5 ≥ x^5 - 1 ? same conclusion though in the end)
@blackpenredpen
@blackpenredpen 7 жыл бұрын
DestinyQx yea. I didn't square both sides tho. I just rewrote the 5/2 power with sqrt lol
@DestinyQx
@DestinyQx 7 жыл бұрын
thanks for videos! i began studying diff eq because of your vids.. maybe one day i'll study linear algebra too
@blackpenredpen
@blackpenredpen 11 ай бұрын
kzbin.info/www/bejne/a3izamlpoLWmhqc
@I_make_countless_mistakes
@I_make_countless_mistakes Жыл бұрын
i thought it would be 2 instead of 1at 3.15 Since a =2
@qwerasdfqe
@qwerasdfqe 6 жыл бұрын
what would you do if the equality check gives you false?
@NotYourAverageNothing
@NotYourAverageNothing 7 жыл бұрын
It has no elementary solution.
@vivellywang4037
@vivellywang4037 7 жыл бұрын
Can you do some differential equations?
@blackpenredpen
@blackpenredpen 7 жыл бұрын
vivelly wang I am uploading, some second order and reduction of orders. What topics did u have in mind?
@vivellywang4037
@vivellywang4037 7 жыл бұрын
blackpenredpen thank you. I'm working on homogeneous second order linearly dependent and linearly independent. I knew all the basic stuff, but some books wrote really hard theorem. I don't understand. It's about f(t)=t^2 if t=0 and g(t)= 2 t^2, if t= 0 are linearly independent on (-Infiniti, +infiniti). I only understand they are linearly dependent on (-infinit, 0) and (0, + Infiniti).
@blackpenredpen
@blackpenredpen 7 жыл бұрын
vivelly wang vivelly wang hi vivelly. It's really late now and I prob won't be able to be in school this weekend to make more videos. But the way to do that is, since t^3 and 4t^4 are linearly independent, thus those two piecewise functions are overall linearly independent.
@blackpenredpen
@blackpenredpen 7 жыл бұрын
Perhaps you have a theorem like this in the book, which says if W(f,g) is not zero at some x_0 on the interval I, then f and g are linearly independent on I
@blackpenredpen
@blackpenredpen 7 жыл бұрын
Thus u can show that W(x^3,4x^4) is not zero on (0 to inf) thus f and g are L.I.
@user-nl7mn4rr6s
@user-nl7mn4rr6s 5 жыл бұрын
我覺得右邊的寫法有點讓誤解:第一條式子並不需要大於等於零,零只是一般來說方便驗證,只要是有限大的數就可以。第二條式子小於零也可以類似地用,只是不等式方向要相反。與第一式相同地,這也不必需是零。
@elixiroflife9636
@elixiroflife9636 3 жыл бұрын
mu test will be much easier
@parthasarker6121
@parthasarker6121 7 жыл бұрын
Well, you can leave out some details which are obvious in the process
Innocent looking, but ????
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