Derivative of The Factorial Function

  Рет қаралды 100,450

Prime Newtons

Prime Newtons

3 ай бұрын

In this video, I showed how to differentiate the factorial function obtained from the shifted Gamma function, the pi function.

Пікірлер: 100
@toastdog214
@toastdog214 3 ай бұрын
I love how you always find an intersting topic and go down a deep rabbit hole of making maybe 10 videos about that topic. Truly shows your passion for mathematics and the true desire to learn more. Never stop learning
@darickmendes969
@darickmendes969 3 ай бұрын
I honestly enjoy seeing your enthusiasm for mathematics , you have way more passion and better teacher then all the math profs I had in my university haha
@PrimeNewtons
@PrimeNewtons 3 ай бұрын
Thank you
@darrynreid4500
@darrynreid4500 3 ай бұрын
It's a great choice of a problem for students to build an understanding of what's going on. I can see how you put a lot of thought into example selection, and your subsequent delivery for an audience is something to be admired.
@roberthowes6614
@roberthowes6614 3 ай бұрын
You, Sir, are the epitome of what teaching with passion is all about.
@jethrobo3581
@jethrobo3581 3 ай бұрын
Wow! You're one of the most fantastic instructors I have ever seen! Great video!
@devcoolkol
@devcoolkol 3 ай бұрын
I was just wondering about this a few days ago, can't stop living!
@kianushmaleki
@kianushmaleki 3 ай бұрын
I like it when you smile. Love the videos ❤️
@anthonydevellis6708
@anthonydevellis6708 3 ай бұрын
these are the most wholesome advanced calculus videos ive ever seen in my life. i say advanced calculus only because my high school calculus teacher was a devoutly religious, elderly vietnamese woman who stood 4'11"
@umbertocostabitencourt8417
@umbertocostabitencourt8417 Ай бұрын
This is a really nice video. Your enthusiasm is so natural! Thanks for bringing this to us
@rav3nx33
@rav3nx33 3 ай бұрын
They are some clean as hell blackboards you got there. 😜 You do good work man, love the pace and energy
@journeymantraveller3338
@journeymantraveller3338 3 ай бұрын
Great delivery and informative.
@jeanagulay3479
@jeanagulay3479 3 ай бұрын
Sir your videos helps me a lot.. From Iloilo Philippines ❤❤❤
@josephwellinghoff1259
@josephwellinghoff1259 3 ай бұрын
Very clearly explained...thanks
@WhiteGandalfs
@WhiteGandalfs 3 ай бұрын
Well, it's useful to have a sufficiently appropriate "coarse feeling" of the value. The integral at the end is not straightaway self-explanatory, so lets make sense of it! Maybe for the "coarse feeling" of the derivative, we don't need to take the exact value of the gamma function. By taking the difference over a full 1 in x, then taking the "appropriate" average... difference one up: (x+1)! - x! == x!*(x+1) - x! == x! * ((x+1)-1) == x! * x difference one down: x! - (x-1)! = (x-1)! * (x-1) Since the series is growing by multiplication (by a rather constant factor, since the difference between x and x+1 for the growths is the smaller the bigger x becomes), it is appropriate to take the geometric average from the difference up und down to get a pretty good fitting approximation of the value for the difference at spot x: average (one up, one down) = sqrt( x! * x * (x-1)! * (x-1) ) == sqrt( x!^2 * (x-1) ) == x! * sqrt(x-1) The "-1" in the sqrt we can qietly ignore since the whole thing goes about a "coarse feeling" anyways, thus we land at: derivative (x!) ≈ x! * sqrt(x) That's a very easy to remember (but very coarse) approximation for practical usage. Check with Wolfram Alpha yields that this is actually better approximated by: derivative ((x-1)!) ≈ x! / (sqrt(x) * ln(sqrt(x))) The "-1" on the LHS because the Gamma function is one of against the factorial function. To rectify that for easier use: derivative (x!) ≈ x! * sqrt(x) / ln(sqrt(x)) That is sufficiently easy to remember and to calculate and in the range of a few percentage off the exact value. And it gives a good "feeling" for the look of that derivative function.
@xenmaifirebringer552
@xenmaifirebringer552 3 ай бұрын
Thanks for the extra insight and explanation! I think for a coarse approximation you could also differentiate Stirling's factorial formula. I'm curious if that'd look anything similar to the approximation you explained.
