France | A Nice Math Olympiad Problem

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[@norbertduchting6217]

Factorize the sums of cubics in numerator and denominator. Then you get the solution almost immediately.

[@norbertduchting6217]

Factorize the cubics in numerator and denominaor and you get the solution almost immediately (without substitutions)

[@donsena2013]

Beautifully systematic evaluation technique

[@rcnayak_58]

Here is another alternative way to solve it, maybe little easier. Let a = (29³ + 15³)/(29³ + 14³). Add -1 (minus 1) to both sides. So that (a - 1) = [(29³ + 15³)/(29³ + 14³)] - 1 = [(29³ + 15³) - (29³ + 14³)]/ (29³ + 14³) = (15³ - 14³)/(29³ + 14³) = [(15-14)(15² + (15)(14) + 14²)] / [(29+14)(29² - 29.14 + 14²)] = (15² + (15)(14) + 14²) / (43 (29² - 29.14 + 14²)) = (225 +210 +196)/(43. (841 - 406 +196)) = 631/(44.631) = 1/43. Therefore a = 1 + (1/43) = 44/43

[@Mb-logic]

Thanks for sharing ❤

[@euthman]

Very nice. Thank you!

[@darioc1967]

Good

[@vladimirverkhoglazenko8960]

Я гораздо быстрее умножил всё в столбик))

[@Mal1234567]

Can you explain it again using interpretive dance?

[@hasoturgo2418]

It is for me an appraciated fresh-up. Much better than Sudoko. Can you please problems with derivate and integral solve. Some lim. problema too. Thank you.

[@is7728]

Nice I want them too

[@omerkayhan464]

Would you do the easy way

[@mohamedsalah5525]

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