Young's Double Slit Experiment

[@TheOrganicChemistryTutor]

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[@синиякрыса]

12:45 Multiply 8.5 x 3 Multiply with wavelength Divide number with 0.5

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[@Toddg1234Mr]

Look at the KZbin video "Double Slit Experiment" by Todd Grigsby. It uses an interferometer to show that light waves can bounce off another. This applies to the double slit experiment thus the title.

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[@ishmam5541]

anwer of the third question : 1.76*10^-3 m/1.33 = 1.32*10^-3

[@JoshuaMcHale-oj8xy]

right?! that is what i got as well, i am unsure why he isnt dividing by the m (canceling m)

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very clear

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who else feels so accomplished after getting the practice problems correct?

[@helan311]

ecxactlyy

[@anissofia1731]

Thank you sir for this veryy understanding video! But you only teach about the bright fringe and i want to know about dark fringe. Im having problem with determining the m of dark fringe.

[@Jobeexotic]

for dark fringe, change lambda to lambda/2 in the equations

[@thomasolson7447]

Some other guy was saying that's the squared magnitude of a complex function. I've seen them rounded, if that's the case.

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can you please make a video about thin films.

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now i am convinced that you know *everything*

[@hajerkindi6441]

for 10:35 instead of using dy(1)=lambda m D you could've just used tan1.5 times 4.5 (make your life easier)

[@anangelsdiaries]

Bruh my CEGEP degree should have your name on it lmao

[@kayinator287]

Hey, on question 2, I got the answer as 3.3*10^-11 meters, could there have been a conversion error on your part because I converted all the values into meters via calculator converter.

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[@abdullahannaijjar9306]

If the distance between the two points is 6cm and the angle of reflection, is 30⁰ what is the wavelength?

[@CuriosityGuy]

A wave is spread across. In a double slit experiment, if the wavefunction representing the electron, hits the slits, shouldn’t that be a measurement and shouldn’t that collapse the wavefunction? Now, you'll say it's not a physical wave, it's a probability wave. But then how does a probability wave split into two after the slits? Then, it should be like, the wave hits the slits, the electron says, dude I'm going through the slits, so don't collapse, but you can split into two and diffract. When does it decide that it's going through the slit?

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[@michaelgonzalez9058]

Is sine-product which is the dark of the pupil sight

[@duckman03]

Is it normal to have an average of 17 lessons per subject for finals?

[@zach7559]

A little high. We have 14

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its more helpful👏

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I love you!

[@courage936]

I don't understand why we assumed that Θ is close to zero, it's not zero, it's 1.5 degrees which is kind of a large number relatively?

[@eduflyer]

why is theta equivalent to theta 1 at 4:00 minutes into the video? I wanted to know why those 2 angles are equivalent. tks

[@porschechen6582]

On the last example, why didn't we multiple m=4 on the left side of the equation?

[@JoshuaMcHale-oj8xy]

for the final example, when calculating for d, why are you not dividing by m? I see you are leaving it on the numerator side of the equation when dividing by the remaining left side, but not including it on the denominator.... which would cancel m out entirely... maybe I am missing something.. someone explain pls

[@fatimaalfehaid]

HERO!

[@mohdrafiqbasri5603]

How to consider angle is small?

[@theniqabinextdoor9272]

so helpful!

[@kahlolomolefe9141]

Why did they divide the distance of the two slits by 10^3??

[@waiitwhaat]

As a math nazi, nothing pierces my ear worse than hearing, "thirty-three point _fifteen_ centimeters" I'm kidding lol. I actually found this really helpful. Thankyou so much!

[@IsmaelKorowa]

What mode is your calculator? Mine seems to be not corresponding.

[@jacobmartinelli7496]

What would happen if the constructive interferencing from 1 set of double slits passed through another set of double slits? Would the universe break because of energy being created?

[@rangareddy4336]

😂😂😂 it's very likely that's you'd not be able to align the double slits at the exact same spot where the waves are in phase, but if you do... You'll just get another interference pattern where the intensity/amplitude is lesser than the last interference pattern you saw. The highest intensity in an interference pattern is achieved at the centre of the double slits (projected on the screen) but if you plan on using another 'Double' slit, the starting intensity of the light would be less than the original, and hence you'd only get a fainter interference pattern :)

[@서연우-u9y]

Could I know the reason triangle’s base line is λ ? Why that length could be λ 😭

[@dgwako]

Great

[@StarMan-h9b]

Watch the video of eugene khutoryansky pls ,named : 'quantum mechanichs : animation explaining quantum physics.' In the first 40 seconds it is clear explained using marbles. According to the video marbles and light create same pattern. It mean both of them have same nature. If the marbles are particles same would be the light( light would have particle nature as marbles have ).

[@WeddingWhims]

I have a question please, why did he divide 2.29*10^-5 by 10^-3

[@bakedpiexzigzag1652]

bro i came here to ask the same question i dont understand whyyyyy

[@ironduke5058]

​@@bakedpiexzigzag1652To convert it to millimeters. You divide by 10^-3 if you want the mm conversion of any value

[@kevinjackson976]

6:19 You mean in degrees not in radians, sin(theta) is ~theta

[@yashyelmame1460]

No it is radians and not degrees

[@L1_scann]

u waffled so hard

[@sin_2]

what about darker sides? do we just add 1/2lamda ?

[@chessgamer1198]

Can we use white light in this expriment ? If yes how ? If not why ?

[@matthewbrennan3127]

No, because white light is a mixture red, blur, green, ect., which are at different wavelengths. This experiment uses light at just one wavelength. If you use light with different wavelengths, then each wavelength is going to be diffracting at different angles and interfering with each other so you won't get the neat maximum-minimum pattern on the screen

[@callumdoherty4681]

Yes, you can use white light, it will just produce an even cooler looking interference pattern as the different colours will diffract at a different angle, leaving you with something similar to a horizontal looking rainbow

[@rangareddy4336]

Monochromatic light is preferred because the resulting interference pattern is more sharper when compared to a white light (which is a mixture of other colours). White would give you interference, but not as sharp and distinct as a monochromatic source.

[@user-fh2rw9zh8g]

04:00 why are the angles equal

[@ireneposada3714]

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[@dn-wb7uk]

i don't get why the two angles (theta 1) are equivalent. could you help me to prove it please? thank you

[@ADTheAwesome]

It has to do with the geometry of similar triangles