How does a Half Bridge converter work? | Half Bridge Converter Working

[@thomc2526]

I have to give a special class to my classmates and this videos saved my life, thank you so much for taking the time to explain step by step and for the animations they help a lot to understand :D

[@FoolishEngineer]

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[@sdgb5363]

Very easy to understand and follow. Nicely done. Thank you :)

[@FoolishEngineer]

Thank you so much for watching!! Please don't forget to subscribe to our channel

[@柏恩-s5c]

Very creative presentation. Makes the topic easy to understand.

[@FoolishEngineer]

Thank you so much for watching, glad you liked it!!

[@mateusztrzmiel8979]

6:58 there is a minor mistake. Currents of diodes will look slightly different. Due to inductance of a transformer they cannot change immediately. So if initially ID1 was 100A and ID2 was 0A, they will respectively decrease and increase until they eventually reach L1 current.

[@Dc_tech386]

Thank but I have burning questions if I series two 555 timer can I use the two output signal for h bridge inverting for high and low with the two 555 timer I see a circuit of that in a h bridge motor drive but not on inverter so I want to know if the same design can use a transformer for inverting

[@micheljustnziwa1382]

hello sir i already have a background on rhe half bridge feedback thanks to you but it is not enough for me so far i work with the ir2153 and i would like to have all the details regardingthe stabilization of my two outputs how am i going to connect the feedback ?

[@FoolishEngineer]

Why don't you use ASICs directly..?

[@kubajz2257]

5:30 No, the problem is that the MOSFETs would short out the power supply.

[@krzsn5382]

thanks for sharing your knowledge, is awesome!

[@FoolishEngineer]

Glad you liked it!

[@jayshah4413]

Will freewheeling happen at primary side? How primary side current is increasing and decreasing drastically from zero?

[@David_Benny]

Can i know how to calculate the value of inductor and capacitor in the output, so i can design this converter

[@FoolishEngineer]

You can check some application notes of the Half bridge converter

[@ahoorapersia4698]

Hi 👋. Thank you for this explain. I have a question: In a smps device that I want to repair, there are 2 SRD (3pda 60), step recovery diode, and there is not pulse transformer. Please explain how that diodes work. 🙏🏻

[@spypower7295]

Hello i am trying to do simulation on this in plecs but i cant get it to work

[@panditamol12]

I have issues with my circuit ..would u help me I hv designed half bridge topology based smps .. i already implemented dead time in two gate input Bt when I check the input of primary of transformer then dead time does not present And if I reduced the duty cycle of gate .still transformer primary still gives 50% squre out with no dead time ..will u help me ..thank u very much

[@anderssejer7289]

Great video, keep up the good work sir 💪

[@FoolishEngineer]

Thank you so much for watching!! Please don't forget to subscribe to our channel

[@devbhavsar8025]

the output input voltage relation needs some editing, it should be 0.5Vi instead of 2Vi. Well done for your hardwork.

[@danalex2991]

Why is Vo = 2 x Vin x D x turn ratio ? I can understand Vin x D x turn ratio . But I don't understand how that 2 came . I thought when you are connecting from center tap to one end you will get only half the total secondary voltage . So shouldn't it be 1/2 x Vin x D x turn ratio. ?

[@FoolishEngineer]

Here both Secondary turns of a Transformer contribute for the output voltage. For better understanding you can refer to book 'Power Supply Cookbook by Marty Brown' - Page 58

[@danalex2991]

@@FoolishEngineer ok ok so Ns means only one half of the the total secondary turns

[@freedomisfood6966]

excuse me may be i am in trouble.but in animation current crossing from capacitor in wich the dc current dont cross from capacitor.first mosfet charge second mosfet and current is open because capacitor is charged .when mosfet nuber2 is closed the capacitor 2 discharge .and continued.but why the mosfets must be open in one time .one is closed other is opend.and revers.!!!!!!!

[@SefaOralz]

Thank you very much sir, I appreciate !

[@FoolishEngineer]

Thank you so much for watching!! Please don't forget to subscribe to our channel

[@garinanggara8358]

Sir, what if there is no current path at secondary? I mean open circuit. Does the MOSFET will heat up bcs of saturation?

