Channel Capacity by Shannon-Hartley | Basics, Proof & Maximum Bandwidth Condition

[@EngineeringFunda]

*🔥All Premium Courses Link of Engineering Funda🔥* docs.google.com/spreadsheets/d/1LeLxZPGiMB_ZDZggbZp3P7fK516pXYhVgZA__djNkWM/edit#gid=0

[@EngineeringFunda]

At last Limit x tends to 0, (Log base2 (1+x))/x = (log e)/log 2 = 1.44 I did small error, in that I wrote 1/x in denominator, I will remake this video soon.

[@bharathinadipilli1703]

Ok thanks you sir 😊 your lectures are good sir

[@emilioreign6391]

i guess it's quite randomly asking but do anyone know a good website to watch newly released series online?

[@rodrigodarian3357]

@Emilio Reign Flixportal :P

[@emilioreign6391]

@Rodrigo Darian thanks, I went there and it seems to work :D I appreciate it !!

[@rodrigodarian3357]

@Emilio Reign No problem :)

[@EngineeringFunda]

⬇ *Premium Courses of Engineering Funda* ⬇ ✅ *༺🚩ARM Processor 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e7nFEozQhZDZDSm09SwqbGP ✅ *༺🚩Microprocessor 8085 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e5vHwmowy_kGtjq9Ih0FzwN ✅ *༺🚩Microprocessor 8086 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e4oAeDid0hwuiol_RJdscrp ✅ *༺🚩AVR Microcontroller 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e55CdbY_WnY6pejPHoojCkJ ✅ *༺🚩8051 Microcontroller 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e49i6neo70aGtFLvKeZ3IQD ✅ *༺🚩80386 & Pentium Processor 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e7f4yPj6AbrUoburKwX0fFA ✅ *༺🚩Embedded System 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e5xvXygtghfi-tzyeACx7CO ✅ *༺🚩VLSI 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e6au9bX9P_bA3ywxqigCsaC ✅ *༺🚩Digital Electronics 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e7nYSG31YWEUfwgAp2uIOBY ✅ *༺🚩Network Theory 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e7AccPu8mUhhsJNol9uIKTJ ✅ *༺🚩Control Engineering 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e43et6qbo4IqYSJCv-6kN90 ✅ *༺🚩Electromagnetic Theory 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e4I_YltJja47CwZJkzNWK89 ✅ *༺🚩Power Electronics 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e5Hnu82T1CYLZ8kbZs4Jx8x ✅ *༺🚩Basic Electronics 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e5G05PTgyTTSVyzTOKRfmTn ✅ *༺🚩Signal and System 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e7VdLw7PebRTcZXb_4nKeVh ✅ *༺🚩Optical Communication 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e7CDIWsh61eItP9iRw1EIQc ✅ *༺🚩Analog Communication 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e7uyUYrpgUUQowmRuKxRdwp ✅ *༺🚩Digital Communication 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e5PngHbdEadEun5XPvnn00N ✅ *༺🚩Antennas & wave Propagation 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e7tzLIDL4aXUbtRFY3ykmkT ✅ *༺🚩Microwave Engineering 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e6A4Mtxud6xPHE1UecxWsHW ✅ *༺🚩RADAR Engineering 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e4KmA52Jw3-JhDhFIDQZ9Bv ✅ *༺🚩Audio Video System / TV 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e7EJcPI0P_DMw49ufTYfuOz ✅ *༺🚩Engineering Drawing/ Graphics 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e79xuABrIQeXYlGuuickEz7 ✅ *༺🚩Basic Mechanical Engineering 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e7Fe4vAYDaL0bpseGNhc9on ✅ *༺🚩Mechanics of Solid 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e53xcLCS7ay2iLRolNxyxFk ✅ *༺🚩Theory of Computation 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e6GfXdwqWX5YmszV2KGv-yl ✅ *༺🚩Java Programming 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e5BeN1WTXg1ENPtkRR3SfCI ✅ *༺🚩Python Programming 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e5pY2eB-Lht2_CerQue0Xo4 ✅ *༺🚩Placement Test series on C 🚩༻* - kzbin.info/aero/PLgwJf8NK-2e5ovLgoJkv0Pn58UrucrTPt ✅ *༺ Please Share it with your friends to support us. ༻* 👉 *༺ You can also support us by joining us ༻* : kzbin.info/door/dlnqMpRrMcClK2fT6z8EEwjoin

[@bubusharma9135]

I gave the 200th Like. 😎 Awesome and quick explanation.

[@johncarloroberto2635]

S Latha is correct, it should be lim x -> 0 of log2(1 + x)/x = log2(e)

[@exporter_malhartraders]

You are great ....thankyou so much❤

[@EngineeringFunda]

All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us. Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏

[@reddiindraja1745]

One can understand in one lecture .... Thank u sir

[@EngineeringFunda]

Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.

[@shahnawazhussain3443]

Thank you sir for this..

[@EngineeringFunda]

Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏

[@sumitdebbarma1209]

Sir i am not able to find source coding theorem in your channel. Could you please share a link if topic on this video is available in ur playlist.

[@kailashprajapat3985]

Is there any other method to prove this theorem using probability Dencity function

[@arutselvan2471]

Thanku sir for great teaching it is understandable good sir ❤️

[@EngineeringFunda]

Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.

[@arutselvan2471]

Sure sir ♥️✨

[@CoconutGamer]

A telephone line normally has a bandwidth is from 300 to 3300 Hz assigned for data communication. The SNR is usually 3162. What will be the capacity for this channel?

