In this video, I showed how to differentiate the factorial function obtained from the shifted Gamma function, the pi function.
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@toastdog2143 ай бұрын
I love how you always find an intersting topic and go down a deep rabbit hole of making maybe 10 videos about that topic. Truly shows your passion for mathematics and the true desire to learn more. Never stop learning
@darickmendes9693 ай бұрын
I honestly enjoy seeing your enthusiasm for mathematics , you have way more passion and better teacher then all the math profs I had in my university haha
@PrimeNewtons3 ай бұрын
Thank you
@darrynreid45003 ай бұрын
It's a great choice of a problem for students to build an understanding of what's going on. I can see how you put a lot of thought into example selection, and your subsequent delivery for an audience is something to be admired.
@roberthowes66143 ай бұрын
You, Sir, are the epitome of what teaching with passion is all about.
@jethrobo35813 ай бұрын
Wow! You're one of the most fantastic instructors I have ever seen! Great video!
@devcoolkol3 ай бұрын
I was just wondering about this a few days ago, can't stop living!
@kianushmaleki3 ай бұрын
I like it when you smile. Love the videos ❤️
@anthonydevellis67083 ай бұрын
these are the most wholesome advanced calculus videos ive ever seen in my life. i say advanced calculus only because my high school calculus teacher was a devoutly religious, elderly vietnamese woman who stood 4'11"
@umbertocostabitencourt8417Ай бұрын
This is a really nice video. Your enthusiasm is so natural! Thanks for bringing this to us
@rav3nx333 ай бұрын
They are some clean as hell blackboards you got there. 😜 You do good work man, love the pace and energy
@journeymantraveller33383 ай бұрын
Great delivery and informative.
@jeanagulay34793 ай бұрын
Sir your videos helps me a lot.. From Iloilo Philippines ❤❤❤
@josephwellinghoff12593 ай бұрын
Very clearly explained...thanks
@WhiteGandalfs3 ай бұрын
Well, it's useful to have a sufficiently appropriate "coarse feeling" of the value. The integral at the end is not straightaway self-explanatory, so lets make sense of it! Maybe for the "coarse feeling" of the derivative, we don't need to take the exact value of the gamma function. By taking the difference over a full 1 in x, then taking the "appropriate" average... difference one up: (x+1)! - x! == x!*(x+1) - x! == x! * ((x+1)-1) == x! * x difference one down: x! - (x-1)! = (x-1)! * (x-1) Since the series is growing by multiplication (by a rather constant factor, since the difference between x and x+1 for the growths is the smaller the bigger x becomes), it is appropriate to take the geometric average from the difference up und down to get a pretty good fitting approximation of the value for the difference at spot x: average (one up, one down) = sqrt( x! * x * (x-1)! * (x-1) ) == sqrt( x!^2 * (x-1) ) == x! * sqrt(x-1) The "-1" in the sqrt we can qietly ignore since the whole thing goes about a "coarse feeling" anyways, thus we land at: derivative (x!) ≈ x! * sqrt(x) That's a very easy to remember (but very coarse) approximation for practical usage. Check with Wolfram Alpha yields that this is actually better approximated by: derivative ((x-1)!) ≈ x! / (sqrt(x) * ln(sqrt(x))) The "-1" on the LHS because the Gamma function is one of against the factorial function. To rectify that for easier use: derivative (x!) ≈ x! * sqrt(x) / ln(sqrt(x)) That is sufficiently easy to remember and to calculate and in the range of a few percentage off the exact value. And it gives a good "feeling" for the look of that derivative function.
@xenmaifirebringer5523 ай бұрын
Thanks for the extra insight and explanation! I think for a coarse approximation you could also differentiate Stirling's factorial formula. I'm curious if that'd look anything similar to the approximation you explained.
@AaryanK-wp6vi2 ай бұрын
I think you are very very ... passionate about mathematics. The 10s of videos you make about the same topic in different ways show this. And I like your way of explanation that is different from other YT people. I hope you do more videos like this
@Supercatzs2 ай бұрын
Great videos! Love the scripture at the end.
@kragiharp3 ай бұрын
Thank you, Sir! ❤️🙏
@douglasstrother65842 ай бұрын
You, Michael Penn & Papa Flammy all make me miss *real* chalkboards.
@KaushikAdhikari3 ай бұрын
6:42 John 1:4? Amen Thanks for the tutorial ❤
3 ай бұрын
Good job. You can actually represent the derivative of the gamma function using the definition of the digamma function and its series representation. Keep up the good work!
