Why do I love exam solutions? Simply it’s amazing especially when you’re stuck in a question and have no one to ask!!!!!
@joshuamallon618311 ай бұрын
you sound happy as mate u really make revising fun . u the man appreciate ya !
@andydaniels6363 Жыл бұрын
The point-normal form of equation of a line (i.e., n·x = n·p) seems more convenient and less error-prone in this application. For instance, to find the equation of the perpendicular bisector of AB, we compute n = B-A = (7,-1) and the midpoint p = (A+B)/2 = (3/2,3/2), yielding (7,-1)·(x,y)=(7,-1)·(3/2,3/2) or 7x-y=9.
@ameliamos2 жыл бұрын
i think ill actually get this question right on exams now thank you
@nirmitchanana62095 жыл бұрын
Could you please go through the edexcel a level 2019 mock exams please
@cfgauss715 жыл бұрын
Outstanding explanation! The intersection of the chords' perpendicular bisectors is the key!
@AkashManick-h6r12 күн бұрын
Do we get this in A level Cambridge exam
@sadmanzaid4204 жыл бұрын
Alright I'm feeling charitable so if any of you noobs are finding this hard then may I suggest a more formulaic approach? 1) Consider the general equation for a circle : *(x−x₁)²* *+* *(y−y₁)²* *=* *r²* Plug in the three points to create three quadratic equations. 2) Now there should be 3 equations like: *(x−a)²* *+* *(y−b)²* *=* *r²* *①* *(x−c)²* *+* *(y−d)²* *=* *r²* *②* *(x−e)²* *+* *(y−f)²* *=* *r²* *③* 3) Subtract the *①* from the *②* which will create another equation that's linear, call it ④ and subtract ① from ③, call it ⑤ 4) Solve the two Simultaneous linear equations: *ax* *+* *by* *=* *c* *④* *dx* *+* *ey* *=* *f* *⑤* which will give you the center coordinate points of the circle. 5) Last step is to plug the center points into any of the ①, ② or ③ equations and solve for *r* and the rest is history.
@sadmanzaid4204 жыл бұрын
The 3 quadratic equations forms 3 circles that all intersect at the center of the main circle which you're trying to find, after you derive 2 straight line equations from the non-linear circle equations those lines also intersect at the center of the circle which ultimately provides you the center coordinates of the circle.
@michellesilva73664 жыл бұрын
Woooooowww thanks a lot!
@michellesilva73664 жыл бұрын
But how do you find the radius of all 3 equations?
@andreideiu33504 жыл бұрын
Hey bruh I need your help
@NaveenReddy-vm3ps4 жыл бұрын
@@michellesilva7366 all the three equations are of the same circle, so obviously the radius in each equation is the same and is that of the circle that we are trying to find!
@file43182 жыл бұрын
ahhh such an amazing video thank you!!
@ExamSolutions_Maths2 жыл бұрын
Glad you liked it!!
@hesterclapp97172 жыл бұрын
Is there a way to calculate a circle from point A, point B and a tangent passing through point A?
@mxxced11 ай бұрын
1 year late so this is mainly for anyone else reading but you can use the method in the vid for a line from the midpoint of AB through the centre and the question should give the equation of the tangent/ 2 points on the tangent, so you can do the negative reciprocal at A then set the two equal and solve.
@syp80905 жыл бұрын
2:57 how did you know that was the center?
@ExamSolutions_Maths5 жыл бұрын
The centre of a circle always lies at the midpoint of any perpendicular bisector of a chord of a circle.
@abdul-kadersouid5152 жыл бұрын
Outstanding; thank you
@johnlynch99405 жыл бұрын
Is this still relevant to the AQA spec? I’ve not come across it at all
@hamzahhussain65805 жыл бұрын
i do edexcel, but i have only come across a question with 2 points
@naveedhasan67383 жыл бұрын
Thank youu from Bangladesh
@noahalton50585 жыл бұрын
excellent explanation my brother.....
@AfricanTalesByMum2 жыл бұрын
you are the best you have made me understand this concept
@kakashi24095 жыл бұрын
You videos are very helpful sir. I hope you continue to upload more content. From India!
@ExamSolutions_Maths5 жыл бұрын
Thank you. Yes I hope to continue providing people keep supporting this work.
@princesstrayvilla34884 жыл бұрын
Hey! Can I ask about the gradients? If the gradient is positive, does it become negative as a perpendicular gradient?
@sallywinston53054 жыл бұрын
Yeah. You can use this: gradient of eqn (m1) times perpendicular gradient (m2) = -1. If you make the perpendicular gradient the subject, then you can see how it changes signs and 'flips'.
