Compound Interest Formula Explained, Investment, Monthly & Continuously, Word Problems, Algebra

This algebra & precalculus video tutorial explains how to use the compound interest formula to solve investment word problems.
Logarithms - Free Formula Sheet: bit.ly/4fEwqv0
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Logarithms - The Easy Way!
• Logarithms - The Easy ...
Log to Exponential Form:
• Writing Logarithmic Eq...
Change of Base Formula:
• Change of Base Formula...
Change of Base Log Problem:
• Logarithms
Properties of Logarithms:
• Properties of Logarithms
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Expanding Logarithmic Expressions:
• Expanding Logarithmic ...
Condensing Logarithmic Expressions:
• Condensing Logarithmic...
Natural Logarithms:
• Natural Logarithms
Solving Exponential Equations:
• Solving Exponential Eq...
Exponential Equations - Quadratic Form:
• Solving Exponential Eq...
_______________________________________
Solving Logarithmic Equations:
• Solving Logarithmic Eq...
Graphing Logarithmic Functions:
• Graphing Logarithmic F...
Graphing Exponential Functions:
• How To Graph Exponenti...
Compound Interest Word Problems:
• Compound Interest
Logarithms Practice Problems:
• Logarithms - Practice ...
_______________________________________
Final Exams and Video Playlists:
www.video-tuto...
Full-Length Videos and Worksheets:
/ collections

[@TheOrganicChemistryTutor]

Logarithms - Free Formula Sheet: bit.ly/4fEwqv0 Final Exams and Video Playlists: www.video-tutor.net/ Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections Next Video: kzbin.info/www/bejne/oWWvfZd8e7GFo7M

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​@@sanopann1896 you need to put 1.0066667 into the calculator and put the exponent 480 (its basically raise to the power of 480) and you'll get the result of 485, 467.79.

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@4:42 On your first problem with P=20,000 Int 0.08 time = 40 yrs n = 12 (compounded Monthly) A = $485,467.71 Not $485,467.79 A Spreadsheet is the better tool rather than a calculator because you can easily make a table With N = 1, 4, 12, and 365 and also add the Continuous Compounding for a Column of its own to see A increase as N increases. Good Explanations all in all. Grade A for you video.

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The annual force of interest at time 't' given by ∆(t)=a-b^0.2t, where 'a' & 'b' are constants.Given that an initial investment of £100 at time 0 accumulates to £140 after 5 years and £180 after 10 years, find 'a' &'b'. I need help with this question 🙏

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