Energetics 1 | A level Chemistry

[@gbxnzz]

ive started alevels in september. everyday since then ive relied on your videos and theyve actually helped me so much. its so much easier to understand everything. Thank You!! i get so excited when i see a video of yours that i need!

[@chemistrytutor]

Thank you loads for your kind words 😊 It's lovely to know that they're helping people understand Chemistry better!

[@kizzy6566]

I like how you break down this topic into simpler in just one hour ( great for cramming) 🙃

[@gracechen2412]

I don't think I can do A level Chemistry without your videos! Thank a million!!

[@chemistrytutor]

Happy to help! You can do it!

[@iamahib]

There's only a little time remaining before A levels and I'm completely relying on your videos ; which I believe makes you an amazing teacher! Thank you very much for everything!

[@chemistrytutor]

You're totally welcome! Best of luck 👍

[@saadali5836]

Just 2 days left 🥲. Binging this guys videos at 5x speed is the only way I know whats going on

[@chemistrytutor]

@@saadali5836 best of luck! 👍

[@alibea_1208]

how did it go?

[@jamestuffour2620]

Thank you so much for this video.Ive struggled to understand from different sources but it’s been a needle in a haystack until I found this video.

[@chemistrytutor]

That's excellent to know thank you! Hopefully you'll see that there are other videos on here of the same style drive.google.com/file/d/1s3I5prjbJRR1U1lcKpXO9TQpQMaVoP66/view?usp=drivesdk

[@Sky_h]

Thank you so much for the great explanation! As soon as you started explaining it using vectors, it finally clicked. I understood energy calculation with the formulas but I could never figure out the arrow directions in Hess's cycle before watching this video.

[@chemistrytutor]

Brilliant! I'm really pleased it's useful! Well done for persevering !

[@piqueblinders7303]

53:09 why don't you calculate the enthalpy of combustion for oxygen on the left side of the reaction, only carbon and hydrogen?

[@chemistrytutor]

@piqueblinders7303 Good question. Combustion is an oxidation reaction, so the element reacts fully with oxygen. The element oxygen will not react with itself, as oxygen doesn't burn (although, of course, it supports burning), so it doesn't have an enthalpy of combustion.

[@ASHAR240]

42:48 sir why didnt we take x as the starting point and why we took z instead of x

[@chemistrytutor]

Your starting point is set by what it is you need to calculate. Z --> X was our unknown that we needed to calculate so what means we had to start at Z

[@naledijani1322]

Absolutely adore this, thank youuuu

[@erenildadesouza5938]

Great work

[@chemistrytutor]

Glad it's useful. Hope Chemistry is going well 😃

[@kosiepatricklibeo5106]

I'm writing next week and you saved my exams

[@chemistrytutor]

Hey, glad it was useful. Don't know if you've seen this video? kzbin.info/www/bejne/e6PHdnSAnLp7g6c Good luck for the exams!

[@zebamaryam]

Thank you for the very clear explanation!!!

[@chemistrytutor]

You're welcome 😊 Thanks for the positive feedback

[@boaztemo5783]

So much better than reading words!??!

[@chemistrytutor]

Thanks. Words are good too though 😀

[@boaztemo5783]

@@chemistrytutor Indeed, good work, it's really helpful

[@chemistrytutor]

@@boaztemo5783 👌

[@NwengongLevisonNwiebe]

Very informative video. Thank you so much this was really helpful information

[@chemistrytutor]

I'm really pleased it was useful 😀

[@ImranAwan-n9s]

Do we need to know about Maxwell-Boltzmann Distribution for AQA?

[@chemistrytutor]

Yes definitely. I've covered it in my kinetics videos kzbin.info/www/bejne/hnSXlWVmj9-AjLs

[@tamanaa37]

I wanted to ask how did you know how many of each elements to put in the elements section for formation cycle?

[@chemistrytutor]

You look at the balanced equation from the original line and kept it consistent with that

[@tamanaa37]

@@chemistrytutor I’m not sure ?

[@chemistrytutor]

@tamanaa37 I meant, that was the method. If the reactant is C8H18, you will need 8C and 9H2 at the bottom

[@tamanaa37]

@@chemistrytutor thank you so much !

[@chemistrytutor]

@@tamanaa37 👌

[@ImranAwan-n9s]

Do we need to know about enthalpy change of neutralisation and enthalpy change of reaction for AQA?

[@chemistrytutor]

You could in theory be asked about the enthalpy change for any reaction (which all enthalpy change for reaction means) Equally, you do need to know the Equations for neutralisation reactions. I dont think you'll be asked to *define* enthalpy of neutralisation, but you could be expected to work something out

[@chemistrytutor]

👌

[@areebahaque5916]

These vdos are super helpful, sir can u make a playlist for Edexcel AS chemistry please

[@chemistrytutor]

Hi, apologies for the slow response. I'll add that to my list. It will take a while as I don't know the structure of Edexcel as well as I do AQA

[@CYNTHIA.056]

Am really pleased thanks alotttttt

[@chemistrytutor]

Excellent 😀

[@anelediepo1406]

God bless you for your great teaching

[@chemistrytutor]

Thank you! It's really lovely to know it's useful 😊 ☺️

[@doreenaddo1728]

These are amazing

[@doreenaddo1728]

Will u be making more?

