det A^T = det A

[@dariokronig8009]

"e. t. wants to go home" knocked me out 😂😂 thank you very much for the good video!

[@mikhailmikhailov8781]

It just directly follows from the fact that the determinant is just an alternating summation over permutations. It doesnt matter if you are permuting based on rows or columns. x_1*y_3*z_2 is the same as x_1*z_2*y_3. Its trivial.

[@dwfischer]

Love the enthusiasm 10/10 would reccomend

[@yashovardhandubey5252]

Dr. Peyam : " ASSUME A is invertible" PHYSICS NOISES INTENSIFIES

[@ghnbtrcv8672]

great video

[@zivssps]

Note that the determinant you talked about at 4:38 is not 1 but -1.

[@yashovardhandubey5252]

This is fine camera work.... Good Angle and resolutions....!! 👌👌

[@BabaFroga]

lol, nice, do you have playlist of matrices and determinantes; Those are really cool, just like proves of those rules to calulate them; just what I need for my University now, it's easier to rewatch all those proves to put them in mind, then... :) Thanks :)

[@BabaFroga]

@@Craynz thanks

[@easymath643]

Why prof who spoke English are the best is the key is in English

[@yashovardhandubey5252]

The proofs of matrices and determinants are really interesting

[@Tomaplen]

you divivde by det(A) and BOOM T =

[@danielauto3767]

Suggestion: Show that exp(trace(A)) = det(exp(A)).

[@mikhailmikhailov8781]

Annoying proof, trivial to show in the case of diagonalizable matrices, but for general proof jordan normal form and complex matrices are needed.

[@hallow2083]

lY