my teacher explained epsilon-delta proofs in a really confusing way, so I thank you so much for doing this series! You are literally a hero!
@ShivanshTiwari-yn8wd2 жыл бұрын
I really like his enthusiasm in explaining the numerical. Thank you and keep up the good work
@sangwonlee56692 жыл бұрын
I just started my Advanced Calculus(Intro.Real analysis) course and this is a perfect material for previewing. I appreciate your lecture, Dr Peyam
@drpeyam2 жыл бұрын
Thank you!!!
@drpeyam2 жыл бұрын
You should check out my advanced calculus website: people.tamu.edu/~tabrizianpeyam/Math%20409/math409.html
@sangwonlee56692 жыл бұрын
@@drpeyam I cannot thank you enough for this fascinating professional free content!
@Mryeo53544 жыл бұрын
Im six videos into your continuity playlist and I really appreciate the practice. Thank you
@drpeyam4 жыл бұрын
Thank you!!!
@adityadwivedi44123 жыл бұрын
@@drpeyam how is this 8 months old?
@jamesbentonticer47063 жыл бұрын
It's easy to binge watch his videos isn't it.
@speckpackgamer2 жыл бұрын
Dr. Peyam i kiss your heart de idea with |a| >= -a is ingenious this is where i struggled in my proof but now you have explained it very well and i gave the video a like
@drpeyam2 жыл бұрын
You’re welcome 😊
@speedbird75878 ай бұрын
Thanks for the fantastic video. I got a better intuition about the pointwise vs. absolute convergence.
@NihilistEmier3 жыл бұрын
I'm bad at maths that's why 2n + 2n is 4n(foreign) for me
@wtt274 Жыл бұрын
A beautiful proof .Thank you sir for the great video !
@rjbeatz3 жыл бұрын
Hey, I am studying as an Electrical Engineer and I love your videos!!! Also, do you have armenian or iranian roots? Cause your last name ends in ian
@drpeyam3 жыл бұрын
Yep Iranian
@adityadwivedi44123 жыл бұрын
This reminded me of the proof that concave functions are continuous on open intervals
@chato93273 жыл бұрын
Thank you so much for your videos Dr Peyam =D
@billyhadinata46443 жыл бұрын
7:20 where do you find |x| > |xo|/2 ? thanks!
@lordstevenson96193 жыл бұрын
I would love a 3B1B visual proof of continuity and limits would be great if it’s possible.
@drpeyam3 жыл бұрын
Already done, check out the playlist
@yoav6133 жыл бұрын
you managed to show continuity by yourself! blackpen redpen needed pikachu
@harrik24653 жыл бұрын
Thank you, great videos!
@juancamilochavesmuneton46012 жыл бұрын
Why in the step 2, when you're showing that Delta really works, you use first |xo|/2 as Delta but then use the other Delta. My doubt is: if in the proof I say that |X-Xo|
@weiwei92x2 жыл бұрын
Hi Dr Peyam, could you explain a bit more why we necessarily need step 2? By the end of step 1, we've already shown the choice of delta will satisfy epislon requirement, right? Or is that because epsilon can be anything, that's why there is a possibility that there exists an epsilon which invalidates our assuption of x-x0 less than x0/2 ?
@drpeyam2 жыл бұрын
No in step 1 we found our guess for delta, it’s in step 2 where we show that our delta actually works
@shashwat220723 жыл бұрын
I gave u the 100th like sir❤❤
@drpeyam3 жыл бұрын
Yay!!!
@wanchoi4072 жыл бұрын
Hi, Dr. Peyam. Appreciate and like your lecture! Allow me ask a quick question for you. At 06:14, how do we know 2*|x-x_0|/|x_0|^2 is less than the epsilon?
@drpeyam2 жыл бұрын
We set it less than epsilon, since that’s what we want, and this gives us our delta
@johnbarnes4596 Жыл бұрын
why didn't you use Xo to be 3/2Xo
@iqrarali46313 жыл бұрын
Kindly explain limit x->0 squaroot of X .
@drpeyam3 жыл бұрын
Already done
@iqrarali46313 жыл бұрын
@@drpeyam I couldn't find kindly share link if possible thanks
@JasonOvalles3 жыл бұрын
Is this what you were looking for? kzbin.info/www/bejne/mpuWc3RvbruKrLM You can find it next time by looking at the videos in Dr Peyam's channel. He's pretty well organized with his videos and playlists!
@MathCuriousity Жыл бұрын
But I saw another video saying 1/x is not uniformly continuous for x belonging to open interval (0,1)! Your domain includes everything in 0,1 except 0. So why do you show uniform continuity here but yet the other video says it id not continuous ?! Thanks!
@desertpointshacks6299 Жыл бұрын
1/x is continuous but not uniformly continuous on (0,1]. Uniform continuity is a stricter condition which is not always satisfied. Intuitively the reason it fails to be uniformly continuous is that its graph becomes arbitrarily steep as x approaches 0. There is no universal value of delta that will work for all values of x0 for any given epsilon.
@theproofessayist84413 жыл бұрын
Dr Peyam since you are a PDE expert - please do a video on the glorious crowning theorem of ODE and PDE analysis please: that is of course, the Sturm-Liouville Theorem! :)
@drpeyam3 жыл бұрын
I don’t think it’s that important, I never use it
@theproofessayist84413 жыл бұрын
@@drpeyam Ah really? Then what in your view is the most important theorem in ODE/PDE?
@adityadwivedi44123 жыл бұрын
@@theproofessayist8441 no single result alone can do anything mathematics is much vast
@drpeyam3 жыл бұрын
^ Exactly, pde is such a vast field, there is no fundamental theorem of pde
@theproofessayist84413 жыл бұрын
@@adityadwivedi4412 This reminds me so much of one of my math professor's commentary on the interpretation of Godel's Incompleteness Theorem as stated in Douglas Hofstadter's Godel Escher Bach Eternal Golden Braid. Even if it's impossible to prove everything in a logically consistent system without there being any contradictions - that means there's always more to discover and so mathematicians will never run out of a job - haha :).
@calcuquack12063 жыл бұрын
wow
@rajputzadii-b4e3 ай бұрын
show that f (x)=1/x is continuous at 1 DR peyam will get the this question solved plz my humble request