Complex Numbers (How to find the nth root) : ExamSolutions Maths Video Tutorials

SIGN UP FOR NOW FOR A 30-DAY FREE TRIAL
www.examsoluti...
PREDICTIVE GRADES PLATFORM IS HERE 🚀
☑️ FREE ExamSolutions AI personal tutor
☑️ Accurate grade predictions
☑️ Personalised resources and tuition
☑️ Guaranteed results or get your money back
ENQUIRIES AT:[e-mail]
Tutorial on finding the nth root when dealing with complex numbers.
KZbin CHANNEL at / examsolutions
EXAMSOLUTIONS WEBSITE at www.examsoluti... where you will have access to all playlists covering pure maths, statistics and mechanics.
/ examsolutions.net
NEW INSTAGRAM: / examsolutionsguy
TWITTER: / examsolutions and others on complex numbers and de Moivre's theorem
THE BEST THANK YOU: www.examsoluti...

[@kennys3095]

For 1st Quad arg = Theta ------2nd Quad arg = Pi - Theta ------3rd Quad arg = Theta - Pi ------4th Quad arg = -(Theta) We have to consider different arguements for diff quads. In this case our theta was in 3rd quadrant so we used theta - pi which resulted in -5pi/6 .

[@saadafm]

you beautiful human

[@factgirl147]

You helped me out.... thank buddy

[@viviannesogomo5182]

thankyouuu

[@ebhojayejuliet9728]

Thanks so much this write up was more useful than the video

[@lwazilubisi3810]

Thanks a lot! I've been wondering why he did that cause the Arg was already between -pi & pi at first, Again Thanks!

[@sakiiimouse]

thank you so much, you've made me actually understand complex numbers, and they're no longer complex to me

[@ExamSolutions_Maths]

Just start with k=0, then k=1 and so on. You don't really need to do k=-1 etc as k=1, k=2, k=3 etc will start to repeat the roots eventually.

[@jacktaylor2877]

how is the angle (5pi / 6) if both terms on complex # are negative? Should it not be in the 3rd quadrant ?

[@trkingdavid4943]

i like how you interpret question

[@pignbird4007]

life saver!

[@sjdjfksl]

Is there a range for theta because in exam questions they always add pi if the initial theta value is negative

[@ankitsinha4933]

great method of teaching... awsm clearity of complex concepts !!! thnx

[@ExamSolutions_Maths]

You're welcome.

[@dreamlanddon]

thank you so much teacher... your lecture helped me at exact 1 hour before my calculus exam...

[@zanacs7393]

@@tuneese2561 rah

[@jacksonferris-choi1739]

in the last line of working where did the power of 1/4 go for the trig part go ?

[@ExamSolutions_Maths]

For this type, yes.

[@Elkycreates]

Brilliant!

[@FadiAlHazim]

This is one of the best videos ever! keep the good work and please never stop making those, i feel that am really learning with you!

[@siwipenny6870]

sorry sir, how to find value of k that we use?

[@mdjahin99]

Thanks a ton Sir!

[@ExamSolutions_Maths]

You are always welcome.

[@kojolino2401]

how did u get the 1over 4 for the n?

[@ofmice6577]

Because we are finding z to the power of 4

[@RichieVillan]

In my text book they work in polar form, is this method easier?

[@ExamSolutions_Maths]

Cool

[@thantyarzarhein5459]

8:52 - reason why not k = 3, it 31pi/24 which exceeds pi radient. Which is why it took -1

[@franketanhongda7543]

Why do we need to include the 2kπ?

[@ExamSolutions_Maths]

It should be an integer. Your answers could well be fluky.

[@mramtakujasambaaguy6681]

good lecture

[@user-le3oy9gd2f]

9:45 why does theta have to be less than pi?

[@Mexicomonster25]

do you have a video for drawing shapes with more than 3 vertices on youtube, I don't know how I would go about it!

[@ExamSolutions_Maths]

Sorry, no.

[@aashsyed1277]

@@ExamSolutions_Maths :(

[@brunosilvaneri]

what do you mean by " 31pi/24 exceeds pie radian"? thanks

[@RichieVillan]

+Brunin G3 neri Pi radian = 180 degrees. He is just saying that 31/24pi is bigger than 24/24pi. (The angle is bigger than 180 degrees, going anticlockwise from the x axis). As the range of the principle argument is 0 to pi then 31/24pi exceeds the range we want

[@mathsgreek]

is it a trick to know with which values of k i must start? thanks really apprieciated ;p

[@anuragsuresh5867]

oller bin You definitely won’t find this useful now but for other viewers, I’m pretty sure you start from 0 and go to a k value 1 less than the power of z

[@paris293]

Anurag Reggie ooo thank you

[@AllanLovezGaming]

Oller bin how did your exams go?

[@VipWeerasooriya]

Sir, Can we use seven pi upon six instead of - five pi upon six?

[@kojolino2401]

i also had 7 pi on 6 and iwas doubting

[@michaelechutem995]

I was wondering too

[@DanielSegripuo]

How did you get the -5pi/6

[@LindokuhleMazeka]

I want to know too

[@mohammadalaminsiam711]

BEST

[@adamdesmit776]

Are you god?

[@ExamSolutions_Maths]

Hardly!

[@rordongamsey3057]

@@ExamSolutions_Maths lol I love you so much.

[@booyah7394]

So what's the final answer? Sorry if this is a dumb question

[@ExamSolutions_Maths]

The solutions are the different values of Z when k =-1,0,1,2

[@MrMoeqt]

Is this FP1 or FP2/3??

[@ExamSolutions_Maths]

+Moezph. Depends on what board you are doing.

[@MrMoeqt]

+ExamSolutions I checked your website, it's edexcel FP2. I'm studying FP1 this year. Great videos sir!

[@ExamSolutions_Maths]

+Moezph. Okay - good luck

[@zionsinkala9856]

how come tan inverse of 8/8.root 3 gives you -5pai/6 in the third quad ,am confused you made a mistake

[@ExamSolutions_Maths]

Based on the complex number, we landed in the 3rd quadrant. As mentioned in the video, the Arg Z must be between -pi and pi radians, so you need to find the angle from the positive Re axis, to the reference line (red line) by turning in a clockwise direction (giving a negative angle). As we found the acute angle to be pi/6, we got 5pi/6 by doing pi - pi/6.

[@fatfrankthepeteacher36]

@@ExamSolutions_Maths cool story bro

[@user-vz2qw7ur4x]

How k = -1 ?

[@justaracoonchillinginatoilet69]

Rewatching this again for uni

[@Anyone10M]

Urdu me

[@Anyone10M]

Speaking urdu

[@ebhojayejuliet9728]

Your lectures are veey useless sir very hard and u dont 3xplain how you get values you just write them out if we know then we qont be here obviously all the comments is someone confused pls do better

[@lumosss]

Complex numbers? More like simple numbers. :)

[@abhijeetkumar2099]

speaking for Hindi