Electrical Engineering: Ch 12 AC Power (20 of 58) How to Find Max. Power Transferred? Example 2

[@boratgollum5983]

Nobel prize for that channel !

[@21mejia25]

Thank you for sharing your wealth of knowledge.

[@saitamakun525]

You are great sir! Have a good life

[@Sheldon-v8d]

Sorry, so, to calculate Z_TH, we must ignore the current 12A in a curcuit loop?

[@eshaanwer9734]

Keep uploading such informative videos :)

[@michaelweiser9457]

At 1:00, why did you find the impedance in parallel? Aren't all of the values in series?

[@MichelvanBiezen]

The 5 ohm resistor is in parallel with the rest of the circuit. (relative to the load impedance)

[@MatthewIbarra98]

Have you done any max power transfer examples with dependent sources?

[@MichelvanBiezen]

No, not in this set.

[@teymurhuseynli7138]

May you continue this and other electrical engineering topics?

[@MichelvanBiezen]

Yes, more videos are in the queue.

[@onurarslan6790]

thank you sir for these great videos

[@KattamuriKowshiq]

what to donate you and what to donate sir??

[@MichelvanBiezen]

We appreciate whatever you can comfortablly donate. Thank you! www.ilectureonline.com/donate www.patreon.com/user?u=3236071

[@hectoracevedo7442]

Gracias profesor!

[@SuperJclam]

why are you multiplying 8 times RL at the Average Max POWER?

[@MichelvanBiezen]

You can see the derivation of that equation in one of the previous videos.

[@chanakyasinha8046]

Max power trnsfr to resistive load is (1/2)iv....when rL=rS... Meaning Vdrop acrros source and load resistance is half the max voltage,...but also current gets halfed of max , So power is (1/2)(i/2)(v/2)=(1/8)vi

[@saichandra8773]

@@chanakyasinha8046 sorry brother... U r wrong... We founded that to transfer maximum power transfer load impedance is equal to conjugate of source impedance. Then find out power in the circuit in normal way

[@samiaazom3363]

you are the best sir !!! thanks a lot

[@MichelvanBiezen]

Most welcome!

[@Goldenspitfire588]

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