FINDING EQUATION OF CIRCLE WITH CENTER AND TANGENT LINE

[@Hmmm-w2w]

What's the name of the formula for your radius(r)?

[@MATHStorya]

No name…just the process…

[@dv.1krim]

It is similar to "Point to Line Distance Formula"

[@yanjemie]

how about the center is not given then the tangent line is x+y=2?????

[@MATHStorya]

Give me the problem?

[@grantdeguzman5142]

what if only 0ne center? and given the center of tangent?

[@MATHStorya]

Whats the problem?

[@sheinamandapiton]

hello sir, may i ask if my answer is right

[@sheinamandapiton]

Find the equation of the circle with the center at (-4,2) and tangent line to the line 2x-y+2=0 h= -4 k= 2 2x-y+2=0 A= 2 B= 1 C= 2 r² (Ah+Bk+C)² over A²+B² = (2(-4)+(1)(2)+2)² over 2²+1 = (-8+2+1)² over 4+1 = (-11)² over 5 = 125 over 5 => r² = 24.2 (x+4)²+(y-2)² = 24.2

[@sheinamandapiton]

paki correct po ako hehe needed lang po

[@MATHStorya]

Whats problem?

[@sheinamandapiton]

hello sir, may you check sir if my answer was right hehehe, nasa taas po

[@sheinamandapiton]

Given : Find the equation of the circle with the center at (-4,2) and tangent line to the line 2x-y+2=0

[@rogemmarkperez1892]

Did you forget to get the square root of the denominator; numerator shouldn't even be squared? Equation should be Ah + Bk + C / the square root of A squared + B squared.

[@rogemmarkperez1892]

The answer should be negative square root of 13; or -3.61

[@MATHStorya]

Hello…i am using r² formula so that easy to find the value… that formula you said if you’re solving for r.

[@dv.1krim]

​@@MATHStoryasir, is this formula is for General use? Or you've just made it yourself? Because, in my whole life of reading Geometry, Algebra and any other kinds of book, I've never seen this. It looks like similar to "Point to Line distance formula".I mean, I'm not saying that you're wrong, I'm just asking with all due respect.

[@emilandreisantosislag924]

pano po pag may coordinate points na hinahanap

[@MATHStorya]

What are the unknowns po ba?