Conservation of Momentum In Two Dimensions - 2D Elastic & Inelastic Collisions - Physics Problems

[@TheOrganicChemistryTutor]

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[@adelgamer1684]

Hi. I have a really important question about this video and I would be really grateful if someone could help me! From what I know, when a ball hits a ball with the condition that the vector of the collision is pointing from the center of the first ball to the center of the second one, than the direction if the ball, which is being hit, would be the same as the direction of first ball, because as mentioned, it is a “center to center” collision. So I come to the conclusion that the case that is described in this video is possible, if the collision vector is not pointing at center of the second ball and so, we get different angles of the 2 balls, telling us the exact direction of each one. Am I missing something, or did I catch this right. 2. Question (I am really sorry😅) If we have a different scenario, where you have to calculate the angles of the 2 balls after the collision, do the speed of the balls after the collision have to be constant? For example in air-hockey, the speeds are not constant because of low friction. So do I necessarily get different angles based on inconstant speeds? This is important for a project, so it really would help a lot if someone would help me…Thanks to you all!

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[@gabrielpetta3001]

This exact video saved my physics lab, no other examples I could find had two unknowns. Thank you so much!

[@mbrentharris]

You are probably one of the most brilliant of persons, that I have watched on KZbin. Thank you for your videos, I have learnt a lot!

[@TM-tj7ou]

ive been having trouble with 2d momentum for so long but now its a lot clearer.......thanks a bunch!

[@Ukrainian-22]

Initial Ek (M1) = mv^2/2 = 5*6*6/2 = 90J Final Ek (M1+M2) = M1V1^2/2 + M2V2^2/2 = 5*5.196*5.196/2 + 3*4.99*4.99/2 = 67.49 + 37.35 = 104.84J Final Ek- Initial Ek - 104.84J - 90J = +14.84J - 💪Free energy 💪

[@kumudupremarathne1453]

I've watched many of ur videos related to physics. When I am cramming in the last minutes before the exam ur explanations are vital.I am really thankful ur lit af. IF U R LOOKING UP IN THE COMMENT SECTION BEFORE WATCHING THE VIDEO..TRUST ME THIS IS WORTH SPENDING UR TIME.. 👍 this comment if u think it's true

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[@moonbunnies5216]

You learn this at your 6th grade????! This is in my diploma course what country are you from omg

[@blazar5701]

Lol, yeah, I am in US, we were learning about basic motion in physics but I wanted to go a bit further in depth so I could understand everything that was taught, and also for extra knowledge in the future. But I'm sure this type of physics is taught throughout highschool and college, something that is very important so it is repeated.

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EXACTLY MY TEACHER DOES NOT KNOW HOW TO EXPLAIN SHIT ITS SO ANNOYING

[@chaeairsoft]

what if they do not give you an angle for the 3kg ball at rest, only for the initial ball?

[@connorking1386]

Hello I have loved your videos ever since I was a little undergrad. I did notice if you take your final velocities and plug them into the kinetic energy formula, energy is gained. Could you explain this?

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I swear if he was my physics prof I would attend all of his lectures

[@Awai_quotes]

Faxx

[@dragcraftmaster7]

Super well explained thank you

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[@MrGallinavoladora]

This is just what I was looking for! Thank you so much!!!!

[@Winter_B12]

Im my book the give you the initial velocities and a final speed of one of them and ask for the angles and the final velicity of the other one and calculators ARE NOT allowed and im losing my sanity trying to calculate and solve the equation because they have sin and cos all over the place How do i get around that

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[@kangmingu7995]

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[@adelgamer1684]

Hi. I have a really important question about this video and I would be really grateful if someone could help me! From what I know, when a ball hits a ball with the condition that the vector of the collision is pointing from the center of the first ball to the center of the second one, than the direction if the ball, which is being hit, would be the same as the direction of first ball, because as mentioned, it is a “center to center” collision. So I come to the conclusion that the case that is described in this video is possible, if the collision vector is not pointing at center of the second ball and so, we get different angles of the 2 balls, telling us the exact direction of each one. Am I missing something, or did I catch this right. 2. Question (I am really sorry😅) If we have a different scenario, where you have to calculate the angles of the 2 balls after the collision, do the speed of the balls after the collision have to be constant? For example in air-hockey, the speeds are not constant because of low friction. So do I necessarily get different angles based on inconstant speeds? This is important for a project, so it really would help a lot if someone would help me…Thanks to you all!

