6.2a Spring Arrangements and Composite Rods | AS Deformation | Cambridge A Level 9702 Physics

How do combined systems of rods and springs work together to support a load?
00:00 Hooke's Law and Young Modulus
01:48 Series springs
04:54 Composite Rod
07:21 Parallel Springs Sharing Load
10:53 Parallel Rods
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PRACTICE QUESTIONS
ON12 P11 Q23 (pg4) Triple spring
MJ13 P11 Q23 (pg5) Combining springs
MJ13 P13 Q21 (pg6) Strain energy
MJ14 P12 Q20 (pg7) Spring constant
ON14 P13 Q25 (pg9) Double series
MJ15 P11 Q23 (pg9) F-x graph energy
ON15 P12 Q24 (pg11) Steel-brass pipe
MJ16 P11 Q20 (pg12) “Single” spring
MJ16 P12 Q20 (pg12) Spring balance
MJ17 P11 Q21 (pg14) Spring Energy Conversion
MJ18 P12 Q21 (pg16) Spring Constant Graph
MJ18 P13 Q19 (pg17) F-x Spring Constant
FM19 P12 Q20 (pg19) 2 Composite Springs.
MJ19 P11 Q21 (pg20) Composite Wire
MJ19 P12 Q19 (pg21) Four Steel Rods
ON19 P11 Q19 (pg21) Spring Constant
ON19 P11 Q20 (pg21) Area & Work Done
ON19 P12 Q18 (pg22) Total graph extension
FM20 P12 Q19 (pg23) glass & nylon.
ON20 P13 Q20 (pg26) Four Steel Wires
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[@xenon7806]

In parrallel the springs would have same extension, but what if they are made of different materials/ are of different length etc.

[@tahabashir9405]

that would be weird

[@tahabashir9405]

Miss said that it would be a certain ratio

[@abdelrahmanabohasseba3929]

Different lengths are abnormal to carry the same force

[@mahirasifchowdhury7600]

then the load would be distributed in a way to ensure equal extension, i.e. F/k = x so if k(the spring constant) is higher for one of the springs then F(the proportion of the load acting on that spring) will also be proportionally higher resulting in the same x as the other spring. For example if one of the springs has a spring constant of 2 while the other has a spring constant of 4, and a load of 6 N is hung from a parallel arrangement of the two springs, then the spring with k=4 will get 4 N (from the 6 N) while the spring with k=2 will get the rest of the 2 N. So the extension of both springs would be 1 (= 2/2 = 4/4).