Solving Logarithmic Equations With Different Bases - Algebra 2 & Precalculus

[@TheOrganicChemistryTutor]

Logarithms - Free Formula Sheet: bit.ly/4fEwqv0 Final Exams and Video Playlists: www.video-tutor.net/ Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections Next Video: kzbin.info/www/bejne/bHTViXmsq9yml6c

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Can we swap brains just for this upcoming test???

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I call dibs first!

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Please

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i left this video feeling like a math genius, then i opened my assignment question. i cried

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same

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You really saved me. Made me cry when I solved the answer on my own and got it. Thanks a lot

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Ur wired

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[@georgesadler7830]

MR. Organic Chemistry Tutor, thank you for Explaining and Solving Logarithmic Equations with Different Bases. Understanding logarithm is very important in all levels of math, engineering, physics, chemistry and all the Enviromental's sciences.

[@wistfulgraph]

At 24:58, by skipping over the "non-factorable" quadratic, you skip over a solution which isn't extraneous (because it is a real quadratic and one of the answers fits in the domain necessary for log2(x+3)+log4(5-x)=3. The domain is -3 x>-3 ..... 5-x>0 --> x

[@The_InsideJoke]

Brain hurty

[@morganblarue]

Exactly! I didn’t run through the math like you did, but we did leave out another two possible solutions for x (one being negative, so not a solution).

[@michaels333]

Came here for this comment. On the previous problem the quadratic gave complex roots - not the case here

[@KungFuBarbie-pc7hb]

Where'd you get the 1 solution from

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first time I watched a 32 min math video and not get bored. payed more attention here than in MY CLASS

[@thomassidoti5496]

On that problem ending at 24:36 x=1 is a solution and x=-1+2radical(5) is also a solution. If you did the quadratic equation at the end you would have arrived at that. 1-2radical(5) however, is not a solution because it is not in the domain

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You are a genius man had difficulty in this particular concept and you cleared all ky doubts

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His math tutorials is therapeutic for me.

[@miinjung]

example - 0:37 ✓ one - 1:49 ✓ two - 14:06 three - 16:45 four - 24:49

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I used to find it so hard to change bases in secondary school, but now that I'm in college, plus this video, it's a walk over

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Beautiful...I've gotten back this log wahala solved through this tutorial. Thanks.

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I’m in middle school and I’m taking geometry rn but I figured that if I learned stuff like this I’ll be prepared for the future

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yep finals are hell, definitely helps to be prepared

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same here too!

[@elebeonupeter1477]

Thank you, this was very helpful in refreshing what I had forgotten.

[@PaleBlueDotCitizen]

@23:37 you stick with x=1 and say there are no other zeros but the quadratic x^2+2x-19 can be solved by completing the square to get x = -1 +/- 2 sqrt 5.

[@krishhhprj]

Nerd jk I’m not that guy

[@satyamrai1220]

keep up the good work for all the students looking forward to learning mathematics in much comfortable manner

[@renewd]

These are lengthy and involved compared to some other logarithm problems, but a good challenge.

[@AnilKumar-lv6yf]

Finally helped me to undestand *LOGARITHM* Thanks a lot😊😊

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the way everything just links is amazing....i love math...its like an alien language

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you deserve a special spot in heaven. This was amazing thank you :)

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The struggles of IB maths r real!!!

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Almostutorials sameee my teacher literally sucks at teaching

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@@ilhanyusuf2160 Same here, we sped through this unit so fast and whenever I ask a question she always gives me a hard time

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i thought this was taught in myp??

[@anrajsoni2596]

Auro R'G SAME.

[@yina6816]

@ 21:55 Where (and why) did the multiply both sides with negative one come from?

[@rumanmdhasan6224]

Great video,brother! Those maths seam really easy now!

[@ZakiAsir]

You are the saint of all students

[@laurenorourke2442]

Thank you thank you thank you!! I have an algebra 2 quiz tomorrow and i don't understand logarithmic nor exponential equations, so this was really helpful!! Im praying I do well on my quiz tomorrow

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How did you do? You don’t probably remember since it was 1 year ago!

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@@simonbawi21 i think i actually remember!! i think i got a low A😅 i lowkey miss algebra 2, pre calc kicked my ass last year:(

[@simonbawi21]

@@laurenorourke2442 Thats very good to hear, I'm taking applied calculus in college so I'm just getting help since I don't really learn from lecture.

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You always help me with my maths, thank u so much

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This is wonderful and easy to capture the method

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OMG I have been failing such kind of question when they come on a test ,but I can't believe that I have known how to solve them

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So comprehensible yet so mind boggling

[@shawnclifford]

I solved 18:40 by log_2(x+3) + log_4(5-x) = 3 log_2(x+3) + ½log_2(5-x) = log_2(8) log_2(x+3) + log_2(5-x)^½ = log_2(8) (x+3) + (5-x)^½ = 8 (5-x)^½ = -x-3+8 [(5-x)^½]² = (5-x)² 5-x = x²-10x+25 x²-10x+x+25-5 = 0 x²-9x+20 = 0 (x-5)(x-4) = 0 substitute for x = 5 log_2(x+3) + log_4(5-x) = 3 log_2(5+3) + log_4(5-5) = 3 log_2(8) + log_4(0) = 3 log_4(0) is undefined, hence x=5 is not a solution for x = 4 log_2(x+3) + log_4(5-4) = 3 log_2(4+3) + log_4(5-4) = 3 It's wrong tho omg

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but how does line 2 work?

