Existence of Eulerian Paths and Circuits | Graph Theory

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WilliamFiset

WilliamFiset

Күн бұрын

Пікірлер: 47
@adnanemezrag3809
@adnanemezrag3809 9 ай бұрын
bro i love you man. all the questions that was poping in my mind you have answered them. I have searched so long for them but I couldn't find them except here. Thanks again!
@weixinmeng6791
@weixinmeng6791 3 жыл бұрын
I love your way to explain Eulerian Path and Circuits that you gave a lot of good examples.
@sarfarazalam6077
@sarfarazalam6077 5 жыл бұрын
Best explaination, great video and consice animation . Indeed Graph is your favourite topic!!! Thank you for the video :)
@mathuratudu7271
@mathuratudu7271 6 жыл бұрын
Your videos are awesome..Please make videos on Maximum flow in graph.
@BobCao
@BobCao 5 жыл бұрын
Awesome explanation and the table is great!
@alexgenuario8563
@alexgenuario8563 4 жыл бұрын
Super helpful video. Thanks!
@johnsimon8158
@johnsimon8158 Ай бұрын
thanks for this awesome video
@CK-iq1jc
@CK-iq1jc 3 жыл бұрын
From the table, it says that we need to have - one vertex where degree out - degree in = 1 AND - one vertex where degree in - degree out = 1 AND - all other vertices must have equal degree in and degree out. But the example from 8:08 says that it has Eulerian path because all in/out degrees are equal. From the table, I thought you were saying that we need to satisfy ALL of the conditions, not just one of them. Could you please clarify Eulerian Path for directed graph requirement(s)?
@sameerchoudhary8590
@sameerchoudhary8590 3 жыл бұрын
If a graph has Eulerian circuit then it also has Eulerian path. In the table, it says at most not exactly.
@CK-iq1jc
@CK-iq1jc 3 жыл бұрын
@@sameerchoudhary8590 I guess that statement is also true for directed, not just undirected graph? I know that statement came out on 7:06 for undirected graph but wasn't clear if that was true also for directed graph. And I missed out on the "at most". Thanks for pointing that out.
@Suuuuuuuuuuuuuubrat
@Suuuuuuuuuuuuuubrat 2 жыл бұрын
Awesome 💙
@ashaoluayanfe7474
@ashaoluayanfe7474 2 жыл бұрын
I love your explanation, bravo!
@prakhar992
@prakhar992 4 жыл бұрын
Really nice explaination
@sadiashahzadi6841
@sadiashahzadi6841 7 күн бұрын
I'm belonging to Pakistan I really appreciate you Because after watching your video My all problems have been solved
@g1patil
@g1patil 3 жыл бұрын
2:45 is confusing if you take example a->b graph. A graph with one edge. There is no cycle , but there exist path which visits all the edges at least once.
@niroo2781
@niroo2781 2 жыл бұрын
Awesome examples!
@BrayanDiazssJD
@BrayanDiazssJD Жыл бұрын
Good video, thank you.
@ankushgupta630
@ankushgupta630 4 жыл бұрын
MAKE MORE VIDEOS CAUSE THEY ARE AWESOME
@varshasharma8842
@varshasharma8842 4 жыл бұрын
Plz reply to this ques that for a directed graph,we can find euler circuit or path in case of disconnected graph but not in undirected graph,why?
@alexandrreznik3209
@alexandrreznik3209 4 жыл бұрын
Great explanation!!!
@claymeistereu
@claymeistereu Жыл бұрын
3:12 Can an Eulerian Path in an Undirected graph have just even degrees? Take the simple triangle graph. All the vertices have 2 edges. But using them all makes a cycle. You can't make a path without one of the edges being unused.
@ashgbadamassi6089
@ashgbadamassi6089 4 жыл бұрын
Thanks for this video. I'm having trouble finding the slides for this video on GitHub. Can you please share a link?
@WilliamFiset-videos
@WilliamFiset-videos 4 жыл бұрын
They're under the slides/graphtheory folder from the root dir
@ashgbadamassi6089
@ashgbadamassi6089 4 жыл бұрын
@@WilliamFiset-videos Found them! GitHub was truncating the PDF for display. Thank you!
@looksofun
@looksofun Жыл бұрын
Awesome video !!!
@keerthivasan138
@keerthivasan138 2 жыл бұрын
6.39 Is there are 4 verticies having 3 degree how it has eulerian path
@idealspeaker1377
@idealspeaker1377 Жыл бұрын
actually two of them have 4 degrees. i also saw that by mistake at first....
@lorenzomilandri453
@lorenzomilandri453 Жыл бұрын
@@idealspeaker1377 so ahahahha? it still not an eulerian path
@mohammadezatolahi2418
@mohammadezatolahi2418 6 жыл бұрын
amazing ...
@varshasharma8842
@varshasharma8842 4 жыл бұрын
For a undirected graph,is it essential for the graph to be connected? Also,for directed graph,is it essential to be connected?
@halilibrahimustun50
@halilibrahimustun50 2 жыл бұрын
7:41
@ankitraj4957
@ankitraj4957 6 жыл бұрын
This is awesome. I have a question apart from this topic. What are some important problems and topics that cover the Computational Geometry part? can you please provide the topics and resources?
@WilliamFiset-videos
@WilliamFiset-videos 6 жыл бұрын
Computational geometry is a fun topic. Important things to cover there IMO would include basic shape intersections, convex hulls, ray tracing, line sweeping techniques, and perhaps geometric data structures like quadtrees and K-D trees.
@ankitraj4957
@ankitraj4957 6 жыл бұрын
Where to study about the intersection or common area of intersection of N shapes arranged in random way in 2D planes? Ex : Common area of intersection of N overllapping rectangles.
@WilliamFiset-videos
@WilliamFiset-videos 6 жыл бұрын
I learned from programming problems and blogs, sorry I don't have any videos on the subject matter.
@ankitraj4957
@ankitraj4957 6 жыл бұрын
okay
@dontony7071
@dontony7071 4 жыл бұрын
Best🙂
@prajwalchoudhary4824
@prajwalchoudhary4824 Жыл бұрын
a self-edge counts for 1 indegree and 1 out-degree
@jessieli8499
@jessieli8499 2 жыл бұрын
I love you
@vansh2853
@vansh2853 Жыл бұрын
nice music bro
@viaMac
@viaMac 4 жыл бұрын
You should have made it more clear whether the conditions are necessary or sufficient.
@fishball1634
@fishball1634 3 жыл бұрын
i think an eulerian path and elerian trial are 2 different things. a trail can have repeated verices and a path can't
@nevokrien95
@nevokrien95 5 жыл бұрын
Spoted some mistakes (i think) In 857 there is no path Non directed graphs are a spciel case of directed graph which feets ur requirment for eulrian path but they dont all have a path soooo explain
@shoebmoin10
@shoebmoin10 5 жыл бұрын
It doesn't matter if we don't visit all the vertices, we should just visit all edges once.
@nevokrien95
@nevokrien95 5 жыл бұрын
@@shoebmoin10 ok gotya
@lorenzomilandri453
@lorenzomilandri453 Жыл бұрын
6:37 this isnt an eulerian path ahahah
@drmichaelsunsschoolformath
@drmichaelsunsschoolformath 4 жыл бұрын
Seems to be talking about non-existence
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