Coordinate Geometry : Equation of a perpendicular bisector : ExamSolutions

A tutorial on coordinate geometry and the equation of a perpendicular bisector.
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[@matttower3872]

you ARE the definition of a miracle sir, thank you!!!!!!

[@dylankriel83]

Thank you so much! I have a test tomorrow and this REALLY helped

[@ExamSolutions_Maths]

Good luck.

[@benfennell1430]

How did your test go?

[@dylankriel83]

@@benfennell1430 It went really well, one thing youtube lessons taught me is that teachers can usually do their lessons in about half an hour and its pnly becauseof tests that we have so much time in class

[@benfennell1430]

@@dylankriel83 thats great to hear!

[@zoerichard88]

I know it may not mean much.But this really helps the way you explain things make them so simple and understanding. Thank you so much! Appreciate it alot!!

[@ExamSolutions_Maths]

+Zoe Richard It means a lot. Thank you.

[@aizedhaider2979]

loved it sir great way of teaching thank you soooooooooooooooooooooooooooooo much!!!!!!!!!!!

[@ExamSolutions_Maths]

Appreciated. Best wishes

[@donjibz]

Absolute legend, this is so helpful thank you!

[@vikiwikinana]

thank you for explaining it so simply. My maths teacher confused the hell out of me and didn't explain it step by step. (I'm doing A level maths)

[@henryhuynha4818]

How are you doing now? it's been 5 years

[@jaytripathi5611]

@@henryhuynha4818 and how are you doing now, it's been two years

[@jay.tripathiofficial]

@phymax finally I got to reply, I gave my A levels in March and now awaiting the results

[@ExamSolutions_Maths]

FP1 yes, FP2 hopefully next two terms

[@ExamSolutions_Maths]

@anti1china yes

[@gfgrfgdfgfdgfd4192]

what grade would this be on the 9-1 scale? Thanks

[@andydaniels6363]

Seems like a bit more work than necessary, especially since you end up undoing some of that work to get the required equation form. Using the point-normal form of equation of a line instead gets you to the solution more directly: subtracting the coordinates of B from A gets you the necessary normal, hence the coefficients of x and y, and after computing their midpoint you just need to subtract its dot product with that normal.

[@Nahiyan12]

Seriously, you are the teacher of my teachers!

[@cybacyclonex2]

Do you also do Further Maths Vids? It would be sooo helpful!!! Thanks!

[@abbypollock2028]

can you tell me how to work out co-oridantes when given an equation?

[@elliottjohnson8113]

thank god for you!!!!!!!!!!!!

[@pokerockman]

Sir, what separates y and y1? I popped the numbers in y instead of y1 and x instead of x1 and i got a similar answer with all the numbers correct but my symbols flipped. I got 10x-12y+29 = 0 instead.

[@ExamSolutions_Maths]

+pokerockman That's the problem, you put them in the wrong places.

[@vedantpophali2343]

Thanks a lot sir 😊😊

[@RitaKaminski]

thankyou :)

[@RShahProductions]

You sir are a Sensei!!!!!!!!!!!!!!!!!!!

[@oliviathe0wl]

This was uploaded on my birthday :D

[@jaytripathi5611]

I have got a test tomorrow, your videos are playing a critical role sire

[@moesha01felix81]

Why did you do the reciprocal of the gradient... Is it because it is an improper fraction??

[@shahmirrasool]

when you're trying to find the equation of a perpendicular of a line then its gradient is the reciprocal of the first line

[@Strawberryturtle96]

You explain it much better than my teacher :D

[@zaibkhan6237]

sir but wont the examiners subtract marks for using that equation instead of y=mx+c ???

[@ExamSolutions_Maths]

+Gamer Sward Not at all.

[@aqtzing3888]

Please can you upload another video on this please??

[@marziasahebzada4096]

Hi, I don't know what I'm doing wrong, but the gradient I got was -6 / -5 so I don't know where I am going wrong. Has someone got an answer to this? Thanks!

[@luckykarkade1908]

Seeing after 10 years

[@Nahiyan12]

True :)