Concavity, Inflection Points, Increasing Decreasing, First & Second Derivative - Calculus

[@TheOrganicChemistryTutor]

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When finding the derivative (2nd) of f(x) = 4x(x^2 - 1), it is easier to expand the function to 4x^3 - 4x instead of using the product rule.

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Can I clarify if x= 0 is an inflection point at 54:04? Since you mentioned that inflection points have a f''(x) of 0, but at x=0, f''(x) is undefined.

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Ok makes much more send now on the use of finding second derivative. I didn’t understand why I even needed it if I can find the max/min with first derivative test.. but now I understand that finding the second derivative and the the zeros and making a sign diagram gives me the inflection points. Thank you

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