Distributed loading on a beam example #4: composite shapes

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Engineer4Free

Engineer4Free

Күн бұрын

Пікірлер: 16
@montserratzuniga1490
@montserratzuniga1490 2 жыл бұрын
me encanto tu video a nadie de habla hispana le entendí, mas que ti gracias por subir videos de este estilo
@eume9412
@eume9412 4 жыл бұрын
Where is the previous video of this topic? I want to know how to find the centroid of the parabolic load.
@Engineer4Free
@Engineer4Free 4 жыл бұрын
The full playlist is at engineer4free.com/statics. This is video #65, so you'll want to at least check out video #64
@ajsa1111
@ajsa1111 4 жыл бұрын
Thank you for such great video.
@Engineer4Free
@Engineer4Free 4 жыл бұрын
You’re welcome, thanks for watching!!! 😁
@commander9173
@commander9173 4 жыл бұрын
Sir Its really very helpful 😊👍👍👍👍
@Engineer4Free
@Engineer4Free 4 жыл бұрын
Great!!! you can find the whole playlist here: kzbin.info/aero/PLOAuB8dR35oeXMk2C5fjHP2K306hGfk_w =)
@MrEpicPwnage1
@MrEpicPwnage1 6 жыл бұрын
Thanks, great explaination -- very clear!
@Engineer4Free
@Engineer4Free 6 жыл бұрын
Thanks for watching and leaving a comment! :)
@lukecaetano8405
@lukecaetano8405 4 жыл бұрын
Thanks bro almost done with this class XD
@Engineer4Free
@Engineer4Free 4 жыл бұрын
Nice!!! Hope it ends well for you =)
@kieranpennesi5994
@kieranpennesi5994 4 жыл бұрын
how did you know the function of that parabola was x^2
@Engineer4Free
@Engineer4Free 4 жыл бұрын
\I should have explicitly stated the function in that section as y=x&2, but I forgot to. I just meant to do an example with the simplest possible parabolic shape, which is what I used. To check, you could realize that knowing its of parabolic form, and that at x=0, y=0, and x=5, y=25, that if y=x^a, then a=2 for this function to work. But sorry, I should have clearly written it on the screen to reduce ambiguity ✌️
@alex.axel-poppa9914
@alex.axel-poppa9914 3 жыл бұрын
Very helpful!!
@bradzepfan
@bradzepfan 6 жыл бұрын
you are awesome keep up the great work!
@Engineer4Free
@Engineer4Free 6 жыл бұрын
Thanks bro!
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