@AaryanK-wp6vi
@AaryanK-wp6vi 2 ай бұрын
I think you are very very ... passionate about mathematics. The 10s of videos you make about the same topic in different ways show this. And I like your way of explanation that is different from other YT people. I hope you do more videos like this
@Supercatzs
@Supercatzs 2 ай бұрын
Great videos! Love the scripture at the end.
@kragiharp
@kragiharp 3 ай бұрын
Thank you, Sir! ❤️🙏
@douglasstrother6584
@douglasstrother6584 2 ай бұрын
You, Michael Penn & Papa Flammy all make me miss *real* chalkboards.
@KaushikAdhikari
@KaushikAdhikari 3 ай бұрын
6:42 John 1:4? Amen Thanks for the tutorial ❤
3 ай бұрын
Good job. You can actually represent the derivative of the gamma function using the definition of the digamma function and its series representation. Keep up the good work!
@andy_lamax
@andy_lamax 2 ай бұрын
you are so close to discovering the di-gamma function
@DEYGAMEDU
@DEYGAMEDU 3 ай бұрын
I was waiting for this
@ttaylor3rd
@ttaylor3rd 3 ай бұрын
nicely done!
@garrytalaroc
@garrytalaroc 2 ай бұрын
Cool but how are you gonna evaluate more complicated integral
@maths-pro-by-khan-sir
@maths-pro-by-khan-sir 2 ай бұрын
YOU ARE AMAZING
@ricardopaula4082
@ricardopaula4082 Ай бұрын
calculus is my favorite maths topic, its so fun
@pk2712
@pk2712 3 ай бұрын
There is another maybe shorter way to show that the partial derivative with respect to x of t^x is ln(x)t^x . We know that t is considered as a constant . The derivative with respect to x of y=e^(ax) is ae^(ax) . Start with t = e^(lnt) ( where t and also lnt are constants ) and substitute this into t^x = (e^(lnt))^x = e^[(lnt)x}] . Now the derivative with respect to x of this last expression is lnxe^[(lnt)x} . But , in this last equation we know that e^[(lnt)x} = t^x ; therefore , the partial derivative with respect to x of t^x is (lnt)t^x .
@iithomepatnamanojsir
@iithomepatnamanojsir 3 ай бұрын
Very nice lecture
@rajesh29rangan
@rajesh29rangan 3 ай бұрын
Thank you.
@cbbohn8107
@cbbohn8107 3 ай бұрын
He is awesome
@Ghostwriter_zone
@Ghostwriter_zone 3 ай бұрын
Now it's time for integral x factorial
@ingiford175
@ingiford175 3 ай бұрын
Saw an interesting definition of the gamma function: lim (n goes to infinity) n! * u^n / Product (other Pi function) ( v as v goes from 0 to n) of (u+v) u > 0 In an old 1960's Finite Differences textbook.
@Harrykesh630
@Harrykesh630 3 ай бұрын
I would like to enroll in your class this year!!
@polzinger
@polzinger 3 ай бұрын
Very nice writing.
@PrimeNewtons
@PrimeNewtons 3 ай бұрын
Thanks a lot 😊
@lornacy
@lornacy 3 ай бұрын
All I could think of is that the derivative would be huge, quickly. Factorials grow fast 😅 I am going to have to rewatch this to really get my head around it.
@mickodillon1480
@mickodillon1480 3 ай бұрын
Interesting one there. Good video.
@alejandropulidorodriguez9723
@alejandropulidorodriguez9723 3 ай бұрын
splendid
@MrMusicM67
@MrMusicM67 2 ай бұрын
Love the shirt! Where did you get it?
@Misteribel
@Misteribel 2 ай бұрын
You can simplify using the digamma function, though (if you can really call that a simplification).
@rknowling
@rknowling 3 ай бұрын
Thankyou for a fun and useful result! 😄 In the early pages of Bleistein & Handelsman "Asymptotic Expansions of Integrals", they talk about: \limits_{N \to \infty } \left[ {{{\left( { - 1} ight)}^N}N!x{e^x}\int\limits_x^\infty {\frac{{{e^{ - t}}}}{{{t^{N + 1}}}}dt} } I have been wrestling with this for some time; thanks to your videos combining the Leibnitz rule, l'Hopital, second FTC etc with limits, I am (slowly! haha) gaining some traction. Much appreciated!
