True! The Navier Stokes equations which govern all fluids - in the case of a really small Reynolds numbers (i.e a very viscous fluid such as, I believe, the corn syrup used here) get reduced to just being dependent of the pressure and viscosity terms because the acceleration term gets vanishingly small (again because we multiply with a very small Reynolds number). Since that’s the only term bringing time into the equation however, we should expect to see the exact same result when we perform the exact same action in reverse, regardless of time, because time, in the case of a small Reynolds number, doesn’t matter.