Example 1-2 Internal Resultant Loading |Mechanics of Materials by R.C Hibbeler|

[@ericsu6169]

why force at point D no need to be considered in calculation?

[@engradnanrasheedmechanical]

Well you can see that we have been asked to find the internal loading at point E therefore we analyse the beam and all the forces acting on the beam by the members attached to it. Since point D in not in attachment therefore no need to find it. For your own satisfaction you can find it by using equation of equilibrium..

[@enockdadzie2937]

pls on this same question can you go ahead to (1) draw the bending moment and shear force diagram acting on member AB (2) using mid steel of yeild strenght 234Mpa, design the size of the member AB with a factor of safety of 1.5

[@engradnanrasheedmechanical]

Thank you for contacting me I have done it but not in video. Email me so that I can send the picture of your required problem. My email address is [e-mail]

[@engradnanrasheedmechanical]

i wish i could have option in comment section to share the photo....

[@engradnanrasheedmechanical]

@Enock Dadzie your required solution is already if you want it , email me by referring this along with your name.

[@engradnanrasheedmechanical]

Have you checked your required solution? I did not hear anything from you. Waiting for your response

[@norbertomorilloogando9462]

thank you, you have a new subscriber 👌

[@engradnanrasheedmechanical]

You are welcome and enjoy the video with more to learn as well...Hope you will like it....

[@engradnanrasheedmechanical]

You are subscriber number 4460.....

[@classicconstractioncompany9000]

Thanks eng.

[@engradnanrasheedmechanical]

you are welcome 🙏

[@JacobAlexis]

This is soooo good

[@engradnanrasheedmechanical]

Thank you for your valuable feedback 👍

[@Nasazoon]

Thank you 💞😊

[@engradnanrasheedmechanical]

You are welcome 😊

[@shakirullah3525]

Nice sir

[@engradnanrasheedmechanical]

Thank you 😊 💓

[@sherazahmedkhan9048]

Example 1.1 sir wo be solve kr dn

[@engradnanrasheedmechanical]

Ok g noted with thanks

[@IqbalF-uy8gr]

how can 500kg be multiplied by 9.8N?

[@engradnanrasheedmechanical]

500 kg is mass and to convert this mass into weight which is force we have formula w= m x g where m is mass and g is acceleration due to gravity , m =500 kg and g=9.8 m/s^2 will convert mass into weight/Force. I think it will be clear

[@IqbalF-uy8gr]

@@engradnanrasheedmechanicalthank you sir

[@engradnanrasheedmechanical]

You are welcome 😊

[@MichaelRose-g4v]

I get 12250N for (Fcd)y

[@engradnanrasheedmechanical]

No problem it's correct and try to focus on solving method and practice it. You may get error in my calculations as we are human but ultimately goal is to get concept and learning. Thank you

[@kvngblue5807]

Hello sir

[@engradnanrasheedmechanical]

Hello how are you?

[@LeviAckerman-w6l]

In my text book,Ay value is positive. Is it right or wrong Cuz yours is negative

[@engradnanrasheedmechanical]

when ever you get negative value it means that your assumed direction is wrong it should be opposite to what you have suggested. In my video i have taken it downward which gave me negative value so it should be upward. in yours book it will be taken upward...

[@cosmosatrosanguineus3171]

The answers are wrong, try solving them in calculator

[@engradnanrasheedmechanical]

Try again using calculator. You can calculate and compare the answer given at the end of the book. Remember try to learn how to solve problems rather than sticking to the answers only. We are human and we can make mistakes. Thank you 😊 💓

[@engradnanrasheedmechanical]

Also this is example and you can compare it with the solution. The video is just recorded in order to explain the procedure available in the solved example for those who have difficulty in understanding 😀

[@classicconstractioncompany9000]

Eng I want your whatsap number to discuss some issues about this subject

[@engradnanrasheedmechanical]

sure here is my number [phone]