First Order Transient Circuit Analysis

[@Rodlfisher]

Really wanted to thank you Matt. I finally understood this circuits and I feel much more prepared for a final test in three days. Awesome video. Hope you do even more because you are really good at it. Hope my teacher won't force us to do it via LaPlace transform x( more analysis less algebra with this method.

[@AlanMedina314]

We are using the same book in my class. Thanks Matt your videos are helping me.

[@AraujoMatt]

The passive sign convention can be the trickiest part. In the video, I assign a parameter vc(t) with an arbitrary polarity. For a simple circuit like this, I can guess that I have the polarity correct, because the battery deposits a positive charge on the top of the cap....even if i didn't know it wouldn't matter...because my parameter is at my discretion. When I apply KVL to the left loop I get : -12V +6k(1m) +Vc[t] = 0. Hence vc(t) = 6V

[@mohiuddinsiddiqui6346]

I need Mathew email address

[@AraujoMatt]

This is one of a series of videos I created documenting a year-long course in circuits

[@PaulNakroshis]

Nice discussion Matt!

[@AraujoMatt]

Thanks Paul! I made 24 other videos on circuits last year to cover everything from KVL, KCL, three-phase, 2nd order systems and steady-state analysis. I'm on the Portland campus this semester for statistics. I'll drop by your office sometime.

[@abrahamebyfugui326]

Next time u have to solve and show every single calculations. Thanks for the video.

[@cornevanzyl5880]

the switch opens at time = 0... the way the circuit was drawn, I thought that the switch closed at t=0 and had the most conflicting 15 min of life.

[@ALGH2101]

Corne van Zyl He explains what it does at 5:16. I wasn’t sure either at first. This happens a lot in KZbin examples. So when Im not certain about something at first I try to pay attention to every detail afterwards, especially when it relates to what I wasn’t sure about to see if it is explained later in the video. Fortunately, in this video, he does clarify at 5:16 what the switch is doing. But I agree, this seems like an untraditional and confusing way of writing the initial switch condition. But I guess this is how he was taught.

[@aca2156]

THANK YOU KEEP UP THE GOOD WORK

[@isaacaguirre1881]

Thanks, man, I really appreciate what you do

[@AdvancedGT]

Set speed to 1.5, you're welcome. Good video tho

[@casp3r_de_gh0st90]

What if the switch is being closed instead of opened at t=0? how does this change the way you solve the problem?

[@srdonline5490]

When Vs is shorted, there is still a 6k resistor to the left. should Rth be 6k || (2k +4k) and is 3k?

[@RajeshKumar-pn3lk]

Srdonline SrD Yes but we consider the case where switch isn’t closed so far!

[@itzshoulderific]

thanks for the video! im just confused as to why the thevenin resistance was 6k

[@radtrav1]

when t>0 the left side of the circuit is shorted. you then only have 2k in series with 4k

[@srdonline5490]

at t>0, there is still a 6k resistor on the left. i might be wrong, but i think Rth should be 6k || (2k+4k), and is 3k.

[@bajojohn]

Old post, I know. You open voltage sources and short current sources for thevinin. Since it's open, it's not connected.

[@dm6031]

T>0 the time switch is opened. Meaning no current goes through the left branch, which means that there's no voltage across the 6k resistor on the left. Therefore the only resistance seen by the capacitor would be the 4k + 2k in series, = 6k.

[@GeekBagels]

Nice explanation of everything..thanks a lot!

[@LamiereByM]

Thank you so much. you made it so easy. 😊

[@yousufadnan3952]

i wanna know that in a transient state why we neglect a source ????

[@Thesportynerd16]

Your arrow is confusing, it took me a second to put two and two together that that at t = infinity the circuit was open. Maybe have the arrow drawn the other way to signify that it opens at t = 0? Thanks for the video

[@masudkaysarovi7330]

What steps I should follow if i want to use differential equation technique? Thank you

[@Iplayforhim16]

Love this!! Thanks

[@Festus2022]

What is X supposed to be in this video?

[@manukris]

how, the time constant is 6*4....it should be 3*4...no?

[@lukebonnici5627]

+Manu Krishnan I have the same question. The only way I can see it is that there is no current flowing through the circuit as the switch is open, so the 6 comes from the 2 + 4. The other 6 is part of an open circuit branch so that 6ohm resistor isn't included.

[@Thesportynerd16]

This is correct, the 2 + 4 because when the switch is open the 6-ohm resistance doesn't see any current. I know this is year late but yeah, hope it helps

[@srdonline5490]

How did you get the Rth = 6k? thanks

[@xAng3lxHD]

is this the step by step method?

[@escarlai]

NICE!!! this video make me easy to understand !!!Thank you!!! , i hope you have more example for this ：)

[@OpolotNaphtal]

thanks

[@kriksizanderson5471]

Helpful video

[@anajo240]

if would be so much helpful if you could show all the calculations

[@natureispriority5520]

Thank you

[@NitishChauhan1]

you are awesome

[@ashleecohen8397]

how come its not -6v? using the passive sign convention

[@ZeroOptions]

Very unclear on how to find Vc

[@ZeroOptions]

Holy fuck, please don't do this again if u gonna stutter the whole vid

[@jinshikami7525]

Hey could you try this software? Any feedback is appreciated! Search: 'Circuit Solver' on Google Play.

[@tceterex]

Text book is Irwin

[@bing765]

My professors is one of the authors of this book. Bro literally wrote the book and doesn't teach us how to do ts💀

[@TheMehedi007]

(y)

[@Chr0nalis]

Please... Capacitors store charge inside an electric field. The don't store a 'voltage' . A voltage is only a potential difference between two points inside the electric field. Inductors store energy in the magnetic field. Current is an instantaneous quantity , not an accumulative one. Current arises from a potential difference between two points in an electric field. You can't "store"' current.

[@AraujoMatt]

Like I said, it's one way of thinking about it. Capacitors and inductors are both energy storage devices. With the inductor, the energy is stored in a magnetic field. How is this energy released? The magnetic field induces a current when it is released. Likewise the capacitor stores energy in an electric field...

[@supremedogexx420xx3]

+Shagas Heizenberg Damn. You just got wrecked.

[@ajiri_e]

+Matthew Araujo pls how did you add the capacitance and get 4 uF

[@mrdistraction]

+Ajiri Ekwerigbe capacitors in parallel have their capacitances added. So the 2 that are in parallel will be 12 microfarads. The inverse of equilavlent capacitance of capacitors in series is 1/ceq = 1/c1 + 1/c2. This is 1/4 so the ceq is 4. There is also a shortcut that can be mathematically done as (6*12)/(6+12) = 4 microfarads

[@Luke_Skywalker1836]

Huh