@beapaul4453
@beapaul4453 3 ай бұрын
Can you upload videos about complex geometrical problems(drawing graphs), like polygons? That would be great to see.
@PrimeNewtons
@PrimeNewtons 3 ай бұрын
Sounds like something I don't know yet
@paraskumar9850
@paraskumar9850 3 ай бұрын
@@PrimeNewtons never stop learning, those who stop learning ! stops living
@lornacy
@lornacy 3 ай бұрын
​@@paraskumar9850 He never said he wasn't willing to figure it out ... Looks to me like a way for him to sustain life!
@miguelmarcoscatalina3872
@miguelmarcoscatalina3872 2 ай бұрын
Hace mucho que no practico matemáticas, pero me parece, solo me parece, que hay un grave error en cambiar una función que solo es continua en puntos concretos y aislados en una función continua en todo el intervalo. Lo considero un error, aunque puedo estar equivocado
@kotylka90
@kotylka90 2 ай бұрын
Mister I think leibniz rule hold for proper integrals. How would you justify using it for the improper integral here?
@kianushmaleki
@kianushmaleki 3 ай бұрын
❤️❤️
@lemon.linguist
@lemon.linguist 3 ай бұрын
i love your videos! i have a question that's unrelated to the video but still mathematical i can put it in the replies of this question if you'd like
@PrimeNewtons
@PrimeNewtons 3 ай бұрын
An email with be better. Primenewtons@gmail.com
@herlandarmantotampubolon8135
@herlandarmantotampubolon8135 3 ай бұрын
Sir, it seems to me that you could use Lambert Function to continue the last result.
@makramaarid6598
@makramaarid6598 2 ай бұрын
This is the gamma function
@user-ky5dy5hl4d
@user-ky5dy5hl4d 2 ай бұрын
I did not understand much of it without delving into it more. But the beginning is interesting by making the x factorial as pi of x. I think you can do that with any irrational number, so why not chose square root of 2? Or another irrational number.
@mrngochoi89
@mrngochoi89 3 ай бұрын
But i dont know the define of x! if x in R
@szymonharpula1217
@szymonharpula1217 2 ай бұрын
Wouldnt it be easier to use stirlings aproximation
@jacobgoldman5780
@jacobgoldman5780 3 ай бұрын
the bounds are in terms of t or x?
@anuragguptamr.i.i.t.2329
@anuragguptamr.i.i.t.2329 3 ай бұрын
t
@raghuvanshiedit
@raghuvanshiedit 2 ай бұрын
Hey sir, a doubt is can't we write ln(t) t^x as ln(t)^(t^x) which would give x?
@sammtanX
@sammtanX 3 ай бұрын
sir, for the power of t, shouldn't it be x-1? Because the y = x!, not y = (x-1)! hence it should be gamma of x, so t's power has to be (x-1)
@PrimeNewtons
@PrimeNewtons 3 ай бұрын
I used the π function
@salahouldaya4958
@salahouldaya4958 2 ай бұрын
why don t you ask if this fuction is derivable before anything
@MathSync
@MathSync 3 ай бұрын
i ❤ Mathematics
@awrRoman25
@awrRoman25 3 ай бұрын
You could just differentiate Stirling formula.
@nyksik001
@nyksik001 2 ай бұрын
Is this channel for postgraduates?
@Ahmad-yi6d
@Ahmad-yi6d 3 ай бұрын
Oops derivative of a factorial function 🥶
@MATHS_FOR_FUN
@MATHS_FOR_FUN 3 ай бұрын
Dy/Dx = X! [ Sum from {i = 0 to x-1} (1/(X-i))] Isn't it ?
@hydraim9833
@hydraim9833 3 ай бұрын
Hi! I am curious, why is there no way? At the end of the video you had the intention to replace t^x e^-t with x! ? You didnt do it because it would be abusive notation or im missing the smth?
@awrRoman25
@awrRoman25 3 ай бұрын
You can not replace t**x*exp(-t) with x! because integral(t**x*exp(-t)) from 0 to inf equals x!, not function inside.
