Distributed loading on a beam example #1: rectangular loads

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Engineer4Free

Engineer4Free

Күн бұрын

Пікірлер: 14
@iftiimiye1038
@iftiimiye1038 6 жыл бұрын
thanks for amezing explanation.clear
@Engineer4Free
@Engineer4Free 6 жыл бұрын
You're welcome, thanks for watching =)
@14henrylover
@14henrylover 7 жыл бұрын
really helpful thank you sir
@Engineer4Free
@Engineer4Free 7 жыл бұрын
Thanks for the feedback! f you haven't already, make sure you check out engineer4free.com/statics for the rest of the tutorials!
@mx520rider
@mx520rider 5 жыл бұрын
How do you solve when A and B aren't on the ends of the beam? Thanks
@Engineer4Free
@Engineer4Free 5 жыл бұрын
Then you would have some kind of overhanging beam. Here are some examples with overhanging beams: kzbin.info/www/bejne/eHmxl2CrrLxqrck - kzbin.info/www/bejne/h5jNfoWop7Kkn6c
@MomenMusameh
@MomenMusameh 4 жыл бұрын
what is the relation between centroid (center of area ) and distributed forces?
@Engineer4Free
@Engineer4Free 4 жыл бұрын
Centroid of the shape of a distributed load represents the x location of the equivalent point load. It's needed for the sum of moments about a point calculation. Please watch videos 58-65 here: engineer4free.com/statics it will explain the method and go over enough examples to be confident in what's going on.
@MomenMusameh
@MomenMusameh 4 жыл бұрын
@@Engineer4Free you are the best thank you ♥
@أفكاربسيطة-ج8ل
@أفكاربسيطة-ج8ل 4 жыл бұрын
when we change the distributed force to concentrated force how can we find the point of action of this force ?
@Engineer4Free
@Engineer4Free 4 жыл бұрын
Please watch videos 58-65 here: engineer4free.com/statics it will explain the method and go over enough examples to be confident in what's going on
@s_naeemnaqvi8725
@s_naeemnaqvi8725 4 жыл бұрын
you saved my ass
@eykaaaa99
@eykaaaa99 6 жыл бұрын
For pin support where is the Ax
@Engineer4Free
@Engineer4Free 6 жыл бұрын
Ax = 0 because there are no horizontally applied loads. It's pretty okay to not bother writing that, but if you are on a test I would still explicitly write Ax = 0 just to communicate without doubt that you know what is going on.
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