Convolution by Image Method: Detailed Approach in Signals and Systems

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[@fffooccc9801]

aapne t tao aur 2 sab confuse kr diya

[@vakhariyajay2224]

Thank you very much. You are a genius.

[@kanaknautiyal6824]

Can you explain what you have done at last?? How the convolution become 3^(-3£) *u(t-2) As graph of u(t-2) start from 2 to infinity But we are taking interval between 0-2

[@1587nirjhar]

i have observed that in last 55 videos that you have not responded to comments where students have noticed some error in the solution. kindly clarify doubts in the comments section.

[@1587nirjhar]

x(t) = e^-3tau u(tau) then how come y(t) = e^-3tau u(t-2)? tau has changed to t. please clarify what will be the exact value of y(t) because in the second last graph you wrote tau first and then scribbled it to t.

[@CodeTillEternity]

tum sirf bhai bhida rahe ho , concept se nahi kar rahe