COUNTDOWN to 2025:13 Integrals in 13 Days! Weierstrass Sub ∫ 1 /(3-2sinx) dx | Math with Professor V

[@siyabongashoba9901]

Weierstrass Sub is a powerful tool indeed thank you so much Prof.V really gain a new tool in my toolbox 😊

[@mathwithprofessorv]

I am so glad you are finding it helpful! 😊

[@punditgi]

Happy holidays! ❤🎉😊

[@mathwithprofessorv]

Happy holidays to you too! 😄

[@tony413chow]

Hi Professor V, I learned this method from the other video and tried to solve it. It worked and got the same result. Cheers.

[@mathwithprofessorv]

Awesome job!!! It’s so satisfying when you can apply those skills to a new problem, great work! 😊

[@tonybluefor]

It took me quite a time to solve this integral. I have a feeling your 13 integrals look like the 12 (+1) labours of Heracles😁, so I expect there will be one (+1) that is much easier😄. Anyway I like them🤩

[@mathwithprofessorv]

Haha! You’re right, some of them are more challenging than others! I’m glad you’re enjoying this series. ☺️

[@armanavagyan1876]

THRILLED to watch THESE VIDEOS ARMENIA needs more like U🇦🇲❤

[@mathwithprofessorv]

☺️☺️☺️🇦🇲🇦🇲🇦🇲

[@ryanrasco2354]

Please tell me I won’t need this for dif eq😭 love the video! These are very helpful!

[@mathwithprofessorv]

Haha! You never know in differential equations but it’s HIGHLY unlikely. Either way; hopefully these videos will give you a leg up! 😉

[@avielabc604]

I didn't notice the arctan integral when I solved it myself I went stright to trig sub after completing the square 😂😂🤦‍♂️

[@mathwithprofessorv]

😂😂 I had a student years ago in Calc 2 who always used trig sub any chance, even if it took longer, he loved it so much! It happens sometimes when you’re deep in the zone of integrating. 😉

[@siyabongashoba9901]

Dear Prof.V I hope you are doing well. Yeah, this is extremely hard. I timed by 1= (3+2sinx)/(3+2sinx) and got two integrals. One was the integral of 2sin(x)/(5 + 4cos^2(x) ) which was easy to solve, but the second one is integral of 3/(5 + 4cos^2(x) ) which is very hard to solve. Oh, please help. let me check the video then.

[@darkmask4767]

for 3*int(dx/(5+4cos²x), multiply numerator and denominator by csc²x. This gives 3*int(csc²x/(4cot²(x)+5))dx = ¾*int(csc²x/(cot²(x)+5/4)) dx. At this point, the integral can be solved by substitution.

[@siyabongashoba9901]

@@darkmask4767 Thank you so much.

[@siyabongashoba9901]

🙏