[@paulsabatino625]

Very clear explanation, but I do see a problem with your example. You show the balls moving at right angles to each other after the collision. This is not possible when the masses are unequal. If you calculate the kinetic energy before and after the collision, you'll find that the kinetic energy is greater after the collision. This is impossible, even for an inelastic collision.

[@PedroLopez-jv2yv]

No one seems to have pointed this out. There's more energy after than before.

[@gprofisfreddymul]

How do you calculate the collision number? Why are the results negative? Please explain.

[@studyingd5565]

3:30, in here if we write 30 degrees above the x axis is it cos 30?

[@rganaiktasl9482]

Very well explanatory.. love it... soli kela❣❤✍✍

[@jasstan180]

What if it’s the other way around. And you’re looking for the angle and final Velocity? Only. I’m talking about an inelastic collision where they stick together in the end. I don’t know if this makes sense to anybody

[@sugar4936]

so where is the inelastic collision problem at?

[@mindwipe0074]

I know u prob dont care anymore but if the problem states that its an inelastic collision do this and if its an elastic collision then u can do this too but u should just keep in mind that the kinetic energy is conserved, just in case ur teacher decides he wants to make his student's lives more miserable and gives u another variable to solve. KEi = KEf

[@Ishaan35]

Elastic : kinetic energy and momentum conserved Inelastic: Only momentum is conserved

[@cristondingding1038]

Thank you for the tutorial. Hope for more:))

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[@Stat1onary]

Perfect thanks. Great as always.

[@coreyb8080]

Im in 5th grade and really benefitted from this video! Maybe some more challenging problems would be better however I solved this faster than I pressed start to the video.

[@WyattXD]

damn bro

[@MariePeters11]

Amazing video, Sir! However, I have a question @5:24: Shouldn't V1y' = -V1*sin(-30deg)? I thought we also have to carry the sign of the direction of the component. Thank you in advance :)

[@vm8856]

He is, the direction is 30 degrees so he's making that part negative

[@exodus58]

the final speed in x and y direction must be different for momentum to be conserved?

[@adrianneadonis7401]

Thanks so much 👍🏻😊

[@dominicpakula7813]

What if you are only given one angle and one speed vector? This doesn't work in that case

[@ThatWasherNerd]

5:37 Someone is angry behind the wheel

[@gartyqam]

i dont get it. how is he angry

[@ThatWasherNerd]

@@gartyqam If you listen carefully, you can hear a long horn honk

[@gartyqam]

@@ThatWasherNerd oh i didnt even realize dat haha until i listen VERY CLOSELY D:

[@dhanalakshmik2226]

@@gartyqam so u listened on the horn not on the lecture lmaoo😂🤣

[@Song-ub9rk]

why is m1v1x' -ve (why cos(-30) ), isn't the horizontal component pointing to the right?

[@jeewoo7195]

yes, and cos(-30) = cos(30), as in they're both positive

[@lethbophilip6365]

Lot appreciation ❤❤

[@lenael4747]

This guy is awesome ❤️

[@rysonwell5071]

Tq it was help me a lot

[@hopeworld4247]

If you don't mind senpai, can you make another video about collision in 2D? I want to practice solving more 🥺

[@HaHa_HaHub]

At 5:38 it sounds like there was a collision outside 😹☠️

[@jimhahn2665]

There's a clear error in the derivation. Look at KE before and after. KE before = (1/2) * 5 * 6^2 = 90 KE after = (1/2)*5*(5.2)^2 + (1/2)*3*5^2 = 67.6 + 37.5 = 105.1 KE cannot be greater! Also, a commenter said that the degree total was 90 and that could not be, because the masses were not equal. Well, I don't think so. If the angles total to 90, then the collision is elastic irrespective of the masses.

[@jimhahn2665]

I was wrong, and therein lies the problem. The angles total 90 ONLY if the masses are equal. These masses are not equal so therefore the angle total cannot be 90. So the problem is overspecified. The only way to solve it is to put extra KE in, which is kinda illegal. No? Cos(theta+tau) = (v2/2*v1) * (m1^2 - m2^2)/(m1*m1) The classic elastic m1=m2 case results in cos(theta+tau) = 0 which requires theta+tau = 90degrees.

