Equation of tangent to Circle x^2+y^2-8x-10x-128=0 IB Math GCSE -GCSE-EDEXCEL-SAT

[@OpaiGipints-w2n]

This is very clear explained...i really love it ....because it will help me with the exam coming tomorrow.

[@ssgrazer1162]

To find center of a circle in standard form and general form like the one used in video, just take derivative w.r.t x or y term of circle. For example: x²+y²-8x-10y-128=0 For center C(h,k), i need h so i will take derivative w.r.t x. So, 2x+0-8-0-0=0. (EVERYTHING except x will be treated as constant term) (remember it is for this scenario only that we treat y as constant and not y' ) 2x=8. => x=4 For k, take derivative w.r.t y, 0+2y-0-10-0=0 2y=10. => y=5 Hope it helps.

[@samuelmoges4606]

that is sick

[@dhsanurag9229]

More easy method Just multiply the coefficient of x and y by -1/2 , to get coordinates of cente You don't need to differentiate at all!

[@taiworoqeeb2726]

Thanks but how then do you find the radius?

[@MirzaRaza-e1b]

Very helpful 🙏🙏🙏🙏🙏 cleared all the doubts Thanks a lot Anil sir

[@jaycee4911]

Thanks..... you're the best..... you've explained excellently

[@simiyukevin1727]

Thanks so much Mr.Kumar

[@kalkidanyishak221]

thank you so much this man is saving lives

[@andrewkasonde734]

You're very smart at explanations thank you've really helped me 🙏🙏🙏

[@aastramento3802]

Nice vedio sir 🎉❤

[@johnterry546]

Thank you very much sir I must say I enjoyed your lecturing, ❤❤❤ your English is amazing

[@MathematicsTutor]

Thanks for appreciation

[@billharm6006]

Call me overly cautious, but I would first check that the desired point of tangency is actually on the circle (I checked. It is).

[@MathematicsTutor]

Correct

[@tumininuodusanya4228]

This really helped me, thank you

[@tejaswininegi5826]

Thankyou sir you explained very well🙏🏻

[@prabeshmandal1674]

Thank so much for your help

[@mohammadjonashkhanm.1439]

thank you prof God Bless

[@Dien-g3w]

Why are you using the coordinates of the point and that of the centre to find the slope of the radius??

[@janetminong3462]

Thank you Sir that was really helpful.

[@MathematicsTutor]

Thanks for appreciation

[@aisuiro.cellist]

So useful!

[@masto6847]

best ever

[@amyalexander7360]

very helpful sir!!

[@emmanuelcherepromise6380]

Please sir how did you know that the tangent line will be drawn at that point

[@bhumaiah]

Sir, shall I use to get tangent equation directly from given circle equation by this way: x*{-8} + y*10 - 4{x-8} -5{y+10} -128=0 which implies 12x - 5y +146 = 0

[@ODHIAMBOPETEROWINO]

So does it mean that the equation of the normal line to the circle is the same as the equation of the radius

[@EnchongM-x5v]

Thanks!😁👌

[@kingsleylevi8519]

Thanks it really helped

[@ebronmfunka6714]

Nice explanation

[@ChiomaDike-on4ty]

Very helpful 💚

[@phetztalon7698]

-5² is + 25 right? The radius mas be the squareroot of 119

[@matarijuan]

Hello, I'm having a question which is more of the same like that but a bit different,. Find an equation of each tangent line drawn to from the point (5,1) to the circle x^2 + y^2 = 14. Please I need my feedback.

[@mariak2523]

Yep, this one please!!

[@Dark_matician]

5x+y=14

[@dtns3683]

Thank you sir

[@sangaychodup2024]

Find the equation of the line passing through the center of the circle x^2+y^2-4x-2y-6=0 and the point (3, 2)

[@wesleykipkoech1064]

Thanks so much,

[@vfxjmb]

Thanx sir

[@thefrenchrevolution5578]

dude you saved me, questions can we send fanmail?

[@ashayadav2672]

Hello sir .... please share few qs related circle .. which possibility comes in exams

[@MohammedNyawa-k7o]

Nice one

[@MathematicsTutor]

Thanks

[@title_g]

Can you write the final equation starting with 'y' instead of '0' ?

[@MathematicsTutor]

Yes, you can. Thanks

[@sumeshrana4832]

2x + 3y + 4)(2x + 3y - 5) = (ax2 + by2 + 2hxy + 2gx + 2fy + c) how we can find the value of a b h g f and c faster sir if you know then tell me in comment i get the answer sir please clear my doubt

[@sublime681]

Sir it's y-5=12/5 (x-4) Last step

[@amitsharmaknowledgepoint6632]

M1 =12/5 how

[@henokmercury]

Thank you, but i don't understand well

[@MathematicsTutor]

We found the centre by completing the squares first. Then the equation of tangent as it is perpendicular to the radius. Hope that helps. Thanks

[@Vibriooooooo]

Obtain the equation of the tangent to the parabola y 4x 2  which is parallel to the line y  2x  0 and find the coordinates of the point of contact