[@EngineeringFunda]

To calculate the capacity of a communication channel, we use the Shannon-Hartley theorem. The theorem states that the channel capacity (C) in bits per second (bps) is given by: C = B log_2(1 + SNR) where: - B is the bandwidth of the channel in hertz (Hz). - SNR is the signal-to-noise ratio, expressed as a power ratio (not in decibels). Given: - The bandwidth B is from 300 Hz to 3300 Hz, so ( B = 3300 - 300 = 3000 ) Hz. - The signal-to-noise ratio (SNR) is 3162. Let's substitute these values into the Shannon-Hartley theorem formula: C = 3000 log_2(1 + 3162) First, compute ( 1 + 3162 ): [ 1 + 3162 = 3163 ] Next, we need to calculate ( log_2(3163) ). This can be done by converting the logarithm base 10 to base 2 using the change of base formula: [ log_2(3163) = log_{10}(3163)}/{log_{10}(2)}] Using a calculator, we find: [log_{10}(3163) = 3.5004] [log_{10}(2) = 0.3010] Now, divide these values: [ log_2(3163) = {3.5004}/{0.3010} =11.63] Finally, calculate the capacity: [ C = 3000 * 11.63 = 34890 bps ] Thus, the capacity of the telephone line channel is approximately 34,890 bits per second (bps).

[@CoconutGamer]

@@EngineeringFunda thanks

[@philipthecow]

2:34 doesn't explain why the number of levels that can be separated without error is what it is. I think it involves some sort of coding with large hamming distances concept.

[@jogishravani4730]

Osom lecture sir thank you 😊

[@EngineeringFunda]

Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.

[@meghapandey2048]

Thanku sir❤️

[@EngineeringFunda]

Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.

[@selimreza7929]

you are boss in control system.your all tutorial are helpful.please give more vedioes

[@pst7592]

From where the noise came in the ofc cables?

[@em_unnai_ra_trolls5795]

AGWN concept is not used in this proof....?

[@avichoubey9586]

sir aapne jo bhe padhya kuch smjh nhi ayaa , Thankyou

[@kalyanibarapatre4950]

Thanks I understand a bit

[@ethendixon4612]

Good pun

[@enthotipallavi9828]

Please explain the implicants of Shannon Hartley theorem

[@soumalyaghosh6643]

sir what is n (eeta)?

[@beginnersplay947]

Efficiency

[@harshkashyap-wk1vy]

Sir please provide the PDF of information theory.

[@karthikganjam296]

By the way we wont say forty four ....after point

[@lightbinger]

point four four :X

[@আব্দুল্লাহআলমাসুদরানা]

sir i have a math..if bandwidth (300 - 3200), and SNR 20 dB,what is the chAnnel capacity and,here which bandwidth

[@EngineeringFunda]

Bandwidth is higher cutoff - lower cutoff frequency

[@ajiths1689]

Sir I didn't understand why u take the ration for calculating no of levels of un effected by noise

[@EngineeringFunda]

It is ratio of voltages with noise signal and noise

[@ajiths1689]

But why u have taken like that sir .....

[@ajiths1689]

Means I just want to know how that formula came

[@ajiths1689]

Thanks for your fast reply... For previous comment

[@EngineeringFunda]

(Noise + Signal)/Noise = m m should be as high as possible. If m is high then we can have more number of levels in qauntized signal. Practically it shows levels can be detected without error. By writing here it is difficult to explain but if you draw it then you will get it exactly.

[@FFGAMING-dr4dh]

Sir do channel capacity of Gaussian channel and channel capacity by Shannon same sir ?? Reply fast sir tmr i have external exam

[@suyeshmenon7810]

What happened ur exam bro

[@slatha4698]

Lim x tends to zero (1+x)^(1/x)=e

[@hplis]

This is how fast God can think.Assuming God is omnipotent.

[@EngineeringFunda]

Yes, GOD is omnipotent that I feel.

[@jai-hanuman555]

Are diwane God mind se think karega shannon Hartley theorem se nahi

[@nandinikose1414]

👍

[@EngineeringFunda]

Thanks and welcome

[@nayansurani1192]

Sir, i think some mistake in log2e's formula...

[@EngineeringFunda]

It's correct

[@prachinainawa3055]

@@EngineeringFunda how did u applied the formula of log e? I'm also confused here.

[@VayunEkbote]

@@EngineeringFunda Equation is of the form :- log₂ e(1 + x) / (x), in this case. But you have considered the formula for log₂ e(1 + x) / (1 / x). Please check.

[@mdsaddamkhan8400]

Clear

[@pritampaul3508]

eng mat bola kariye sir...na ap atche se samjha pate hay..na hume samajh ata he..adha adhura reh jata he..ya to apke khud k concept clear nhi hay .ya fir eng kamjor hay

[@harshitsingh4764]

S/nb = x, Then 1/x= nb/s but sir you used above expression in that expression of limit.

[@Googlinghelpers]

Savdhan this channel is for ece ,cse wale durr rahe ye sir cse walon ke liye nhi hai we don't know abc of ece and he assumes we know everything and yha pr time pass ke liye aayen hai 8:32

[@karthikganjam296]

U r wrong with limit .......

[@ajiths1689]

Please say me sir

[@johnpeter6779]

sir plz improve your teaching skill first then teach

[@EngineeringFunda]

Ok

[@prachimohnot5454]

Why u being so rude? U could have just said that u didn't grasp the concept. Or watched another video.

[@devanshdalwadi6015]

If u want to see then see else leave

[@RJ14RIDERR]

sir i am them sure, that u don't know how great tutor u are 🫡🫡

[@EngineeringFunda]

Thank you so much 😀