EDEXCEL Topic 16 Kinetics II REVISION

[@afraankhan20]

You're helping me big time, Mr. Harris. If I could, I would burn down the subscribe and like button because you said so. Godspeed!

[@tomkrys3331]

Well explained, fantastic detail, brilliant video as always. I just get this topic now. Thanks a hell of a lot man, you're a fantastic teacher!!!

[@AlleryChemistry]

Glad it helped!

[@mhd8499]

An absolute lifesaver Mr. Harris! You’re a legend!

[@miranabbas67]

THANK YOU SO MUCH YOU ARE THE BEST

[@AlleryChemistry]

You're welcome!

[@miranabbas67]

@@AlleryChemistry sir how do i make my notes? do i just rely on the textbook? please help me x

[@inderpalhayer3507]

Hii I need help on this question, don't understand how to solve it.The enthalpy change of HYDRATION of MgSO₄ can be found using two seperate calorimetry experiments. ΔH for dissolution of MgSO₄ (s) = -85 kJ mol‎⁻¹, and for MgSO₄.H₂O (s) = + 9.5 kJ mol‎⁻¹. What is ΔH of hydration of MgSO₄?

[@daisylawrence7447]

36:19 won't the concentration of reactants change as reactants get converted to product, so less moles of reactants?

[@Anonymous-ll1pj]

Great ... On point 👍👍

[@vee4815]

thank you is all i have to say

[@HamzaElsharkawy-n7z]

AMAAZING VIDEO!!!!!!!! I LOVE YOUUUUUUUU. BBG

[@raulbabbar5415]

🐐

[@Fafa22]

5:37

[@the_crackin3610]

This a whole ahh movie bruh

[@livontheedge101]

Saving my whole chemistry Alevel 🙏🙌🙌

[@daanyaalkhan2687]

But that shits not too bad is it 😂😂😂

[@cyrusfrei807]

Lifesaver. Very concise and all bases covered.

[@kazuki2882]

57:55 on the right side of equation isn't it 2H+? since you lost a hydrogen ion from propanone.

[@garimagrg6796]

TYSM! i was having trouble understanding but it all makes sense now!!

[@nightwing4407]

hi at 27:36 the rate has quadrupled then how it is a first order reaction? when u said when rate quadruple it is second order reaction and when it doubles it is 1st order reaction?

[@wanker5399]

It's because the concentration quadrupled as well. For a first order, the change in concentration is proportional to the change in rate, in this case the concentration increases by 4x and so does the rate, but if this were second order, the rate would have increased by 8x, not 4x.

[@karimaakter2598]

Hello @Malahim kashif , ik i'm but here it is :) It's first order because [NO] has increased by 4 times as well as the initial rate.So [NO] is directly propotional to the initial rate as a result it is first order. hope this helps

[@ahmedibrahim9082]

SO CONFUSED. HOW IS 0.63 TIMES 4 2.58 ISN'T IT 2.52 ?? CAN WE INGORE THESE SLIGHT CHANGES 27:30

[@luhvs]

im so confused too

[@raz4114]

yes if it is roughly the same then you ignore it

[@AG-ql1sy]

19:20 what happened to you saying it can only be worked out experimentaly and not from the equation

[@ahmedibrahim9082]

I think it was already calculated and they just gave it in the question, no idea why he referred to the 2 moles in front of the nitrogen.

[@daanyaalkhan2687]

55:09