@brandongudoy17084 жыл бұрын
What if it doesnt have vertical or horizontal line? What formula is needed?
@ExamSolutions_Maths4 жыл бұрын
Are you referring to the chords? In this example, the chord AB is not horizontal., and its perpendicular bisector is not vertical. The only formula required for this question is the equation of a circle (x-a)^2 + (y-b)^2 = r^2, where (a,b)is the centre of the circle and r is the radius. The centre (a,b) is found at the intersection between the perp bisectors of chords AB and AC.
@Chloe-gc5sh4 жыл бұрын
@@ExamSolutions_Maths oh so like we could still do the same thing even if the chord is not vertical?
@cathalodonnell91102 жыл бұрын
Thans mate
@shirufaith56254 жыл бұрын
nice work
@itsshreyshrey15085 жыл бұрын
Thank you for making maths videos for us! You have helped me raise my grades a lot! ❤️
@bhagyaamarasinghe46734 жыл бұрын
Thank you so much. This helped me a lot. :)
@ExamSolutions_Maths4 жыл бұрын
That's good. Best wishes
@omaribrahim34815 жыл бұрын
Can you please do worked solutions for M1 IAL past papers? Please, I really need your help. All of your C12 solutions were super useful
@ahmetlushi20095 жыл бұрын
How many marks would these sort of questions be worth in a typical exam ?
@gutsmcgordan41844 жыл бұрын
Can i apply this same logic with 4 points given?
@alster7243 жыл бұрын
Nailed it in 5:30 (5 mins 30 seconds)
@ronskie93244 жыл бұрын
Thanks for saving my life, sir
@ExamSolutions_Maths4 жыл бұрын
Good to hear. Best wishes.
@glorietatabillabandolon32325 жыл бұрын
Thank you
@ridzwansaiful27353 жыл бұрын
This help a lot !! Thanks ;)
@ahnafjawad772 Жыл бұрын
HAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAHHHH, thanks been dying over a sum like this
@zagi02074 жыл бұрын
Chrystal-clear explanations; wonderful!
@karanjha71174 жыл бұрын
Excellent concept . Keep going, very helpful
@janiceibanez16094 жыл бұрын
I just want to ask if this is the standard equation of the circle passing 3 points
@ExamSolutions_Maths4 жыл бұрын
This is a standard method of finding the standard equation of the circle passing 3 points as opposed to the standard equation of the circle passing through 3 points.
@janiceibanez16094 жыл бұрын
@@ExamSolutions_Maths thank you 😘😘
@NTEdits374 жыл бұрын
Thank you sir super teaching
@falahzainab26334 жыл бұрын
Thanks for the help❤️❤️❤️❤️!!! I have my As maths exam tomorrow
@elyzajanemondaya51013 жыл бұрын
😊 thank you so much
@zachpaterson81284 жыл бұрын
I might be going crazy but didn't you do the slope formula backwards? Normally it's (Y2-Y1)/(X2-X1)
@ExamSolutions_Maths4 жыл бұрын
You and I are correct. It will give the same answer, try it.
@zachpaterson81284 жыл бұрын
@@ExamSolutions_Maths Does it always work both ways? Or is this just one of those happy coincidences?
@ExamSolutions_Maths4 жыл бұрын
@@zachpaterson8128 It is not a coincidence. It depends on what you call X2 and Y2. Somebody else may call your X2, Y2 there X1, Y1. If you multiply top and bottom of the fraction by -1 you will see that (Y2-Y1)/(X2-X1) = (Y1-Y2)/(X1-X2)
@S123-x5b3 жыл бұрын
@@ExamSolutions_Maths their*
@Krystal-sg9ji3 жыл бұрын
You're a lifesaver ❤️
@davidhill81633 жыл бұрын
Much better update of this question in higher resolution
@lorrainemudzamiri6463 жыл бұрын
Thank you very much this help me
@vegsamosa3 жыл бұрын
FINALLY someone who's not American 🎉
@michellesilva73664 жыл бұрын
Thank you soo much
@maxo40673 жыл бұрын
how many marks do you think this question would be worth in an exam?
@andreideiu33504 жыл бұрын
Sir
@dimitredixon33964 жыл бұрын
Yo thanks dawg ya help me
@muradkhammassi6274 жыл бұрын
Thanks my name is murad and my teacher has an impala the size of my future
@ohmy92613 жыл бұрын
A what?!?
@wipcreme4 жыл бұрын
STEM PA MORE
@ShiroKage-h8v3 жыл бұрын
this is too complicated
@jankira20434 жыл бұрын
I think u made the gradient ab wrong its y_2-y_1 not y_1-y_2