Excellent video sir. Can anyone help me to understand please 9*5inverse mod 17 and 63 mod 17 calculation in details explanation. Thanks in advance
@prakashkumarojha10272 жыл бұрын
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@niloofaralizadehsaveh79312 жыл бұрын
watch this: kzbin.info/www/bejne/qZnEgo2dbceki68
@eyob_g9 ай бұрын
5^-1 mod 17 (multiplicative inverse of 5 modulo 17) can be calculated using Extended Euclidean Algorithm (EEA)
@barfib18714 жыл бұрын
thank u sir, u are the best. Yes u have clear all my doubts.
@codeaperture3 жыл бұрын
Good one 🔥💯
@eyob_g9 ай бұрын
Thank you very much for providing such informative lectures. I have a question regarding your explanation around the 10:39 mark. Given that the elliptic curve is symmetric about the x-axis, wouldn't -P simply be equal to (x1, -y1)? Once again, I sincerely appreciate your efforts in clarifying these fascinating concepts.
@PixelSergey4 жыл бұрын
Thank you! Your video has immesely helped me with my IB Extended Essay on Elliptic Curve Random Number Generation.
@AdvancedMath4 жыл бұрын
You are welcome. It makes me really happy that it is helpful for anyone out there.
@mohonasib179 Жыл бұрын
Thank you so much sir ,I really grateful to you ❤️❤️
@MrRyzale Жыл бұрын
I have a question, where do you get the equation for slope?
@cTRINp Жыл бұрын
Thanks for the video really helped :)
@Yoyo-ck9pm3 жыл бұрын
Super ❤️❤️❤️❤️
@cosminp40472 жыл бұрын
great!
@HiteshJoshiJI10 ай бұрын
For posterity, just adding , -131mod 17 is 5 , because -131 = 17* (-8)+5
@nazmulislamananto Жыл бұрын
How are equations of x3 and y3 are obtained?
@naveedkhan-i3d Жыл бұрын
sir ,how i multiply 18 into (12,18) this .like let 18 is a private key and the pair form number is our base point on elliptic curve
@AdvancedMath Жыл бұрын
See the previous videos please.
@manmohanpundir56193 жыл бұрын
amazing explained
@MindSparks01 Жыл бұрын
How can be reverse calculation easily
@eden98084 жыл бұрын
Thankyou so much for this video. It helped me out a lot :)
@AdvancedMath4 жыл бұрын
I am happy to know that.
@jb05023 жыл бұрын
Sir, thanks for your excellent video. Where is x-axis now? Is it shifted to P/2(17/2)? Or P is added on both sides as x+17 and x-17? Thanks in advance.
@xl0xl0xl02 жыл бұрын
Excellent video, but, did you just . . . . skip over modular inverse like it's not even there???
@AdvancedMath2 жыл бұрын
Yep. That was not the focus of the video so I pre-calculated it.
@jeevaneswaranmuthukumar622910 ай бұрын
@@AdvancedMath can teach us how to do that? Im having difficulties on how you get 11x 10 inverse 1= 13
@brycebacon20414 жыл бұрын
i dont understand how you got 9/5 mod 17? help!
@AdvancedMath4 жыл бұрын
22 mod 17 = 5 as 5 is the remainder when we divide 22 by 17. Similarly 77 mod 17 = 9 as 9 is the remainder when we divide 77 by 17.
@brycebacon20414 жыл бұрын
@@AdvancedMath thank you so much :)
@sai12110 Жыл бұрын
sir 22/17 = 1.29 and 77/17 = 4.5 how to possible 9/5 please explain
@srscoachingclasses67643 жыл бұрын
Sir, is there no use of b
@YOGESHP-u7p2 ай бұрын
-6 divided 10 mod 17 how it become 11 *10^-1 mod 17 ???
@alejandroamoros53392 жыл бұрын
Why are we doing mod17 twice? One as 77/22 and another time for 9/5^-1?
@AdvancedMath2 жыл бұрын
We can apply mod 17 whenever we want simplification. First I apply mod 17 to simplify 77/22 to 9/5. However, after applying inverse the number became large again, so I apply mod 17 again to simply it.
@alejandroamoros53392 жыл бұрын
@@AdvancedMath Great! That makes a lot of sense! The videos are great, very easy to understand the maths behind it. Thank you very much sir!
@sandeepkumar-vy3se3 жыл бұрын
sir can you made the video on finding the order of point P
@AdvancedMath3 жыл бұрын
I plan to...
@sandeepkumar-vy3se3 жыл бұрын
Thank you sir
@jojo22343 жыл бұрын
I don't understand how 9*(5^-1) mod 17 which should be (9/1)*(1/5) mod 17 is equals to 63. Could you explain me that? Thank you.
@jojo22343 жыл бұрын
@εὔνοια Thank you, I will watch it.
@prakashkumarojha10272 жыл бұрын
kzbin.info/www/bejne/fJ-0f5V8oZxlgrs
@niloofaralizadehsaveh79312 жыл бұрын
watch this: kzbin.info/www/bejne/qZnEgo2dbceki68
@naveeningaleshwar63003 жыл бұрын
How 9×5inverse=63 ?
@AdvancedMath3 жыл бұрын
5 inverse in mod 17 is 7. Thus 9*7=63.
@yuliaruda82803 жыл бұрын
maybe the question is about the inverse? as I understand, the inverse of 5 is taken by multiplication, not by addition (5^-1 doesn't equal -5). that's why we search for a number that multiplied by 5 will give us a 1 mod 17. so 5 inverse is 7 (not 12).
@MrRyzale Жыл бұрын
@@yuliaruda8280 I still don't understand, please elaborate further
@AM-sg4zg10 ай бұрын
@@MrRyzale The inverse of 5 (mod 17) is the number x such that 5x = 1 (mod 17). In other words, we need to find a number x such that 5x is one more than a multiple of 17. We have 5*7 = 35 = 2*17 + 1, hence the inverse of 5 (mod 17) is 7. And therefore 9 * 5^-1 (mod 17) = 9 * 7 (mod 17) = 63 (mod 17) = 12 (mod 17).
@MrRyzale10 ай бұрын
@@AM-sg4zg Thank you so much for the explanation sir, now I understand.