wow, can't believe this came on my recommended today. im doing a maths degree at university now and your videos were amazing dude. you are truly doing amazing work. props to you dude
@Yma010411 ай бұрын
what university do u go to for yr11 GCSE maths level💀
@kyuzo331311 ай бұрын
na u misread it, I use to watch his videos back when I was sitting my gcse (never sat it tho coz of Covid) . randomly had his video pop up on my recommended one day
@saturday90327 ай бұрын
Cheers for the walkthrough mate. Appreciate it
@dobby101 Жыл бұрын
Thank you so much for uploading
@A-78918 күн бұрын
for question 22 , how do u know to use 'g' first then 'f' ?
@sophiekindly319 ай бұрын
Thanks lots of help 👍
@Mirabelle_maier9 ай бұрын
the last step on question 20?
@khalidrahman23587 ай бұрын
for q24 how did u know that the centre was of the circle was the origin?
@Arthur_CSR7 ай бұрын
The question states that the equation of the circle given is x^2+y^2=12.25. The general form for an equation of a circle is x^2+y^2=r^2. The points which were given were 2.1,2.8. Radius can then be found using Pythagoras. 2.1^2+2.8^2=r^2 works out to r=3.5, which is the same as root 12.25 (the result of making r the subject of the equation of a circle which was given). These two values are the same, therefore meaning that points 2.1,2.8 must originate from 0,0.
@Emilyfarrell15x6 ай бұрын
Shoutout to st hildas for using papers from 2022 🔥
@nooneparticular7213 Жыл бұрын
I love❤genie
@DAGUM-n3g Жыл бұрын
is same as IGCSE?
@Yma010411 ай бұрын
unfortunately no
@vascobishop3359 Жыл бұрын
You are the best
@alisajadhosini1158Күн бұрын
❤❤
@emwanta76877 ай бұрын
what topic is q12
@ch7pp7 ай бұрын
Iteration
@RMProjects7857 ай бұрын
Why do you assume the centre of the circle is 0?
@MadinaJamali7 ай бұрын
it's highly likely, basically if you're not given the centre then you just assume its 0
@A-78918 күн бұрын
I just copied what someone else wrote: The question states that the equation of the circle given is x^2+y^2=12.25. The general form for an equation of a circle is x^2+y^2=r^2. The points which were given were 2.1,2.8. Radius can then be found using Pythagoras. 2.1^2+2.8^2=r^2 works out to r=3.5, which is the same as root 12.25 (the result of making r the subject of the equation of a circle which was given). These two values are the same, therefore meaning that points 2.1,2.8 must originate from 0,0.