Forced Harmonic Motion

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MIT OpenCourseWare

MIT OpenCourseWare

Күн бұрын

Пікірлер: 14
@marktoffoli9186
@marktoffoli9186 2 жыл бұрын
Thank you professor Strang, you really have made learning engaging and insightful, I thoroughly enjoy watching your videos
8 жыл бұрын
Thank you MIT for sharing the knowledge to the world!
@goytomt
@goytomt 7 жыл бұрын
Love that "Hee'e" sound @6:51. Thank you sir!
@lexrogan2207
@lexrogan2207 4 жыл бұрын
Thank you Professor Strang!
@irslanullahashraf5158
@irslanullahashraf5158 2 жыл бұрын
thank you, professor ... you always add beauty into mathematics and make it super interesting
@knowledgewith90shoomans97
@knowledgewith90shoomans97 9 ай бұрын
conside an at rest linear system described by : y"+25y=2 sint+5cos5t the response of the system will be : decaying oscillation in time, oscillatory in nature, growing oscialltion inb time, none
@studio.maximoff
@studio.maximoff 6 жыл бұрын
why impulse response is 1/mWn not just 1/m?
@leonardosoto5669
@leonardosoto5669 6 жыл бұрын
watch the previus lecture,in the null solution the coefficient of sin(wnt) is (dy/dt)(0)/wn ,in this case (dy/dt)(0) is 1/m but you stil have to divide it by wn
@freeeagle6074
@freeeagle6074 2 жыл бұрын
Since d(sin(wnt)) brings wn out, we need wn to exist at the denominator to cancel wn so the dy/dt is 1/m.
@atomskyjahid1533
@atomskyjahid1533 8 жыл бұрын
Physical interpretations are what I'm here for. ^_^
@bigdave6952
@bigdave6952 Жыл бұрын
i dont understand why did he end up calling a null solution a impulse response at the very end, it my must have been a slip up him. It cant possibly be true.
@eclipseslayer98
@eclipseslayer98 2 ай бұрын
Differential Equation seem like they should be "fairly" easy to learn, but for some reason, I can barely find my way around.
@Hobbit183
@Hobbit183 7 жыл бұрын
dam thats interesting
@T4l0nITA
@T4l0nITA 5 жыл бұрын
So c1 and c2 of yn are the same of the oscillating function of the previous video, or do I need to solve for y(0) and y'(0) the whole yc solution instead of yn ?
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