Second-order differential equations: how to solve.

[@DrChrisTisdell]

It is my pleasure. Thanks for the wonderful comment.

[@anthonydulake9322]

G`Day ,I`ve downloaded a few of your lectures and i find your lecturing style to be quite refreshing and quite interesting and direct. I especially liked the lectures on differential equations which i seem to be watching over and over again . Goodstuff.Keep up the good work.

[@DrChrisTisdell]

It's my pleasure. Thanks for the feedback.

[@DrChrisTisdell]

By definition (or you can show), the general solution to u' = qu (q = constant) is Ke^{qx} where K is any constant. The problem I solved has q = -2. Hope this helps.

[@djarteybenjamin3612]

very good lecture Dr your students are grateful .from Ghana/Africa

[@DrChrisTisdell]

I am very glad that you found this useful.

[@Pyoga03]

you made everything clear and really detailed proff.. thanks alot.. now i know why we are doing the procedure and its not just a pattern...

[@Phughy]

Thank you so much for quick repons!

[@bahiraborhan7068]

Thank you very much for the video Dr. Chirs

[@DrChrisTisdell]

You are very welcome. Good luck with your mathematics.

[@Phughy]

10:46, can someone explain me why u is in the form of K.[e^(-2x)]?

[@zabuza55]

Once again sir, you're the best! Thanks to your videos, I have no problems in this topic. =)

[@DrChrisTisdell]

@superppp1000 You are welcome.

[@Ensign_Cthulhu]

@ 4:35; the way to find a black cat in a dark room is to walk through it with your eyes shut, carrying eggs on a fragile china tray. Murphy's Law says the cat WILL be there. Nice demonstration of where the two functions of e come from - very clear!

[@jokerxyz2]

thanks

[@DrChrisTisdell]

:-)