This is series will be very help full for upcoming csir net
@SADDAMHUSSAIN-mw3cv Жыл бұрын
1:06:03. But Correct options are (a) and (d) Only.
@ankitayadav404327 күн бұрын
If n=3 then ??
@RanjangamingYT74772 ай бұрын
55:36 jast example [1/2,1/2][1/2,1/2] this is idempotent but diagonal entries not 0 and 1 Therefore b option discard
@yogeshjadhavpatil4120 Жыл бұрын
Aafke video se bahut help milati hai
@mystory54389 ай бұрын
Thank you so much for your lecture sir, . It is very useful for us.
@jittaboinaramu1537 Жыл бұрын
Sir , in some problems at A²=I is involuntary matrix but you told that it is idempotent matrix ..
@amitgupta-sk4hw Жыл бұрын
Correct buddy
@hajeeranasreenqueenofscience Жыл бұрын
In hurry sir has said like that...
@BalajiPadhy-l8f5 ай бұрын
Dear Sir If A=I then A is always Diagonalizable Bcoz am(1) = Gm(1)@1.11.05
@pranavninghot37779 ай бұрын
A^2 = A is idempotent matrix A^2 = I is involuntary matrix
@DrHarishGarg9 ай бұрын
Thanks
@roshaningale59076 ай бұрын
10:57 dec 2014 questions AM(1)= 2,GM=1
@Achukutty256 ай бұрын
Yes, rank is 1, so GM is 2
@rajithak26065 ай бұрын
Thanks a lot sir for providing the tips for every concept of u taken sir it helps me a lot to understand it in better level and think in a objective way and I always thankful to you sir🙏
@masterkapil6214 Жыл бұрын
Thnku sir aap hmare liye bhut acha content tyar krte ho
@SADDAMHUSSAIN-mw3cv Жыл бұрын
59:33 sir here you taken an example of a matrix of zero eigen values.
@nidhiyadav1577 Жыл бұрын
Good evening sir, Thank you so much sir for making helpful lectures. THANK YOU SIR.
@super40educationalinstitut29 Жыл бұрын
Very good sir.. mja aa gaya
@mak511 Жыл бұрын
Sir in this video many mistakes in the solution... overall most helpful thanks for this .
@anitakaushik-be8mo Жыл бұрын
In que june 2017 ..option b is not correct sir ..for idempotent matrix it is not necessary to be an diagonal matrix ..it can be all entries with (1/n) type ..so how it is correct by your side
@kritikagrover4980 Жыл бұрын
Thank you so much sir for all your efforts🙏🏻🙏🏻
@shimorikichishorts83025 ай бұрын
How can we know rank of a matrix from characteristic polynomial 40:10
@ishadevi20715 ай бұрын
Very helpful 😊
@SAJID-BOXАй бұрын
sir,at 47:48 if we take the trace of only A then option c is true but if we are having A= -I then the sum of trace of A and A(square) is 0..then option b must be true ?
@archanakumarimeena30587 ай бұрын
24:42 par A2=0 to A^3=0 hi.hoga zero matrix se A ka.multipliy karenge to zero honhoga A^3=A^2.A
@Manish-uq5le10 ай бұрын
Thanks you sir ❤
@physicsmagic7868 ай бұрын
11 : 25 e. Values are 1,1,2 which are not distinct so how it can be diagonalisable.
@hajeeranasreenqueenofscience Жыл бұрын
Sir 1:10 dec18 ...A=I ev's (1,1,1) not distinct so not diagonalizable Right
@ummehabeeba9026 Жыл бұрын
Sir can you solve modern algebra pyq?
@mirshabir3672 Жыл бұрын
Net Dec. 2018 A is a real matrix and Characteristic polynomial (X-1)^3......Sir, can you explain the question again ............
@hajeeranasreenqueenofscience Жыл бұрын
A=I ,evs( 1,1,1) not distinct so not diagonalizable.
@Radharanilove-y5d5 ай бұрын
1:10 sir why option d is wrong .... In this option they didn't ask the minimal polynomial...so why we check tgis with minimal polynomial....matrix M satisfy this option d....and also one is not an eigen value in d option ... Please clarify this option
@906mukesh8 Жыл бұрын
Thank you so much
@shrawankumarpatel2148 Жыл бұрын
Thank you so much sir
@rintumondal56587 ай бұрын
1:02:07
@anupamsamanta6690 Жыл бұрын
Sir Identify matrix always diagonalizable
@906mukesh8 Жыл бұрын
Thanks you sir
@sat4maths8 ай бұрын
Hi sir, All your short trick are very nice and useful to solve the problems quickly. But few problems ,there some mistakes that rank of Matrix is we count no.if non zero rows right..... In some problems you took no of zero rows.....
@indhui1911 Жыл бұрын
A^2 =A matrix is Idempotent **
@maharaja8085 Жыл бұрын
Both
@HeWhoKnows- Жыл бұрын
Sir can you please do a short video on Rate of convergence of Müller's method. I've searched in my library and non of the books has detailed proofs and just a statement that it convergence to 1.84
@sureshm92 Жыл бұрын
Thank you sir...
@ronneysaini7763 Жыл бұрын
Thanks Sir ji❤
@mainakbanerjee92824 ай бұрын
7:44 are the eigen values correct?
@manishasharma96373 ай бұрын
I think not correct
@ishitaagrawal987 Жыл бұрын
sir identity matrix is always diagonalizable then how are you discarding options saying it is not.
@bantumath3527 Жыл бұрын
Im also thinking that I is not diagonalizable,but it is not true But how sir prove AM(a=1) is not same as GM(a=1)
@ishitaagrawal987 Жыл бұрын
Am is always equal to Gm for identity matrix
@bantumath3527 Жыл бұрын
@@ishitaagrawal987 no Am(1)=3 and gm(1)= nullity(A-0.I) Which is 3 but sir take rank of A ,that why it is not equal Now i know it is equal
@mathmadeeasy26016 ай бұрын
54:00 can't be use matrix [1/2 1/2 1/2 1/2]
@UrbarmanIItpkd6 ай бұрын
Why ?? Although it satisfy A^2= A
@shwetarathi304 Жыл бұрын
Thankyou sir
@SADDAMHUSSAIN-mw3cv Жыл бұрын
54:48 only options (a) ,(c), and (d). are correct.
@waseemayoub6227 Жыл бұрын
We can take nilpotent matrix to discard option (a). Why is b not true...if eigen values are distinct then it is necessarily diagonalisable. Correct me if I am wrong sir.
@mathematical2508 Жыл бұрын
Sir aapne diagonalizable ka jo first point likhvaya h vo iff nahi h Diagonalizable ke liye jaruri nahi h ki eigen value distinct aayengi Distinct imply krta h diagonalizable honga
@saikatmalla73906 ай бұрын
sir please upload ring theory previous year question lecture
@aaqibwani74062 ай бұрын
Dear Dr,,,,at 55.06 just take an example of [[1/2,1/2],[1/2,1/2]] to discard option 2.
@RanjangamingYT74772 ай бұрын
1:6:20 B option not true . Only A true
@amitgupta-sk4hw Жыл бұрын
❤
@GameFeverHQ Жыл бұрын
There are so many mistakes sir,like you said identity matrix is not diagonalisable . overall helpful
@RanjangamingYT74772 ай бұрын
I think only C option true hoga. B,d option ka rank 2 ha question me rank of Matrix 1 ha