@petr_duduck
@petr_duduck 2 ай бұрын
Учитывая, что Гамма функция- это интеграл, найти от неё производную не так уж сложно
@user-ld7cm5jj6h
@user-ld7cm5jj6h 3 ай бұрын
Please try to solve this equation (X+1/x)^x=2
@user-ld7cm5jj6h
@user-ld7cm5jj6h 3 ай бұрын
Please
@user-ld7cm5jj6h
@user-ld7cm5jj6h 3 ай бұрын
Please
@bridgeon7502
@bridgeon7502 3 ай бұрын
x = 1 (I just guessed)
@allozovsky
@allozovsky 3 ай бұрын
x = 1 is a trivial solution
@IoT_
@IoT_ 3 ай бұрын
Since the function on the left always increasing , there can be maximum one solution. One may guess that it's x=1 , but I am afraid , you have to use numerical ways to solve it, like Newton's method.
@allozovsky
@allozovsky 3 ай бұрын
I guess the next derivative would square the logarithm.
@eliaskhanmeh7399
@eliaskhanmeh7399 2 ай бұрын
Not zero x/ y if y=0 that mean not knowing
@danielaromero8474
@danielaromero8474 2 ай бұрын
Γ(x) = (x-1)! → x! = Γ(x+1) (Gamma function) Γ'(x) = Γ(x)(ψ(x)) → Γ'(x+1) = Γ(x+1)(ψ(x+1)) d(x!)/dx = x!(ψ(x+1)) → ψ(x+1) = ψ(x) + 1/x (Digamma function) ψ(x) = Hₓ₋₁ - γ (Harmonic number & Euler's constant) d(x!)/dx = x!(Hₓ₋₁ - γ + 1/x)
@himadrikhanra7463
@himadrikhanra7463 3 ай бұрын
( x-1)!...?
@harris5140
@harris5140 3 ай бұрын
Factorial is part of N, not R.
@allozovsky
@allozovsky 3 ай бұрын
Abuse of notation is pretty common in math (as long as it is clear from the context what a given notation mean). After all, there are not so many math symbols to denote the variety of similar concepts.
@fabiopilnik827
@fabiopilnik827 3 ай бұрын
Well in that case the derivative of x! is (x+1)! - x! = x!(x+1 - 1) = x!x. But technically that’s a difference not a derivative.
@anigami01
@anigami01 2 ай бұрын
anyone from India ( JEE aspirant) here
@cparks1000000
@cparks1000000 3 ай бұрын
Taking the derivative under an integral requires some justification.
@hussainrashed4453
@hussainrashed4453 3 ай бұрын
The FTOC.
@eliaskhanmeh7399
@eliaskhanmeh7399 2 ай бұрын
X Munier multiply by zero the result zero
@eliaskhanmeh7399
@eliaskhanmeh7399 2 ай бұрын
Thé chaîne de zéro is unknowing
@Berin.Jervin
@Berin.Jervin 2 ай бұрын
X! is not continuous, so has no derivative.
@thedudethatneveruploads2617
@thedudethatneveruploads2617 2 ай бұрын
Correct; however, he differentiated the Pi function, which is a popular extension of the factorial function to all reals except negative integers, essentially making a continuous factorial function
@scheillaraffaelli
@scheillaraffaelli Ай бұрын
A non differentiable function may still be partially differentiable. He's correct here.
@porcospino289
@porcospino289 2 ай бұрын
Ugh.
@salahouldaya4958
@salahouldaya4958 2 ай бұрын
This fuction is not continu how could it be derivable ???
@v8torque932
@v8torque932 3 ай бұрын
Derivatives an anti derivative
@Leoscacchi08
@Leoscacchi08 2 ай бұрын
Hey bro here y=x ok? Emh no sorry i didn't understand I said that y=x Emh i'm sorry, can you repeat, i can't hear you Oh are you deaf? I said y=x!
@tonyscott1658
@tonyscott1658 2 ай бұрын
You can go further. That derivative you speak can be obtained in terms of what is called the digamma function (Psi) . en.wikipedia.org/wiki/Digamma_function i.e. Int(t^x*ln(t)*exp(-t), t = 0 .. infinity) = Psi(x+1)*GAMMA(x+1)
@RottenWoodInPower
@RottenWoodInPower 2 ай бұрын
Me totally forgot gamma function
@kk12181
@kk12181 Ай бұрын
May I know the name of this educator! Respect 🫡
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