[@FoolishEngineer]

Yes it will! MOSFET will damage.

[@electronicsjockey]

What can be minimum load then

[@ruchikumari6996]

Hey you have taken input voltage as Dc right?. so how does it support induction in transformer.since we have been studying since btech, transformer works in ac only?

[@FoolishEngineer]

Well, technically you are giving AC to transformer, AC doesn't only mean Sine wve.

[@ruchikumari6996]

@@FoolishEngineer thats what i want to know. how?

[@alimohsin9209]

@@ruchikumari6996 We know in AC wave current changes its direction after every half cycle right. Similarly in this circuit, we have arranged the MOSFETs in such a way that direction of current is getting revered so technically it is working as an AC. Hope it clears your confusion

[@rudywang3936]

Hat off! Respect...

[@FoolishEngineer]

Thank you so much! Please show support to my video with Super thanks.

[@frankcole3196]

As Subhojit Das says, with both Q1 and Q2 'on' ... even briefly, the Vin DC supply is short circuited (through the Mosfets) and a very high current, often exceeding the Mosfet specifications, can flow. This is called 'shoot-through' and has to be avoided. Dead-time in the turn-on and turn-off is introduced to prevent this situation.

[@muhammadnasar4484]

Would you explain how the feedback works?

[@FoolishEngineer]

yes. I'll try!

[@mehdibenzineb5544]

There is a big mistake about the direction of current when each mosfets turns on; firstfull the c2 and c1 are initially fully charged, then when Q1 turns on the current start flowing from +c2 to the negative side c2 in this case the Primary side of transformer supplied by Vin/2 and the current get positive; On the other hand, when Q2 turn on and Q1 off the current flow from +c1 to the negative side of c1 (GND) then the current gets negative and finally the voltage will -vin/2

[@DIYPhil]

Correct! That is exactly what I was taught in school. I immediately looked at the comments to see if somebody else noticed that.

[@luizvision478]

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[@FoolishEngineer]

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[@zbyszekskibinski]

These types of converters are never to be seen in consumer electronics. Rather than that, half bridge inverters are used with one supply source and small driver transformer. There are a couple of small 15-30nF capacitors added in the circuit between the end of primary winding and the ground. The charge is built in them when top mosfet is off and the energy is taken off them when the bottom mosfet closes and current flows in another direction across the primary. There is definitely no second supply source and neither is there the center tap in the primary so its not a push-pull circuit!

[@paramanandprajapati3867]

why are we using Schottky diode, why not simple diode?

[@FoolishEngineer]

Good question, Please watch this video for this. kzbin.info/www/bejne/mnjZfZp3mLyLbsk

[@paramanandprajapati3867]

@@FoolishEngineer Thank you, sir! it really helped.

[@GenadiJai]

Thank you very much for your videos, it's very helpful, but in this particular one I think you have a mistake. As I know, the Volt Second Balance of full bridge converter is given by: Vout=D*Vin*(Ns/Np) and not Vout=2*D*Vin*(Ns/Np)

[@FoolishEngineer]

Okay, I'll check! Thank you so much for watching!! Please subscribe to our channel

[@totemoraku]

@@FoolishEngineer Probably because Ns is 1/2 of the total secondary turns

[@AbdulRehman-vi9ln]

Amazing👍

[@FoolishEngineer]

Thank you! Cheers!

[@johnaweiss]

Plz explain advantage/disadvantage compared to Full Bridge converter.

[@FoolishEngineer]

Sure

[@amrhallak4867]

Great

[@FoolishEngineer]

Thank you so much! Please show support to my video with Super thanks.

[@subhojitdas108]

so far I know the dead time applied in PWM is due to sc of source ..not the tx saturation. you need to check that point

[@FoolishEngineer]

Okay, i'll check. Thank you so much, Glad you liked it!!

[@sowndaryasonu997]

The input voltage is DC.How the transformer works in DC supply

[@abdurrahmanenic625]

V0 should be equal to Vin*D*Ns/Np instead of 2*Vin*D*Ns/Np