Great video, I don’t know why people are not showing you more appreciation. Keep up the good work. Thank you,
@fornx85746 ай бұрын
Professors who use Pearson Publisher have the option to disable his videos in the homework. My instructor removed all his vids except for like two of them but I am in an accelerated summer course at a community college. I googled and found all Dr. Anderson vids on youtube. Thank the physics lords!!! I made an A in my uni physics I course, while employed full time. Hoping to get the same results for physics level II. This man has single handedly helped me pass.
@saskiavanhoutert31904 жыл бұрын
I wished I had you as teacher in my early schoolday's perhaps then I could have a positive result. You'r a excellent teacher keep doing that good work, thanks and kind regards
@rickshawty Жыл бұрын
this is the best explanation straight to the point. Thank you!
@lancelovecraft59134 ай бұрын
I have been over reliant on gauss law. I forgot this method w trig sub. Gauss law is so powerful it can get u there in significantly fewer steps. But i like this method as well bc i enjoy seeing multiple methods of arriving to the same conclusion
@irfanjames65512 жыл бұрын
Honestly, it's soo good. Why his videos are so underrated. God Bless you.
@yoprofmatt2 жыл бұрын
Underrated? I've got millions of views. Of course, most of those are from my mom, but still. Cheers, Dr. A
@mubashirwaheed4742 ай бұрын
Cute! Thank you so much, and I hope you are having a great day
@MmAaZzzz Жыл бұрын
Great Explanation👍
@pnt143 жыл бұрын
I am from india. I like the lesson . Thank you 😁 sir
@dynabenamara6352 Жыл бұрын
I do no know why you don't have a lot of views your explanation is awesome
@changliem69862 жыл бұрын
Thank you so much ,professor your lecture just make me love physics
@yoprofmatt2 жыл бұрын
Awesome, love to hear that. Cheers, Dr. A
@heeohjin32633 жыл бұрын
Thank you, professor! Your videos are amazing:) How do we know that the integral of (x^2+y^2)^-3/2 = 1/y^2? I understood y is a constant, but It’s still confusing. How did you get the 1/y^2
@fastandbulbous6282 Жыл бұрын
You take the improper integral of 1/(x^2+y^2)^3/2 from 0 to infinity, plugging in infinity we see that the value of the anti derivative there “vanishes” and we are just left with 1/y^2
@imranibrahim24444 ай бұрын
@@fastandbulbous6282please explain widely I still don't understand
@talhaanik84418 ай бұрын
so good
@Gomamon64 Жыл бұрын
you're a life saver
@andonkeppeler8156 Жыл бұрын
Amazing!
@ahmetmelihterzi63443 жыл бұрын
the (fake) end was literally wonderful :D
@gerakore8948 Жыл бұрын
do this integral.... oh you can look it up in the book
@TheRecoveryChannel2 жыл бұрын
#DUNN
@keshosingh56453 жыл бұрын
thank you sir
@akaez28072 жыл бұрын
just wow!!
@guillermocesarganem5532 Жыл бұрын
I CAME HERE ONLY FOR THE INTEGRAL TO BE RESOLVED!!! WHY Y'ALL ASSUME I CAN DO IT???
@chunkylover700511 ай бұрын
you don't really need to solve it. It's in the "table of integrals" section of your textbook just look it up. unless your professor is making you solve it by hand... then i'm so sorry for you
@imranibrahim24444 ай бұрын
@@chunkylover7005Which text book???
@QuickLearnScience3 жыл бұрын
How you know it an infinite line chart do they have to tell you in the problem??
@yoprofmatt3 жыл бұрын
Yes, the problem should specify. Cheers, Dr. A
@yacinetebbi90074 жыл бұрын
Man you saved my life
@saul-gone-z3o4 жыл бұрын
I have a question. Is Ey = Enet ?
@yoprofmatt4 жыл бұрын
asem shaat, In this special case, yes. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
@imranibrahim24444 ай бұрын
Who knows how to do the integral ...... I can't do it
@thuyavansathiamurthi35927 жыл бұрын
dat fake out at the end =/
@network99907 жыл бұрын
Why don't you write k for 1/4pieE0, aren't they equivanlent?
@marcioamaral75115 жыл бұрын
They're literally the same, k is a name for 1/4piepsilon0
@Ghostride1004 жыл бұрын
Its mainly because E0 can change based on the material between the line of charge and the point, it represents the permittivity of free space but if there was something inbetween the line of charge and the point, E0 could be different.