Moments of a Force | Horizontal beam in equilibrium on 2 supports

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[@josephrobinson9526]

I thought the ruler idea was very good, really helped me to understand which way the forces were turning which I struggled with before this video

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[@sweetnsourowaziyo2993]

Thank you very much Sir for the RULER IMAGINATION METHOD, for the first time i can say i understand moments of forces , you made it clear for me.. God bless you

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[@ExamSolutions_Maths]

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[@ExamSolutions_Maths]

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Awesome. Not even doing M1 but this is great for my physics exam.

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Thank you so much sir for the imaginative and informatively explanations..

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Wonderful explanation. Thankyou

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Great help

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I’ve always thought that lol 😂

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it is very helpful!!

[@science_dar3022]

Thank you so much 🙏

[@omarelnahas8668]

Thank you Sir!!

[@refiloeleanyatheko9281]

Thank you so much. This was helpful. Will you please show how you draw a bending moment diagram using this method...😊

[@Riplure]

plz upload more moments vids

[@Fun_Dealer]

Hello, great video! How can I calculate this for an item of known weight except I don’t know it’s in equilibrium and the reaction force ?

[@RiddhiKhan]

Thank you so much!

[@chooga4eva]

are reaction forces only at supports? are there reaction forces at the ends of the beam as well?

[@ExamSolutions_Maths]

Another word for 'reaction force' is called 'contact force'. So you only get these forces when objects are in contact with each other. So there will be no reaction forces at the ends of the beams.

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[@ExamSolutions_Maths]

You're welcome.

[@artistyomnasherif7145]

thankss a lot!!

[@majidsubhani1823]

Thanks sir

[@IsmailPbx]

At 12:22 shouldn't the answer be in Newton METRES?

[@ExamSolutions_Maths]

Not at all, it is a force, not a moment.

[@stefaniebabiolakis2724]

If there is no additional load and the beam’s supports are symmetrical about the centre of the beam, are the upward forces from each support equal?

[@Fartcat6992]

Yep

[@AnneBlanche-p9u]

Thanks for the video but I am confused with the possitive and negative sense

[@hallowvalor3477]

Why is m(c) equal to zero? If it’s at equilibrium wouldn’t that mean m(d) is equal and opposite to m(c)? Sorry I’m new to this stuff

[@zohaibafzal7785]

So is R = to the Weight acting downwards Because i jst got a question like tht but they r asking about the weight imstead of R

[@DanielBoakye-ic2cr]

How did u get the 28g?

[@tairenjansevanvuuren7067]

He skipped a step answer was -28g but if you move -28g to the 0 side -28 becomes positive 28

[@ax3199]

i know this is stupid to ask but is it possible to take moment from A/B?

[@mihirshah3332]

Nope. There is no fulcrum[pivot] to it wouldn't rotate.

[@lght6311]

what happens if one side has no weight would u include one end in ur question

[@ExamSolutions_Maths]

If no weight were hanging from one end of the rod then I would still draw the rod but leave out the hanging weight as there is not one present. I hope I have answered what you asked?

[@amirjafar3615]

Fucking right dodgy,it is a good video!