@andy_lamax2 ай бұрын
you are so close to discovering the di-gamma function
@DEYGAMEDU3 ай бұрын
I was waiting for this
@ttaylor3rd3 ай бұрын
nicely done!
@garrytalaroc2 ай бұрын
Cool but how are you gonna evaluate more complicated integral
@maths-pro-by-khan-sir2 ай бұрын
YOU ARE AMAZING
@ricardopaula4082Ай бұрын
calculus is my favorite maths topic, its so fun
@pk27123 ай бұрын
There is another maybe shorter way to show that the partial derivative with respect to x of t^x is ln(x)t^x . We know that t is considered as a constant . The derivative with respect to x of y=e^(ax) is ae^(ax) . Start with t = e^(lnt) ( where t and also lnt are constants ) and substitute this into t^x = (e^(lnt))^x = e^[(lnt)x}] . Now the derivative with respect to x of this last expression is lnxe^[(lnt)x} . But , in this last equation we know that e^[(lnt)x} = t^x ; therefore , the partial derivative with respect to x of t^x is (lnt)t^x .
@iithomepatnamanojsir3 ай бұрын
Very nice lecture
@rajesh29rangan3 ай бұрын
Thank you.
@cbbohn81073 ай бұрын
He is awesome
@Ghostwriter_zone3 ай бұрын
Now it's time for integral x factorial
@ingiford1753 ай бұрын
Saw an interesting definition of the gamma function: lim (n goes to infinity) n! * u^n / Product (other Pi function) ( v as v goes from 0 to n) of (u+v) u > 0 In an old 1960's Finite Differences textbook.
@Harrykesh6303 ай бұрын
I would like to enroll in your class this year!!
@polzinger3 ай бұрын
Very nice writing.
@PrimeNewtons3 ай бұрын
Thanks a lot 😊
@lornacy3 ай бұрын
All I could think of is that the derivative would be huge, quickly. Factorials grow fast 😅 I am going to have to rewatch this to really get my head around it.
@mickodillon14803 ай бұрын
Interesting one there. Good video.
@alejandropulidorodriguez97233 ай бұрын
splendid
@MrMusicM672 ай бұрын
Love the shirt! Where did you get it?
@Misteribel2 ай бұрын
You can simplify using the digamma function, though (if you can really call that a simplification).
@rknowling3 ай бұрын
Thankyou for a fun and useful result! 😄 In the early pages of Bleistein & Handelsman "Asymptotic Expansions of Integrals", they talk about: \limits_{N \to \infty } \left[ {{{\left( { - 1} ight)}^N}N!x{e^x}\int\limits_x^\infty {\frac{{{e^{ - t}}}}{{{t^{N + 1}}}}dt} } I have been wrestling with this for some time; thanks to your videos combining the Leibnitz rule, l'Hopital, second FTC etc with limits, I am (slowly! haha) gaining some traction. Much appreciated!
@beapaul44533 ай бұрын
Can you upload videos about complex geometrical problems(drawing graphs), like polygons? That would be great to see.
@PrimeNewtons3 ай бұрын
Sounds like something I don't know yet
@paraskumar98503 ай бұрын
@@PrimeNewtons never stop learning, those who stop learning ! stops living
@lornacy3 ай бұрын
@@paraskumar9850 He never said he wasn't willing to figure it out ... Looks to me like a way for him to sustain life!
@miguelmarcoscatalina38722 ай бұрын
Hace mucho que no practico matemáticas, pero me parece, solo me parece, que hay un grave error en cambiar una función que solo es continua en puntos concretos y aislados en una función continua en todo el intervalo. Lo considero un error, aunque puedo estar equivocado
@kotylka902 ай бұрын
Mister I think leibniz rule hold for proper integrals. How would you justify using it for the improper integral here?
@kianushmaleki3 ай бұрын
❤️❤️
@lemon.linguist3 ай бұрын
i love your videos! i have a question that's unrelated to the video but still mathematical i can put it in the replies of this question if you'd like
@PrimeNewtons3 ай бұрын
An email with be better. Primenewtons@gmail.com
@herlandarmantotampubolon81353 ай бұрын
Sir, it seems to me that you could use Lambert Function to continue the last result.
@makramaarid65982 ай бұрын
This is the gamma function
@user-ky5dy5hl4d2 ай бұрын
I did not understand much of it without delving into it more. But the beginning is interesting by making the x factorial as pi of x. I think you can do that with any irrational number, so why not chose square root of 2? Or another irrational number.
