Your Pen or whatever it is... It is simply amazing...
@jamesbrosnahan34229 жыл бұрын
Patrick- Excellent video . I suggest googling 'wheatstone bridge' + 'strain guage' and also using a microcontroller with two A2D input pins that can be set to DIFFERENTIAL mode. Your results should improve. Good luck. I enjoy your videos. I'm subscribed. - Jim
@BrandonBaunach3 жыл бұрын
Does the sensing quality degrade over time as you bend it over and over for years?
@PatrickHoodDaniel3 жыл бұрын
I have not tested this item. The manufacturer should have that information in the datasheet for the product.
@haljohnson69473 жыл бұрын
you forgot to tell me to subscribe and smash the like button
@huntermalone68994 жыл бұрын
Will adding a potentiometer require a resistor in the circuit still?
@shaider19829 жыл бұрын
hi there. i tried to use this to control a servomotor. i can command the motor as if i am using a potentiometer but if i am not flexing the sensor, the motor trembles. i wonder if it really does this or did i break the sensor. could i filter out the.tremors? thanks
@Synergy7Studios7 жыл бұрын
shaider1982 no, you didn't break it. That's just normal noise. You'd get that from any sensor like a flex sensor. You will need to smooth it out in software (maybe take 5 readings and average them). A capacitor in parallel might also smooth it out..
@danaishrathore26594 жыл бұрын
Hi, can you share the link of Flex sensor, I want to buy it.
@PatrickHoodDaniel4 жыл бұрын
Here you go: www.newbiehack.com/categories/newbiehack-sensors-flex-sensor-spectra-symbol#prettyPhoto
@danaishrathore26594 жыл бұрын
@@PatrickHoodDaniel Thanks
@jermainepop8 жыл бұрын
what type of pen pencil is that?
@ZA-fo2rn4 жыл бұрын
I am distracted by the pen or just the way u write
@eddivanhallen8 жыл бұрын
Where is possible to buy a flex sensor?
@gouthamnaroju8935 жыл бұрын
Amazon eddivanhallen
@GouthamKolluru9 жыл бұрын
Vout = Vin (R2 / R1+R2 ) right ?
@PatrickHoodDaniel9 жыл бұрын
Vout = Vin * ( R1 / (R1+R2) ) I add the parenthesis to show order of operation.
@GouthamKolluru9 жыл бұрын
Patrick Hood-Daniel No, I mean at @2:57 Vout is equal to the voltage drop on R2 ,If you are measuring the drop across flex sensor directly then Vout should be Vin - Vin * ( R1 / (R1+R2) ) because the reference was GND, As far as I understand, the supply voltage is divided into voltage across flex sensor and resistor R2 and by measuring voltage across R2 we determine the range of voltages that flex sensor outputs for various bending positions. To transform the voltage to our desired range we use potentiometers, op amps etc etc.Is my understanding correct ?
@H2CO3Szifon9 жыл бұрын
Goutham Kolluru yeah, that's it. The formula in the video is wrong as-is.
@PatrickHoodDaniel9 жыл бұрын
Árpád Goretity You are all correct. I will correct the video. I used the formula from the datasheet for this flex sensor. Silly me.
@H2CO3Szifon9 жыл бұрын
No problem, thanks for the video anyway!
@sabahoudini4 жыл бұрын
God damn youtube commercials are getting out of hand. There is to many.