[@daveschorrtube]

Yeah, he shouldn't have said that the collision was elastic.

[@hectorgrand3214]

I dont get how you can sub in the y value with the x value, towards 7min. Plz somebody explain 😭😭

[@jesusmrosario-claudio4104]

Thank you once again.

[@ernestdaka7825]

Asante sana

[@Jaseinatl]

I followed you, but the problem is that you are giving us the angles to start with. How can we determine what angles the two objects go off at? In other words, in the real world, you have a 6kg object hit a stationary 5kg object going 6km/hr, how do I determine the 60/-30 angle split?

[@helpontheway7856]

Much love brother

[@hajranaidoo9037]

Love this!!

[@BatyhileleLamla]

Thank you so much sir

[@ExcitedGiraffes-zt1qc]

You are a king

[@TroubleWoe]

It’s not -30 degrees for the x component for v1. Its moving to the right so it should be 30 degrees positive

[@granthqweqw5244]

It is moving down though so It would be -30° if we think of it like we do in the video

[@subhan12340]

Cos(-x) =Cosx so it doesn't matter anyway

[@medotedo8410]

But when I am substituting values to verify the conservation of momentum the answers are not the same !

[@Bangpink_vibes]

Thanks a lot sir

[@nataliabacic]

Can someone explain to me why sometimes we use p^2/2m and sometimes 1/2mv^2 in the formulas?

[@karishmasawhney21]

Hey. p=mv In the equation 1/2mv2 if we multiply the numerator and denominator by “m” it becomes m2v2/2m..Put p2 in place of m2v2 as mentioned in the first line! Hope it helps

[@fahimal-huq6867]

THANKS A LOT

[@roknagor]

how do you solve it when only one of the degrees is given though :(

[@machbooks]

Kahn Academy has that version

[@dauthuc8807]

Love you dear you are so good

[@Hercrati]

For the end answer, is it bad that you got one positive and the other to be negative?

[@Sir_Isaac_Newton_]

youre not smart are you

[@malikandrew8887]

Hi I'm malik Andrew from Nigeria I have a little problem on momentum and impulse

[@fatihahwahida8123]

thank you sir

[@samfogelson2050]

Why does he use Cosine and sine?

[@raadavijithalimurtaza951]

why is it cos?

[@natnaelendalkachew8458]

Not all heroes wear capes like fr im barley hanging on with wht my teacher teaches me but you damnn

[@AbdifanoKebato]

It is solution for freshman for long periods

[@betul-ev2fu]

*TYSM!!!!!!*

[@sdjdavies42]

Thank you

[@davidalacabo4298]

Is this elastic or inelastic collisions?

[@jungiejg]

what does prime means?

[@reynolddlm]

Jungie Cual prime means final, i guess

[@deborahdouglas682]

final

[@LJ-ml7oz]

its just something you put to differentiate initial from the ones after. its like a marker.

[@machbooks]

means after a change, two primes would be after two changes

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Why are you better than my tutor it’s annoying

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DUDE I LOVE YOY

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Legacy ❤❤❤

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god bless u

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You sound like Billy Russo from the Punisher

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he doesnt.

[@aryajoshi8069]

goated man

[@tomasmenchaca1903]

Am I the only one that heard the car alarm at 5:38?

[@fahadkhaled5056]

Love you

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Bravo sir, bravo

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sos god chabon

[@XhianFadah]

Machine 🎉

[@darkslayer5558]

GOAT

[@Rad6866]

he made a mistake at 7:01 when isolating for V2, V1' should be 10.39 not 5.196

[@victorzoma2749]

You are poor!

[@kidxclusive]

You might want to try that again. Think about it. If 30/5 =6, 30 divided by anything greater than 5 (5.77) isn't going to give you anything close to 10.

[@iliekmathphysics]

Radmehr Abdolahi I made the mistake you made too, I’m guessing you used positive angle degrees like 60° and 30°, but you were supposed to use angles such as 60° and -30°

[@vedulabs766]

Look at Virtual Laboratory (3d real time WebGL) about Momentum Conservation (absolutely elastic collision in particular) in mechanics at vedulabs.com/

[@dulinadissanayake7560]

Its easier to solve it without calculating decimals

[@abdultarar1408]

Very difficult to understand 😢