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[@roccomelodino4347]

At 22:04 can you explain why you times it by -1 please

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Perfectly done thank you sir

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Thanks allot at least you have shared your ( maths) knowledge with me

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120 people unliking this . 😑😑 ok they dont even know what is log 😰😩 this was really helpfull and ots for free

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man thanks brother you seriously help a lot keep doing what you do bro!!!!

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lmao i love how he just ends the video after the lesson

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U wanted him to rap before ending them or smt ? Lol

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No question this guy is a genius

[@Ioa_kun]

3:52 why did you multiply the right side by 1/3? By the way, you really helped me a lot to catch up in classes, Thanks

[@accensa]

Late to this but division can be defined in terms of multiplication; it's essentially the inverse version of the operation (multiplying by the denominator). Log3(4x + 7)/3 is the same as 1/3[log3(4x +7)]. When you distribute 1/3 it becomes Log3(4x + 7)/3. The reason why he chose to multiply by 1/3 is so that you can make it an exponent for the log as he explained it.

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Kudos to your effort sir.

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man u saved me before my test

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I have an exam today, thanks.

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Lets assume we have 45 seconds to solve this? How do we get there this quick?

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You don't

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Just guess

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Me and my friend are in 6th grade and still love your log,factorials,ln,and algebra vids

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Thanks m8, I really needed that

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have you done a video on solving to x when you have mixed equations of exponentials or logs and normal binomials?

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Man you are a savior

[@thomassidoti5496]

Love your videos! in the 2nd to last problem, why aren't 3.472 and -5.472 solutions to the equation? They work out when plugged into the original equation

[@thomassidoti5496]

3.472 is but not -5.472 because it is not in the domain

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Best ❤🎉

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when he said two is a factor of 15 by accident I lowkey panicked. ;P

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Thank you very much Sir..

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When your teacher assigns only 4 problems and you think it won’t take long buts it’s already midnight

[@kingmonpillay9844]

🙏🏽 You're a Math 👼

[@carlmina4287]

4:01 pls explain it to me further on how it became 1/3

[@MrBoston2512]

I know this is a late reply, but he is just simplifying the problem. Dividing by 3 is the same as multiplying by 1/3. An example of this would be 3/3. If you divide 3/3=1; if you multiply 3(1/3) [i.e. 3/1(1/3)] you will also get 1.

[@themoon51]

@@MrBoston2512 @4:59, could you explain why we raise both sides to the 3rd power?

[@MrBoston2512]

@@themoon51 Sure thing. So again, he is trying to simplify the problem (4x + 7)^(1/3) is gnarly. So, in order to get rid of the 1/3, he raises both sides to the third power (he has to do both sides since both of the equations are equal to each other). In doing so, you cancel the 1/3-->(1/3*3/1=1 bc of the exponent rules you multiply two exponents if one is raised to the other), and anything to the ^1 is just that value. You are left with the (x-2)^3=(4x+7), which is much easier to solve.

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You just saved a life

[@nathanmofya3866]

How can I solve an equation for this sort; 3×10^3+2×10^x+5×10^y=3002.05

[@programmingbezaleel]

Thank you so much.

[@AdityaShinde_11]

Wonderful #DefinationsForStudents

[@zeph8620]

Can we just exchange everything with Euler's number and use natural log?

[@sharonann3259]

rombe nandri ya🙏

[@atharvsingh3185]

Thanks it really helped .....

[@mrannunaki6852]

in the first problem.. after you've changed the bases to logbase3 on both sides can you just cross multiply and solve? cuz its then (logbase3 (x-2)/1) = (logbase3 (4x+7)/3) so.. that = 4x+7 = 3x-6 Then x = -13

[@simkuntheng5465]

help me do this one logbase 2 of 2/5=...? logbase 2 of 3/5=...? Thanks!

[@alexcarter7317]

But the you'll have a negative log value so it won't work.. kinda late but worth mentioning for other readers

[@rolexbigsmoke7613]

16:53 wait holdup what's the police doing here.

[@theengineeringstudent2678]

So interesting!

[@MegaAgiri]

How do you do If one Base is x and The other one is 2. I cant find a video example of this kind of problem. Log2(x)-8logx(1/4)=8

[@CrimsonBlade39]

use

[@teaaaaa1691]

THANK YOUUU!!

[@myzahra4029]

that's helpful , thank you

[@LuisMartinez-ly8xd]

where did you got the -1 to multiply into 0= -xCubed - xSquared + 21x - 19(towards the end of the third question)???

[@LuisMartinez-ly8xd]

time's at 21:48/32:42

[@PHILLYMEDIC69]

we dont know man.

[@serinacat4781]

Very helpful thanks haha

[@beverlyfrancis8433]

Thank you.

[@Airborneworms]

where are you getting a third from?

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ILY LIFE SAVER

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make video on log table

[@TheOrganicChemistryTutor]

This video might be helpful: kzbin.info/www/bejne/goPFmpKmgr1keq8

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Real good

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Can I send a question basing on the topic

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Puñeta ang hirap , btw thanks a lot💖

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hahaha