@mrngochoi893 ай бұрын
But i dont know the define of x! if x in R
@szymonharpula12172 ай бұрын
Wouldnt it be easier to use stirlings aproximation
@jacobgoldman57803 ай бұрын
the bounds are in terms of t or x?
@anuragguptamr.i.i.t.23293 ай бұрын
t
@raghuvanshiedit2 ай бұрын
Hey sir, a doubt is can't we write ln(t) t^x as ln(t)^(t^x) which would give x?
@sammtanX3 ай бұрын
sir, for the power of t, shouldn't it be x-1? Because the y = x!, not y = (x-1)! hence it should be gamma of x, so t's power has to be (x-1)
@PrimeNewtons3 ай бұрын
I used the π function
@salahouldaya49582 ай бұрын
why don t you ask if this fuction is derivable before anything
@MathSync3 ай бұрын
i ❤ Mathematics
@awrRoman253 ай бұрын
You could just differentiate Stirling formula.
@nyksik0012 ай бұрын
Is this channel for postgraduates?
@Ahmad-yi6d3 ай бұрын
Oops derivative of a factorial function 🥶
@MATHS_FOR_FUN3 ай бұрын
Dy/Dx = X! [ Sum from {i = 0 to x-1} (1/(X-i))] Isn't it ?
@hydraim98333 ай бұрын
Hi! I am curious, why is there no way? At the end of the video you had the intention to replace t^x e^-t with x! ? You didnt do it because it would be abusive notation or im missing the smth?
@awrRoman253 ай бұрын
You can not replace t**x*exp(-t) with x! because integral(t**x*exp(-t)) from 0 to inf equals x!, not function inside.
@petr_duduck2 ай бұрын
Учитывая, что Гамма функция- это интеграл, найти от неё производную не так уж сложно
@user-ld7cm5jj6h3 ай бұрын
Please try to solve this equation (X+1/x)^x=2
@user-ld7cm5jj6h3 ай бұрын
Please
@user-ld7cm5jj6h3 ай бұрын
Please
@bridgeon75023 ай бұрын
x = 1 (I just guessed)
@allozovsky3 ай бұрын
x = 1 is a trivial solution
@IoT_3 ай бұрын
Since the function on the left always increasing , there can be maximum one solution. One may guess that it's x=1 , but I am afraid , you have to use numerical ways to solve it, like Newton's method.
@allozovsky3 ай бұрын
I guess the next derivative would square the logarithm.
Abuse of notation is pretty common in math (as long as it is clear from the context what a given notation mean). After all, there are not so many math symbols to denote the variety of similar concepts.
@fabiopilnik8273 ай бұрын
Well in that case the derivative of x! is (x+1)! - x! = x!(x+1 - 1) = x!x. But technically that’s a difference not a derivative.
@anigami012 ай бұрын
anyone from India ( JEE aspirant) here
@cparks10000003 ай бұрын
Taking the derivative under an integral requires some justification.
@hussainrashed44533 ай бұрын
The FTOC.
@eliaskhanmeh73992 ай бұрын
X Munier multiply by zero the result zero
@eliaskhanmeh73992 ай бұрын
Thé chaîne de zéro is unknowing
@Berin.Jervin2 ай бұрын
X! is not continuous, so has no derivative.
@thedudethatneveruploads26172 ай бұрын
Correct; however, he differentiated the Pi function, which is a popular extension of the factorial function to all reals except negative integers, essentially making a continuous factorial function
@scheillaraffaelliАй бұрын
A non differentiable function may still be partially differentiable. He's correct here.
@porcospino2892 ай бұрын
Ugh.
@salahouldaya49582 ай бұрын
This fuction is not continu how could it be derivable ???
@v8torque9323 ай бұрын
Derivatives an anti derivative
@Leoscacchi082 ай бұрын
Hey bro here y=x ok? Emh no sorry i didn't understand I said that y=x Emh i'm sorry, can you repeat, i can't hear you Oh are you deaf? I said y=x!
@tonyscott16582 ай бұрын
You can go further. That derivative you speak can be obtained in terms of what is called the digamma function (Psi) . en.wikipedia.org/wiki/Digamma_function i.e. Int(t^x*ln(t)*exp(-t), t = 0 .. infinity) = Psi(x+1)*GAMMA(x+1)