Equation of a Circle Through Three Points

[@innes4060]

Much more helpful than my PreCalculus teacher

[@NightingaleFlorine]

Thank you so much sir! I have an examination tomorrow and not solving this question would have made my anxiety skyrocket. Your answer has been of extremely great help ^^

[@edpagan5421]

5:26 divide by 2 because I can😎; love it, and it is so true

[@MK-ww4lb]

very clear, in my opinion NO need to do the part from 4:33 to 5:40. go directly to find X from bisectors equations.

[@Loaderdani]

Way too fast for me, but with a bit of pausing I got through it. Brilliantly clear. And a very pretty example. I tried with a circle of circumstance 5 and center (1, 3) and the fractions do not simplify so tidily.

[@sanjitsaravanan5303]

thank you so much man you're really helping a lot of people

[@hodafarid3019]

I actually found this very helpful! clear and straight to the point thank you!!

[@connordunne560]

Thanks helped a lot unlike most videos I've seen

[@mercytendai6714]

Very precise and short. Good work

[@hikmeterdogan2513]

what software are you using? It looks awesome!

[@sai.g1]

Thank You So Much! This was so helpful!!!

[@MikhaelAhava]

Thanks, would help me in pre calculus.

[@Opticalresolution]

saved my life and my time!

[@dikeledimary7537]

It really helped me a lot Thank you 😁

[@TheGuyWhoAsked72]

That test tomorrow looking extra spicy 😅

[@turksvids]

Hope it went well!

[@TheGuyWhoAsked72]

@@turksvids I got an 92% on it 💪

[@turksvids]

Awesome!

[@nikhilbhasin2095]

Why do you do the negative coefficient of the gradient, which bit of the circle is perpendicular?

[@turksvids]

The center of the circle can be found by intersecting the perpendicular bisectors of the chords of the circle. So we find the equations of the perpendicular bisectors of the chords. Perpendicular lines have slopes that are opposite reciprocals, that's where the negative is getting involved. (I think this answers your question but I'm not 100% sure...)

[@tianjinghan1]

It is a right triangle, due to the two slopes of 1 and -1. The center is the circle is the mid point of the hypotenuse, which is (8,1).

[@turksvids]

That's useful for this particular problem, but is it useful in general for solving this sort of problem?

[@dihydrogenmonoxide6748]

Question, will any segment work??

[@turksvids]

Any segment created from two points on the circumference will work as a chord.

[@dihydrogenmonoxide6748]

@@turksvids thanks!

[@princesstrayvilla3488]

hey! uh how did you come up with x-y=7? isn't it supposed to be x+y=7? how did 2y become negative?

[@turksvids]

I didn't move things around the way most people do on that one. I really had 14 = 2x - 2y from adding 13 to both sides and subtracting 2y from both sides, but then rearranged it to get 2x -2y = 14, then divided through by 2. (Basically I just kind of "move things" however I find it most convenient and I prefer positive numbers for whatever reason...) Hope this helps!

[@princesstrayvilla3488]

thank you so much!! this helped a lot..

[@omarbedward]

Thank you so much

[@ilovetiananmen]

Very nice! Thank you!

[@katemoon7476]

What about the general formula?

[@turksvids]

If you follow along with everything in the video you can get the general formula by expanding everything, moving everything to one side, and collecting like terms. Hope this helps!

[@Taol127]

Thanks for the help

[@letsdothis7619]

What if your perpendicular slope of one line is vertical

[@turksvids]

Shouldn't really be an issue. If one of the slopes ends up undefined, then the line is definitely vertical, which means you already know its equation: x = k, and then you can go from there using substitution to solve for the center. Hope this helps! (I think it answers the question...)

[@empressomeletmatcha7078]

Why would it become +14 when it just came outta -13-1?

[@turksvids]

at 5:20 I explain what I'm doing. I moved the 2y to the right and the -13 to the left side...it's kind of the opposite of what I think most people would do but it avoided a lot of negative signs getting involved. Hope this helps!

[@smritigupta3133]

Thank you Sir !!

[@عبدالرحمناحمد-ب5ذ4ب]

Amazing

[@nickspanoudakis6776]

I see why you chose AC instead of BC. Having one of the midpoints be the center confused me when repeating this. Good video

[@willbillthedill3883]

thank u maybe i wont fail this test

[@micah1464]

What if you can't cancel out a y or x value? 5:35

[@turksvids]

You can use any of the techniques mentioned in the document (there are links to videos) at this link: drive.google.com/file/d/0B11F_FpivrRiUWM0UDlHZWdSYXc/

[@alster724]

Used Algebraic method

[@aszxs1847]

i love you

[@Brook_alx]

Slow down a bit when you talk...

[@turksvids]

I'm sure you're aware you can slow down a video and that it's likely easier for you to do that than for me to change the way I speak, right? If not, you can hit the gear and change the speed of any video. Give it a shot!

[@Brook_alx]

@@turksvids ✌

[@gamerzzchannel1499]

Even if this is correct some people can't catch up to you... You talk to fast just like my math teacher.. i can't understand any equations and solutions you used whilst talking.. Good video btw

[@turksvids]

You seem like a person who doesn't understand that videos can be played at different speeds. Perhaps try slowing it down? Hit the gear? Pick a different speed? There are plenty of people who can understand at the current speed, some who speed it up, and some who slow it down. Take the initiative instead of complaining. Thanks for the comment btw.