[@chemistrytutor]

@@doreenaddo1728 definitely I will. I'll be sticking with Physical chemistry for the next few weeks. Then move on to inorganic.

[@salmannadeem2827]

Thanks. Please make a website where you organise your videos and files as this will make it easier for others to use your channel and will increase your popularity.

[@chemistrytutor]

This is a great idea. It's something I've been considering... but I'd need to work out how to do it!

[@AAROnline-b4v]

helped a lot thanks 👍👍👍👍

[@chemistrytutor]

😎

[@doreenaddo1728]

I have some confusion about why u don't include the enthalpy change of combustion of the oxygens at 52:00

[@chemistrytutor]

Combustion is the reaction between a substance and oxygen. So the oxygen is necessary because it supports the burning process. It doesn't actually burn itself. And if it did burn and we follow the logic... oxygen would be reacting with itself and turning into its own oxide of oxygen, which would be oxygen... so that's what you started with. And that's not a change. So we have it in the reactants to balance the equation, and because its needed to help other things burn, not because it burns.

[@doreenaddo1728]

@@chemistrytutor Ohhhh ok ok, that makes sense. Thank you soo much 😊😊

[@chemistrytutor]

@efaz kader yes, I think so. All A level courses for sciences *have* to be similar. I think chemistry is almost identical whatever the exam board. There are some differences in the exams themselves. That seems to be the main difference

[@roshanehaughton6665]

🙏 This is lovely

[@kizzy6566]

Indeed😭😭😭

[@chemmy8062]

is a month of doing past papers non stop good enough to land me an A or B at least?

[@chemistrytutor]

Good question. It really depends on where you're starting from. If you're already confident with the core content and will be able to do all past papers at least once in that time... probably, yes. If you're shaky on some or lots of the content, it will take longer. You might find some gaps in your knowledge that take lots of time to fill, and you need to build in time for that. My advice is to start earlier than that. Then you can feel confident you'll have time to deal with the issues that arise

[@vanshikabhatia7020]

at 51:43 you added 3/2 o2 on both sides. Why did you need the fraction when the equation was already balanced? couldn't it just be o2

[@chemistrytutor]

There are 4 oxygen atoms in CO2 and 2H2O at the bottom and only 1 in methanol do that's why we needed another 3 oxygen - hence the 3/2 O2. With respect to the reactants at the top, you're right really- 3/2 O2 and 1/2 O2 is really 2 O2

[@mira98kkhh]

@@chemistrytutor so could the equation just be C + 2H2 + 1/2O2 -> CH3OH + O2 instead of the fractions you used sir? at 51:43

[@chemistrytutor]

@amirah175 for the equation you've written there are 3 oxygen on the right but only one on the left. You'd need an additional O2 on the left, which is why I combined them into 3/2 O2

[@lina-pz3oy]

Your just the best🎉

[@chemistrytutor]

Thank you 😊

[@국햄]

can you go through this topic with exam questions? cause i want to apply what i have been taught from this video with your proper explanation

[@chemistrytutor]

kzbin.info/www/bejne/nobYmoywoLGDpNk This is a calorimetry question walkthrough. I'll do more including multiple Choice questions before too long 😃

[@Abdu1Mui2]

Thank you so much Your vids are amazing!!!

[@chemistrytutor]

That's lovely feedback! Hope chemistry is still going well!

[@Eshaal-y3g]

15:43 why would the temperature return back to 298 K? Also your videos are amazing

[@chemistrytutor]

Thank you, that's very kind! What I meant was - the temperature begins at 298K and after the increase or decrease in temperature, it will eventually return to 298K again once the reaction has finished

[@Eshaal-y3g]

@@chemistrytutor thankyou

[@mashiatislam2036]

is this applicable for cambridge students?

[@chemistrytutor]

CIE A level? Yes definitely 😀

[@khizranfatima4910]

@@chemistrytutor Does this cover A2 chemistry or only AS?

[@chemistrytutor]

@khizranfatima4910 this is just AS. Thermodynamics 1/2: kzbin.info/www/bejne/fqXMlHisnLFohMk

[@OmarAhmed-iz5vr]

I've understood more in this video than in class

[@chemistrytutor]

That's great that it's useful!

[@justsomeone5660]

Thanks a lot sir

[@chemistrytutor]

😀👍

[@Masowe.]

thank you sir, this was stressing me out but i get it now

[@chemistrytutor]

Excellent! Some of these topics take practice. Especially ones with loads of skills and calculations

[@Masowe.]

@@chemistrytutor I was trying to practise but I found myself running out of knowledge so maybe it's time

[@chemistrytutor]

@@Masowe. 🧐 maybe

[@axmiire5410]

thank u soooo much

[@chemistrytutor]

Most welcome 😊

[@Softplug237]

Thanks

[@chemistrytutor]

😀👍

[@dannnzyyyyyyy]

Where were u 2 days ago😭😭

[@chemistrytutor]

Hang in there!

[@alibea_1208]

thank you !!!!

[@chemistrytutor]

Very welcome 😀

[@adnansakeeb739]

,-, wow... That was easy...

[@chemistrytutor]

Excellent! That's the dream 😃

[@mohammedalloghani2699]

Thank u 😭

[@chemistrytutor]

Hang in there! You can do this 😁