Diffraction Grating Problems - Physics

[@TheOrganicChemistryTutor]

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Grating problems. These kind of problems in higher education which have a method like usual study problems or sometimes a bit of difficulty level is a test for knowing the problem solving ability. It is not about concepts always. Being able to solve study problems is a good sign for getting a university degree in education in the sense of skill. Thanks.

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mantap geng

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[@tamashiitrickster643]

Very helpful , THANKS

[@anoopkrishna20000]

that was very helpful. thanks.

[@wobblyjohn]

Error in defining 'd' at 1:27.

[@abhaysuji8052]

(c) Another diffraction grating has half the angle between the first and second order light beams when light of wavelength 532 nm is incident upon it. Estimate the number of lines per mm of this second diffraction grating. [2] The initial grating has an angle of 7.8 degrees difference between theta 1 and theta 2

[@geoffphillips8183]

Hi, great vids! Quick question if d=1/N , N = number of lines per meter ,for example, d= slit spacing… then are we counting the end edge of the diffraction grating as 1slit? Take a diffraction grating of 1m with one line ( slit) in the middle, we know slit spacing is 0.5 m … we know there are 2 slit spacings & 1 slit. But applying the formula without counting end edge as 1 slit we get o.5 = 1/1 … instead of 0.5=1/2 ( counting the end edge as a slit. ) I hope this makes sense.. thanks 🙏

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Thank you.

[@hemishudhav3845]

Thank you so much

[@uddimishra151]

at 1:10, does "m" correspond to minimums or maximums? because m0 seems to be at the central maxima, however m1 and m2 seem to be minimas. Could someone please help me out.

[@qwertykeyboard8563]

By my understanding, M1 and m2 are maximas

[@sheldonfrancis7830]

Could make to find the total number of orders of diffracted light? Should the angle be Zero? (dsine 0= m lamda?)

[@anitaku5153]

Why did you use the equation with sin when the d is very small, I thought you use tan when d is very small 4:26

[@farhatulalam]

thanks a lot!

[@waiitwhaat]

I used to be HELL scared of diffracting gradients. Man those were really easy. Trick is to not be intimidated by the question.

[@Zeewan_and_guitar]

isn't cm to m Divide by 100? Then why you multipled by 100? stucked please reply

[@TheOrganicChemistryTutor]

yes. To convert cm to m, you need to divide by 100. However, it's the reverse when converting 1/cm to 1/m. You need to multiply by 100. 100 cm = 1 m.

[@Zeewan_and_guitar]

Yes I got it. I'm a big fool. Thank you so much

[@Hirwan1889]

What is the distance between fringes produced by a diffraction grating having 139 lines per centimeter for 590-nm light, if the screen is 1.50 m away?

[@anikatajriankhan999]

can you make a vedio about poetential and voltage dividers please???!!

[@swastikpal7230]

the second question u did the wavelength did not fall in the visible range - so how can we see the interference pattern?

[@jsc3417]

can you do some overlapping problems?

[@orekoyaelizabeth9863]

Pls I think there’s a mistake with the conversion from centimeter to meter cos while solving am getting a different answer from yours.

[@dorabinga1101]

im getting 100 he made a mistake

[@giannomarais4363]

2:26 anybody else hear the intro for Phineas and Ferb?

[@thai27]

is there any difference between slits/m and lines/m sir

[@yassin_Ibrahim07]

nah slits is just the difference between the gap and the other border its the same thing

[@ashwinnnnn]

is it m lyamda in both bright and dark frindge?

[@Frankortyfg]

Dear sir Thanks for your video like it Could you give all formula on laser questions ruby he neon Thanking you

[@ruchijaiswara2028]

In q no. 3 m getting a diff. Answer for d

[@remake3693]

what if I need to calculate the order... how do I do that?

[@renfoley5747]

im a year late but.... you gotta rearrange the equation so m is the subject. i.e. (d*sin(theta))/lambda (wavelength)

[@BitterTast3]

How would the math change if the slits weren't all evenly spaced?

[@naomikumson9684]

Why do you do you do x10-9 on wavelengths

[@melissafigueroa4218]

Naomi Kumson cause The wavelength is (ie 540nm) and 1 nm= 10^-7m then 100nm=10^-9

[@wowshamanful]

@@melissafigueroa4218 *1 nm= 10^-9m *

[@geoffphillips8183]

Hi , sorry I’ve always been confused by the formula d=1/N … see previous msg .. thanks

[@faryalhuma9522]

What the hell is this like n=length/no of lines so how this n suddenly equals to 1/d ???? What's this ?can you please reply me because may be my concept is built wrong.

[@connorbellamy8742]

I did this and got 1.1x10^8 but my lines were 500 per mm and the order was second and the angle was 24.8 what did I do wrong

[@mishakireev6195]

Love u

[@harishankarvishwakarma2941]

If there are 15000 lines per in a grating find the grating element

[@deandramiller8025]

I need assistance doing a physic work.. someone please help

[@cerengulyuz119]

first question, wavelength was 650 why did it become 650x10^-9 ? pls im so confused

[@ImtiazAli-mh8nb]

the initial wavelength was in nm, u have to convert it into meters for calculation

[@aliko3519]

My brain is on the verge of exploding, ughhh i don't understand

[@faryalhuma9522]

Same is the case with me... its been 1 year of your comment so now if you're understanding this shit please help me too....

[@harishankarvishwakarma2941]

Answer Abhi chahiye

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[@aswin8063]

Hey! Do u know the difference between diffraction and diffraction grating?

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Thanks a lot, sir

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