Electrochemistry Gr 12 : Electrorefining

Рет қаралды 60,358

Kevinmathscience

Күн бұрын

Пікірлер: 61

@russellr.gwenjere2456 4 ай бұрын

Cheers to us 2024 matriculants

@Lost_soul78 4 ай бұрын

we cooked

@simaineegumede 4 ай бұрын

@@Lost_soul78omg so real

@stomemaake6334 4 ай бұрын

What is there to cheer about my guy, we're cooked🥲

@Luyanda-w2v 4 ай бұрын

@@stomemaake6334 LMAO so facts, t- minus 12 hours😭😭

@ndaba_girl 4 ай бұрын

@@Luyanda-w2v its about to go down 😭

@ConfusedEarth-tl5ey 2 ай бұрын

Tomorrow is my final I just wanted to say you helped me a lot

@deglanjies696 2 ай бұрын

Good luck, I hope this paper treats us well 🙏🙏

@jakegordz101 6 ай бұрын

Please do a video on the standard hydrogen electrode and how it's used to measure oxidation and reducing ability if everything on the half reaction table

@shub9644 4 ай бұрын

Alright my fellow grade 12. Don't know if this will help but let me explain what I know. So imagine a galvanic cell with Anode on left and Cathode on the right with a Voltmeter connected. So the voltmeter would read the energy transfered from left to right. Now what the old scientists did was put Hydrogen as the Anode of this cell (left) and then tested every single Substance as the Cathode. So if a substance at the Cathode was a good reducer then the Voltmeter reading would be positive because electricity would move from left to right. If the substance was a good oxidiser (or atleast better than Hydrogen) than the Voltmeter reading would be negative because electrons would rather go to the left So they than made the table. So taking Hydrogen as reference: if the substance is positive it's a good Cathode ( it's good at reducing and thus a good oxidising agent) If the number is negative it's a bad Cathode and thus a good Anode( good oxidiser and good reducing agent) Let me keep yapping: When comparing 2 substances The one that is a better Cathode than the other one would be the Cathode in that cell and the other one would automatically be the anode because it's not as good as the other one. So based off of that, if we wanted to know what the Voltage of this cell would be we take our reference voltages ( the ones in the table) And We would compare the cathode one with the anode one ( by subtracting) and then we would get the strength of the voltage of the cell Hopefully this helped, If you don't understand something in this large paragraph just reply to this comment asking and I'll try to respond back.

@jakegordz101 4 ай бұрын

@@shub9644 very helpful thanks so much!!!

@jakegordz101 4 ай бұрын

@@shub9644 writing my chemistry prelim.next week and this was super helpful

@shub9644 4 ай бұрын

@@jakegordz101 glad it helped. I'm writing tomorrow 😅

@jakegordz101 4 ай бұрын

@@shub9644 good luck godspeed

@psychoff2470 2 ай бұрын

If you are here today me and you are cook3d😂

@albangwesu9982 2 ай бұрын

😭😭😭😭

@Boitumeloa 2 ай бұрын

You can say that again 🤣😭

@Hope-ms9fp 2 ай бұрын

Were soo cooked 😅

@psychepulsehq 2 ай бұрын

straight up sautéed😭🥘

@PurpleMayonnaise 2 ай бұрын

Its wraps, shoprite applications lookin juicy rn

@Cocobeans-xo 4 ай бұрын

ngl im cooked

@simaineegumede 4 ай бұрын

Same

@yourfavoritewoman7037 2 ай бұрын

real

@superviciousgaming9584 2 ай бұрын

its chaiii

@fallenlegend6402 Жыл бұрын

Isnt the one the furthest up on the left going to win because reduction is taking place at the Cu cathode and the one higher up has higher reduction abilities? Or am i missing something

@IAMBATMAN... Жыл бұрын

Stronger reducing agent undergoes oxidation

@deppressocatto6795 5 ай бұрын

That's what I'm saying?

@Testis69 4 ай бұрын

left side oxidation agent and not reduction agent

@ziyandamajubana8536 4 ай бұрын

@@deppressocatto6795are you using table 4A or 4B. Kevin is using table A maybe thats why it's a bit different

@Snalo_dlamini 2 ай бұрын

Thank God for this comment 😭