Plus Two Maths Chapter 2 | Inverse Trigonometry - Revision

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Principle value um adhyatha result um njn padicha oru short cut und.Njan padichondirunnappol kitte tha. STC 1st. Sin ,Tan,Cosec ivarda principle value π/2 team aan .[ ], ( ), [ ]- {0} . Result il (-x) varumbol ivarkk adhyan -ve varum. STC. last (Nb:- last ann STC varunnath). CoS, coT, seC. Ivarde principle value 0,π group ann . resultil (-x) varumbo π- varunnu. Ee short cut simple aanu.arkkenkilum useful akumenn viswasikkunnu😊

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superb classes for onam exam thank you sir answer= - π/2

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-90°.....thank you for this hardworking.....this team inspire more people to touch the feel of achievement

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Ente ponno ithra nalla cls vere evideyum kittula . Enikke ee chapter aru kundavum. Ariyunundayirunnilla but within 1.30 hrs sir athe set akki thannu Thnk u soo much sir♥️♥️♥️♥️

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Question of the day answer Sin-¹(-1) = -sin-¹(1) = -π/2 Ente net idakk theernathu kond menti onnum kandilla , anyways classile topics nallonam manassilayi . Thank you sir ❤

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Thankz♥️ Ans=-π/2

[@haneenamahnaas1941]

sin^-1(-1) is -90digree thank you sir......this live session has been incredibly insightful! thank you eduport

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Sin-1 (-1) = -π/2 Thank you shamil sir and Eduport❤❤

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Sin^-1 (-1) = -π/2 Thank you SIR 🥰 Chapter full nannayitt manasillayi Thank you Eduport Team 🥰❤

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Sin-1 (-1) = -π/2 Thank you Shamil sir 🌟❣️

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Ans:π/2 This live session has been incredibly insightful! I've learned so much in such a short time. Thank you to the shamil sir for making complex topics easy to understand. Can't wait for the next one.💗😇

[@atrusfratedot7]

-π/2 aaneee😀

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Sirr super clas Ayirnu veendum re revision pole ayi because sir enik 73 marks Endayirnu +1 il now trying for full mark in maths shamil siree ❤️‍🔥 pina ajas sir rushda mam ellavarum super ahnnn Answer for the question is (-pie/2)

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Sin^-1(-1)= -π/2 Great thankful Eduport and shamil sir from the bottom of my heart for this wonderful session❤🎉

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Thank you so much sirree❤❤❤ thank you for your efforts...sir karanm ee chapter full sett ahnnuu❤️❤️❤️🔥🔥🔥🥰

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Class starts at 5:17

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-sin inverse( 1) Adipoli clss ayrnuu❤

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Full sett🤜❤

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Sir seen thanne thanku sir❤

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Set ❤

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Principle valu of sin‐¹(-1)=pi/2=90°

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[@Kadeeja131]

Sin^-1(-1) =-sin^-1(1) -π/2 Thankuuuuu eduport and shamil sirrrr❤❤❤💌💌💌

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Thank you so much sir

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sin^-1(-1)=-pie by 2 Thankyou eduport❤️

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Sir super class❤

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Principal value of sin^-1(-1) is -π/2 radians or -90 degrees. Thank you team eduport for this wonderful session😊😊

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Sin-¹(-1)=-sin-¹(1)=-π/2 Thank you shamil sir & eduport❤

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Sin inverse of -1=-pi/2 Thankyou sir inverse trigonometry school ill edukumpozhe onnum manasillayirunnilla eppo full chapter set ayii. Thank you Eduport 💖💖

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Sin ^ -1(-1) = - π / 2 Thanku eduport , enikk difficult aayirunnu ee chapter ippol easy aayi 😊😊😊

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Sin^-1 (-1) = -π/2 Thank you sir.chapter sett aayi.🥰

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Sin-1(-1)=-pi/2 Sir Class adi pwoli thnaks shamil sir and eduport

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Sin-1 (_1)=-pi/2 or 90dgree Thankyou shamil sir and eduport❤️

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Sin^-1 (-1) = -pi/2

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-π/2

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-sin^-1(1) =pi/2 Thanku eduport Good and super classess❤🎉😊

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Sin^-1(-1)=-pi/2 Thankuu sir for ur wonderful clz.....🥰

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Ans= -pi/2 I understood this cls very well. Thank you shamil sir❤️‍🔥

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Thankyou sir❤

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Sin-1(-1)=-π\2 Thank you eduport ❤❤

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Thanku eduspot

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-pie by 2 thank you eduport ❤❤

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Thank you sir 🙏🏻

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Ans =-π/2

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Principal value of sin^-1(-1)=-π /2 radian

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Ans: -pi/2 Thank you sir❤️

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sin^-1(-1)= -π/2 Thank you Shamil sir.

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Superb class 💪✨

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Principal value of sin^-1(-1) is -π/2 radians or -90 degrees Thanks to EDUPORT

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Pi/2

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ans =-pi/2 adipol cls arnoo 🤩🤩 tanQ shamil sirr🥰

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5:15

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Answer: -π/2 Thank you sir... Chapter fullum set ayii😊

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-π/2 adipoli classayirunnu sir..

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Sin-1(-1) = - π/2 Thank you sir

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Ans= -π/2 Thanku eduport❤

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Thank you sir Answer =-pi/2

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Sin-1(-1)=-pi/2 . Thankyou eduport

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Sin^-1 = -π/2 Thank you❤ Eduport❤

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Sin-1(-1)=-π/2 Thank you sir ❤

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ans=pi /2 thanku Eduport

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-90° Thank you sir

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-pi/2 Thank you sir ❤❤

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Sin-1(-1) = -sin-1(1) = - π/2

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Sin-¹(-1) = -π/2

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Sin inverse(-1)=-π/2

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Super class 👌

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Qn of the day and= sin inverse (-1)=-sin inverse 1=-π|2 Thank you shamil sir

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Question of the day answer= -π/2 Thank you eduport ❤️❤️

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Sin-¹(-1)=-sin-¹(1)=-π/2

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Tank you

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Sin^_1 (-1) =- pi/2 Thanku eduport ❤️🥺

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Thank you sir ❤ Ans: -π/2

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Thank you sir ❤🎉 Ans=-π/2

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Ans= -π/2 Eduport❤❤ Inverse trignometry set set Tanq❤

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Ans:- -𝛑/2

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Ans=-π/2 rad or -90° Thankyouuu eduportt❤❤

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Sin-¹(sin -1)=-sin -¹ (1)= -pi/2 Thanku eduport ❤❤

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Sir Karnataka syllabus same ano

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Sin(-1)sin -pi/2

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-sin 90

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-90 degree

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-sin pi/2

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Ans = -π/2 Proud to be Eduport student ❤

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Question of the day answer = -π/2

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