Derivation of expression for work done in an isothermal process (class 11 physics - thermodynamics)

[@mnmadape3252]

The best explaination I've ever came across!! You're the best. Thankyou sir!

[@sharathgoresir]

You're welcome 🙏

[@adityagalande6529]

The best sir I have ever learned from Keep it up sir jiii

[@RavinderSingh-ye4jo]

Thank you sir tomorrow is my exam you helped a lot

[@SHUBHKARMANJITKAUR]

Amazing explanation ❤

[@AMMU-rd3bw]

tqsm sir 😊

[@_Craftideas]

Amazing 🤩 Sir❤

[@navjotsingh27145]

Thank you so much 🙏🙏

[@BepinIndana-u3v]

As it is expansion, the value should a negative value so just add a minus in front of it!, Awesome Lecture! :)

[@pranav1502]

that is only in chemistry since work done by the object is -ve in chem,but in phy work done by object is +ve

[@BepinIndana-u3v]

Oh Okay, Thanks! @@pranav1502

[@ayesizagerald8034]

Thanks

[@RavinderSingh-ye4jo]

Sir but there is no negative sign in this expression but in book negative sign is given

[@sharathgoresir]

Check for position of V2 and v1 If V1 is in the numerator the negative sign will come

[@RavinderSingh-ye4jo]

@@sharathgoresir ok thank you sir

[@MESSI-IS-THE-GOAT610]

Sir to be more Work done = Force × distance dw = F ×dl dw = P × a × dl. {•P =F/a} dw. = P ×dv then do the integration

[@prasad5375]

Good explanation bro

[@mansi4479]

This is perfect ✨

[@sharathgoresir]

Thank you 😊

[@DavidEssien-nn7qb]

You're a great teacher sir. I love your video ❤❤

[@sharathgoresir]

@@DavidEssien-nn7qb thank you very much 🙏🏻

[@aishafarzana4396]

Thank you sir you are the best😙

[@sharathgoresir]

You're welcome

[@anamikadebnath6455]

Derive an expression for isothermal mixing of ideal gases.. Is the answer is same?

[@sharathgoresir]

No

[@i-Sensei-XII]

Grt explanation sir

[@sadanand2575]

👍👍

[@RohithGowda-qd9rq]

Sir your teaching is good and i can sucess plz you can expln plz stand side

[@snehabaruah4224]

Thank u sir

[@sharathgoresir]

You're welcome 😊

[@piyushsahu1170]

Thank you sir ❤️❤️

[@sharathgoresir]

You're welcome

[@simonjain143]

Nice explanation ☺

[@sharathgoresir]

Thank you 😊

[@parthivk4310]

❤

[@TheChemEng-guy]

Nice one sir but since the gas is undergoing expansion, how how is the work done positive instead of negative?

[@Arya56737]

thank you

[@babarrrr426]

Easiest way you have done it

[@sharathgoresir]

Thank you 😊

[@babarrrr426]

@@sharathgoresir it is my pleasure

[@babarrrr426]

Thnk u very much sir

[@gamingdawg7383]

Sir aapne PW ka Intro Music chori kiya hahah

[@sharathgoresir]

I seriously do not know about this. I think only two or three video have this music. It's freely available for all in KZbin and filmora

[@gooooalfootballcuts6194]

No thanks to you

[@sunshine5257]

acha chemistry mien bc 2.303nRTlogv2/v1 hoga aur physics mien 2.303RT hoga bc

[@sharathgoresir]

I have done calculation for I mole. So n=1

[@Mahesh-we5hs]

Thank u sir