Emma | Anya Taylor-Joy Manipulates Mia Goth

[@eduardodcell]

mia goth deserves an oscar soon. Pearl, X and Infinity Pool are terrific

[@dAUVIonTrowell]

Goated actress

[@rk63family]

I agree bout that

[@norijean3279]

Yet the Academy would never acknowledge these movies.

[@J7nty]

Mia and Anya have such great on screen chemistry they were also good in “Marrowbone”

[@arontamas5639]

that movie scared the hell out of me and then left me as a crying mess :'D that plot twist killed me.

[@xynfinity]

@@arontamas5639 you are sweet gay

[@Onetwothreefour.]

I’ll never forget her role in split, I came away from that movie thinking about how good of an actor she is. A movie with lots of great talent. Next thing you know she was doing queens gambit

[@arontamas5639]

Their first movie together was Marrowbone, such an underrated horror gem, they both were great in that one......

[@rafaelrusydi710]

I need anya and emma in more movies

[@jules2879]

you mean Mia? lol

[@rafaelrusydi710]

@@jules2879 oh shoot that’s what I mean

[@Rawrrrw1.]

They just meant for each other loll

[@motor4X4kombat]

If they get into the batman, i can see mia goth as harley and anya as poison ivy

[@greghannibal]

Wow, I've never seen Anya in something so...wholesome!

[@ImCheesedOut]

A Brazilian and an Argentinean girl

[@perryjones7771]

Honestly why do I think they act like big ass kids when they’re together. I just feel like they let their intrusive thoughts win.

[@livebreezybreatheasy]

Mia is always wonderful.

[@chasehedges6775]

Fantastic actresses

[@tonyrodriguez2943]

I can wait for Anya Taylor Joy as Princess Peach 👑👸🏼in The Super Mario Bros Movie 🎥🍿.

[@37654]

They fine af

[@auroralee3934]

Johnny Flynn is such a cutie❤

[@grizzly505gaming9]

this is pearls alternate ending lol

[@TedBundy1989]

Would like. Daises remake with these two

[@safado441]

Emma is amazing.

[@janel342]

The English are more circumspect in company and not so emotionally explicit.

[@donotreply8979]

​@@janel342 how much cringier can a response be?